Once the water molecules forms; H2O, the H2O molecules will interact further with each other via what is called hydogen bonding. Hydrogen bonds are not only electrostatic between opposite charges but will also have partial covalent bonding characteristics. This causes neighboring water molecules to bind together like a very weak covalent bond. The result is the liquid state at much higher temperatures than expected by a molecule so light.
but before the H2O molecule forms and /or is forming what is the mechanisum that allows this molecule to form
as we know neither the hydrogen or the oxygen atom becomes a liquid at room temps.
The precise mechanism of the combustion reaction between hydrogen and oxygen takes place by a series of pathways involving radicals.but before the H2O molecule forms and /or is forming what is the mechanisum that allows this molecule to form
As has been pointed out before, this comes down to the nature of the bond between hydrogen and oxygen, within a water molecule, once it is formed.as we know neither the hydrogen or the oxygen atom becomes a liquid at room temps.
The formation of water from hydrogen and oxygen has nothing to do with the temperature at which the these three substances form liquids.
Fill a room with 2 parts hydrogen and 1 part oxygen the gases will not react. Walk into the room and try to light a cigar. The gases will almost instantly convert to water. They will most likely locate your remains quite a distance from the point of original ignition. That is because there is a certain amount of energy that is needed to break the bonds of Hydogen and oxygen and allow them to recombine to water. The formation of water is extremely exothermic so the heat released from the each subsequent water molecule formation will allow more hydrogen and oxygen to form water in a sort of cascade affect.
But like I said this mechanism has nothing to do with the condensation temperature of any of the three materials.
I have the impression at certain ratio of the two gases they will react without a spark
That would be news to me.
Which means there was a spark.An ignition wire was used
Right, when you said without a spark I assumed you meant without a heat source. I also assumed you meant STP. If you rapidly increased the pressure you could also get a mixture of hydrogen and oxygen to ignite; ala dieseling.
The bottom line is that you need an energy source at STP to initiate a mixture of hydrogen and oxygen reaction.
edited to add: In my job we use hydrogen as a carrier gas in a >1000F reaction chamber. If the chamber overpressurizes (not anymore we fixed it) the gas would vent out of the chamber. 1000+ degree pure hydrogen hitting the atmosphere will wake you up in a hurry. It sounds like a 12 ga shotgun going off by your head! No spark needed just the heat of the gas was suffincient to initiate the reaction.
Thank you no ill intent of my part
“ Originally Posted by river
but before the H2O molecule forms and /or is forming what is the mechanisum that allows this molecule to form ”
The precise mechanism of the combustion reaction between hydrogen and oxygen takes place by a series of pathways involving radicals.
It always makes me cringe when people explain chemical reactions by saying that the atoms "want" things or "try" to do things. It usually doesn't really explain anything, because obvious the atoms don't actually "want" or "try" anything. But, whatever...The reason this reaction is so energetic is oxygen will try to complete its octet of electrons. To do so, it needs two more electrons.
It is electrostatic attraction that causes the negative electrons to stick to the positive nucleus until the octet is full. The electrostatic repulsion is between the electrons, but the overall electrostatic potential energy of the electrons+nucleus system is still lower when the electrons are stuck to the nucleus (until the octet is filled, at which point adding more electrons causes the electrostatic potential energy to go up). Magnetic interactions don't really have anything to do with it; the energy involved in the magnetic interactions is trivial compared to the energy involved in the electrostatic interactions. Magnetic interactions don't really become significant until you get to the d and f orbitals, and even then, it's usually a pretty subtle influence.Although oxygen will have more negative charge than positive charge and have electrostatic repulsion, the magnetic addition is more powerful.
It always makes me cringe when people explain chemical reactions by saying that the atoms "want" things or "try" to do things. It usually doesn't really explain anything, because obvious the atoms don't actually "want" or "try" anything. But, whatever...
Highly unlikely.The reason orbitals have opposite spin electrons is this allows magnetic addition.
No, an orbital has electrons with opposite spins because of the exclusion principle. It has nothing to do with magnetism.The reason orbitals have opposite spin electrons is this allows magnetic addition.
No, it is energetically favorable for electrons in a given subshell to be around other electrons with the same spin, due to exchange interactions. This is why, for example, all the electrons in a half-full subshell will tend to have the same spin.Same spin electrons will repel.
This just isn't ccorrectBoth have the same electrostatic repulsion, but magnetic addition will be the deciding factor whether the electrons can share the orbital.
I don't know what you mean by "moving in opposite directions."Getting back to oxygen, when oxygen gets two extra electrons to complete its octet, all the P electrons are moving in opposite direction...
You appear to be attempting to describe exchange interactions, but you're getting it wrong. Exchange stabilization happens between elections in the same subshell with the SAME spin, not opposite spin. See Hund's rule. And as was already explained, these interactions are pretty trivial compared to the electrostatic energies involved.... in each P-orbital and each orbital is orientated in 3-D to the others (x,y,z). This gives extensive magnetic addition among all the electron currents. This stability is created even before we add the attraction to the protons.
No, I can assure you that the I don't imagine electromagnets when I'm thinking about electron interactions around a nucleus...I think about my p-chem textbook.Maybe your misunderstanding of orbital magnetisim is connected to you thinking in terms of magnetism being only something we see in iron, and not in terms of any moving negative charge creating a magnetic field. That is why we call it the electromagnetic force; electrons are always in motion.