Nature of Time Dilation and Length Contraction

DaleSpam said:
No, the orbits would still be circular in the pole-centered coordinates. In fact, the orbits would be circular in any un-boosted (relative to the ECI) inertial frame.

Perhaps it would be easier to think of the orbit as a helical worldline in spacetime. Moving the center to the pole (or to any other point) would simply shift the helix. A boost would simply be a rotation of the helix. In any case the helical path can still be calculated just fine as can the proper time and the coordinate time at any point along the helix.

-Dale
You are only thinking of a single satellite, perhaps an equatorial orbit. You have 24 clocks in 6 orbital planes, all of which must beat at the same rate. Simply defining a circle as viewed from a different location does not keep the relative velocity of the satellite the same at apoapsis and periapsis of a POLAR orbiting satellite, for example. Multiple moving clocks can only be synchronized if all their orbits are circular, and all are orbiting a common coordinate point at the same velocity, the center of the Earth in the GPS example. This IS the ECI frame of reference. THEN, the ECEF frame of reference MUST have the same center-of-earth coordinates as the ECI frame. All position calculations must be done in the ECEF frame, not the ECI frame. The ECI frame is used only for clock synchronization due to velocity of the satellites relative to a non-rotating, earth-centered reference frame. All other corrections, such as gravitational time dilation, Sagnac effect, etc., are done in the ECEF frame of reference.
 
Tom2,

"What spacetime is" is an open question. Some hold the Newtonian view that it has a seperate existence apart from matter and energy. Others share the point of view of Leibniz that spacetime is defined only by the spatial and temporal relations that events have with one another. Whatever your interpretation of spacetime, your coordinate system is an abstract, mathematical construct that gets superimposed on spacetime. It's how an observer keeps track of events. Spatial measurements were always known to be coordinate system dependent. What SR adds to this is that time is also coordinate system dependent.

If we assume that spacetime is a physical entity I can understand how it might be possible for matter to curve it. After all, the curvature of spacetime caused by mass is a local interaction. A person can clearly see the cause/effect relationship between matter and the curvature of spacetime, and can imagine a mechanism that is responsible for it.

However, I do not understand how an observer's relative motion can effect spacetime in the observer's entire frame of reference (which, by the way, includes the entire universe). I don't see the cause/effect relationship, nor do I see a mechanism that can make this possible. Do you? Do you find the curvature of spacetime in GR as real as the length contraction of spacetime in SR? Of course, both are mathematically possible, but are the both physically possible?
 
2inquisitive said:
Multiple moving clocks can only be synchronized if all their orbits are circular, and all are orbiting a common coordinate point at the same velocity, the center of the Earth in the GPS example.
This is incorrect (according to SR). Multiple moving clocks can be synchronized as long as their positions are known and the speed of light is constant. If clock A receives a signal at sa=(cta,xa,ya,za) in some inertial frame which was broadcast from clock B at sb=(ctb,xb,yb,zb) (where ta and tb are measured by the different clocks) in that same inertial frame then the clocks are synchronized in that inertial frame iff |sa-sb|=0. Circular orbits are easier to track and easier to keep synchronized and accurate, but not essential. The ECI frame is also easier to use, but not essential.

Here is a simplified but concrete example:

Let's say that we have two satellites in circular orbits in different orbital planes. They might have worldline equations in the ECI like

sa = (ct, sin(wt), cos(wt), 0)
sb = (ct, cos(wt), 0, sin(wt))

The north pole in the ECI is at p=(0, 0, 0, r) where r is the radius of the earth. So, in a pole-centered frame the equations of motion would be

sa' = sa-p
sb' = sb-p

The positions are still known and c is still constant in the pole-centered frame so the clocks can still be synchronized.

If we wanted to use a boosted frame then there would be some Lorentz transform L from the ECI to the boosted frame. Then the equations of motion would be:

sa' = L.sa
sb' = L.sb

Again, the positions are still known and c is still constant in the boosted frame so the clocks can be synchronized.

