Answer the question.

billvon said:
So you don't know what happens after that. No big deal; some people don't understand basic thermo.
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It's only 11PM, who cares?? Not me. I only wanted to know how much energy a 100 Watt light bulb consumed for 10 hours.

Why would I want to talk about your next measure of energy (power*time)???
 
I simply asked how much energy is in the gas, and how much is it spread out? :confused:

How many kw-hrs are in a gallon of gas, and how is it distributed?
 
Motor Daddy said:
Because people are saying a gallon of gas has energy while it's in the can, albeit spread out and not available.
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So you asked about it because someone said something you disagreed with, but you aren't asking about it because you don't care.

Your train of thought is as clear as your grasp of physics.
 
billvon said:
So you asked about it because someone said something you disagreed with, but you aren't asking about it because you don't care.

Your train of thought is as clear as your grasp of physics.
Click to expand...

Maybe if you would have followed along and understood what was happening in this thread you would understand it a little better? You don't seem to know what's up.

People made statements and I am asking them to quantify their statements. No such luck, they don't care to do that. They just want to talk about little green monsters that you can't measure or see.
 
Motor Daddy said:
People made statements and I am asking them to quantify their statements.
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You'll have to take that up with this guy MotorDaddy. He keeps saying he doesn't care about those statements.

(From this point on I will refer to the "I'm just asking questions here" Motordaddy as MDQ and the "I don't care; I'm not asking anything" Motordaddy as MDT.)
 
Motor Daddy said:
So it's not available at all now? It's not just degraded and less available like you claimed before, now it's not available at all!

So a gallon of gas has energy that's not available at all. It's all in the gas, although you can't measure it or see it, but it's all there! Just not available.

Got it!

You think the reason it's not available at all is that it's spread out too much?
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Well, if you read my reply carefully you'll see I qualify "not available" with the caveat that that depends on whether you have a lower temperature heat sink available. (I have to cover the options because I know what a nitpicking and deliberately obtuse git you can be.)

The energy in an unburnt gallon of gas is not in the form of heat, so it is, of course, available. Once the gasoline has been burnt and is thereby turned to high temperature heat, some of it is available to do work pushing the pistons of your car, but this lowers its temperature, at which point the heat then comes out (of the exhaust and via the radiator), into the atmosphere as low temperature waste heat. At this point it is unavailable.

Got it?
 
Motor Daddy said:
So billvon, how many kw-hr is in a gallon of gas, and how are those kw-hr distributed in the gas?
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MDQ, a gallon of gas at room temperature contains ~.5 kilowatt-hours of thermal energy. In a well mixed liquid it is distributed throughout the gallon.
 
exchemist said:
Well, if you read my reply carefully you'll see I qualify "not available" with the caveat that that depends on whether you have a lower temperature heat sink available. (I have to cover the options because I know what a nitpicking and deliberately obtuse git you can be.)

The energy in an unburnt gallon of gas is not in the form of heat, so it is, of course, available. Once the gasoline has been burnt and is thereby turned to high temperature heat, some of it is available to do work pushing the pistons of your car, but this lowers its temperature, at which point the heat then comes out (of the exhaust and via the radiator), into the atmosphere as low temperature waste heat. At this point it is unavailable.

Got it?
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Read my lips: Energy=Power*Time
 
billvon said:
A gallon of gas at room temperature contains ~.5 kilowatt-hours of thermal energy. In a well mixed liquid it is distributed throughout the gallon.
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So the gas gets hotter, and the can heats up and melts, right? How did you measure the .5 kw-hr of thermal energy? How much time elapsed? How much does the temperature of the gas rise in 1 hour?
 
To MDQ:
Motor Daddy said:
So the gas gets hotter, and the can heats up and melts, right?
Click to expand...
No. A kilowatt-hour is a unit of ENERGY not a unit of POWER. Thus things don't continue to get hotter just because they have energy.
How did you measure the .5 kw-hr of thermal energy?
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293 degrees K. 2.2 kilograms of gasoline. Look up the thermal constant of gasoline and calculate it for yourself.
How much time elapsed? How much does the temperature of the gas rise in 1 hour?
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See above.
 
billvon said:
To MDQ:

No. A kilowatt-hour is a unit of ENERGY not a unit of POWER. Thus things don't continue to get hotter just because they have energy.
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Where did I say a kw-hr is a unit of power???

So no getting hotter, so no thermal energy. So where is the energy in the gas? How much work is the gas doing in the can?

A kilowatt-hour is a unit of energy which is equal to power*time, which is equal to (work/time)*time, which is equal to ((force*distance)/time)*time. So energy= ((force*distance)/time)*time

Good now?

Do you need me to break it down in torque, RPM, and time, for you? :rolleyes:
 
billvon said:
Here: "So the gas gets hotter, and the can heats up and melts, right?"

I see you do not understand the term "thermal energy."
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The problem is not me, it's your failure to understand what a unit of energy is. If you claim the gas has thermal energy of .5 kw-hr, then how did you measure that while the gas was in the can?

Please don't try to say you would take the gas and burn it, or that we know that gas can burn and can perform work in the future. Just tell me how you measured the thermal energy while the gas was in the can?
 
Motor Daddy said:
If you claim the gas has thermal energy of .5 kw-hr, then how did you measure that while the gas was in the can?
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I didn't measure it; I did the math. You can too. (Well, that might be a bad assumption. Trust me, it's easy to do.)
Please don't try to say you would take the gas and burn it
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No, you didn't mention anything about oxygen so the only available energy is the thermal energy inherent in the warm gasoline.
Just tell me how you measured the thermal energy while the gas was in the can?
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Again, math.
 
billvon said:
I didn't measure it; I did the math. You can too. (Well, that might be a bad assumption. Trust me, it's easy to do.)

No, you didn't mention anything about oxygen so the only available energy is the thermal energy inherent in the warm gasoline.

Again, math.
Click to expand...

I measured the energy of 1 kw-hr when the light bulb operated for 10 hours. In 10 hours of measure the bulb consumed 1 kw-hr of energy.

How many kw-hr of energy did you measure in the gas when you measured the thermal energy, and how many hours did you measure, and perform your calculations with?
 
Motor Daddy said:
The problem is not me, it's your failure to understand what a unit of energy is. If you claim the gas has thermal energy of .5 kw-hr, then how did you measure that while the gas was in the can?

Please don't try to say you would take the gas and burn it, or that we know that gas can burn and can perform work in the future. Just tell me how you measured the thermal energy while the gas was in the can?
Click to expand...

This is just another example of how your limited understanding of simple physics concepts leads to your meltdowns when someone tries to expand the concept beyond your tiny sliver of undertanding
 
Motor Daddy said:
How many kw-hr of energy did you measure in the gas when you measured the thermal energy, and how many hours did you measure and perform your calculations with?
Click to expand...

None. You do not need to know time to calculate energy. You are confusing power and energy again.
 
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