... You would need 135,000 of those to store 500MJ. That's $26 million. For the same money you could by 50,000 500W solar panels. That's 25 MW on any sunny day! You could run not only your own business, but everyone else's for miles around.
This used capacitor is in “fair condition” and costs $195 and weight 225pounds, not counting shipping weight or cost. It is 0.74uF, rated for 100KV. Thus it can store 3,700J = 0.5 QV = 0.5 CV^2.
Note Two things:
(1) The fine grounding wire between the central high voltage post and bolt. It is about three or more inches long.
(2) More importantly, note the white ring that makes the arc path that could be same as grounding wire at least 3 inches long. I.e. for safe operation at 100KV you need about a 3 inch gap between ALL POINTS at the high voltage and ground.
As MacGyerer points out BennyF will need 135,000 in series to store 500MJ at 135 million volts – far less than voltage than BennyF’s “100s of billions of volts”
But let’s assume BennyF starts out more modestly storing only 500MJ at 135E6V in a vertical stack of 135,000 of these capacitors and calculate the air gap space, G, between the top 135E6V terminal and ground. It will be approximately three inches times 135,000 or 33,750 feet or more than 6.35 MILES high!
Benny F is totally ignorant of the breakdown problems, even at only 135 million volts. If he really wanted to work with 135 BILLION volts stored, he would need by simple analysis to keep the high voltage terminal more than 6,350 miles above the ground. More realistic analysis would note that the atmospheric pressure decreases with altitude and passes thru the Pashion pressure minimum so the condenser at that altitude would need to have a much taller white ring (several feet) to prevent it from arcing over.
As noted in earlier post, just to store a billion volts will require the high voltage terminal be outside the atmosphere, well above the orbital altitude of many earth orbiting satellites.