-Dale
 
MacM said:
I really, really, hope this comment means you disagree that clocks at the equator and poles of earth have a common tick rate.
No. Based on your previous post I thought it was pretty clear that you wanted to start an irrelevant comment contest. Frankly, I am not sure who came out ahead there.


MacM said:
You apparently fail to realize that v3 is the relative velocity between the clocks if you were using SR.
Wrong. v3= (v2-v1)/(1-v2 v1) would be the SR relative velocity between the clocks. However, why would we want to calculate that? Both sets of clocks are (approximately) in rotating frames so c is not constant in their frames. Therefore we want to synchronize each set of clocks with hypothetical colocated inertial clocks. For that, the relevant velocity is relative to the inertial frame, not the other clocks. It is not that difficult to grasp.


MacM said:
Considering the magnitude of correctly posted calculations I won't even respond to this false innuendo.
ROFL!

-Dale
 
DaleSpam said:
No. Based on your previous post I thought it was pretty clear that you wanted to start an irrelevant comment contest. Frankly, I am not sure who came out ahead there.

The question remains. Do you agree that (other than topological elevation changes and crust density anomalies) the earth's geoid (oblate speroid) results in SR and GR affects cancelling such that over the surface clocks tick at a common rate? Yes or No?

Wrong. v3= (v2-v1)/(1-v2 v1) would be the SR relative velocity between the clocks. However, why would we want to calculate that? Both sets of clocks are (approximately) in rotating frames so c is not constant in their frames. Therefore we want to synchronize each set of clocks with hypothetical colocated inertial clocks. For that, the relevant velocity is relative to the inertial frame, not the other clocks. It is not that difficult to grasp.

Technically correct but using the velocity added formula (as you very well know) does not alter the result because these velocities are sub-subluminal.

I'll make you happy and recalculate using velocity addition. Then perhaps you will address the issue instead of trying to dodge it. :bugeye:

Using the VAF V3 = 3,410.7001953125m/s instead of just 3,410.7m/s. You still want to ignore the -5.8us/day SR figure vs the actual GPS figure of -7.2us/day using a local preferred common rest frame instead of SR?

Correction: I had posted from memory and the -5.8us/day according to SR is incorrect it is -5.583779us/day. That versus -5.583780us/day using your veloicty addition formula value for V3. However hardly changes the fact that the correct value is -7.2us/day based on using absolute veloicty to a local common preferred rest referance instead of SR's relative velocity. (It is absolute in the sense that it has no reciprocity, not that the value is absolute).

BTW are my calculations correct? :D
 
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MacM said:
The question remains. Do you agree that (other than topological elevation changes and crust density anomalies) the earth's geoid (oblate speroid) results in SR and GR affects cancelling such that over the surface clocks tick at a common rate? Yes or No?
Yes. I have read that the GPS system was designed that way and in my personal experience the GPS system works, so why would I disagree.


MacM said:
Technically correct but using the velocity added formula (as you very well know) does not alter the result because these velocities are sub-subluminal.
I know, I was just incredibly amused how you were boasting about "the magnitude of correctly posted calculations" when you didn't even have the formula right.


MacM said:
I'll make you happy and recalculate using velocity addition. Then perhaps you will address the issue instead of trying to dodge it. :bugeye:
I didn't dodge it, but since your reading is apparently as poor as your math I will be glad to re-post it
DaleSpam said:
However, why would we want to calculate that? Both sets of clocks are (approximately) in rotating frames so c is not constant in their frames. Therefore we want to synchronize each set of clocks with hypothetical colocated inertial clocks. For that, the relevant velocity is relative to the inertial frame, not the other clocks. It is not that difficult to grasp.

-Dale
 
DaleSpam said:
Yes. I have read that the GPS system was designed that way and in my personal experience the GPS system works, so why would I disagree.

I would have no idea. But that was the inferance of your post.

I know, I was just incredibly amused how you were boasting about "the magnitude of correctly posted calculations" when you didn't even have the formula right.

I think you are desperate. NOBODY in their right mind would use velocity addition at such subluminal values. You are being silly.

I didn't dodge it, but since your reading is apparently as poor as your math I will be glad to re-post it -Dale

Funny how you can post "I didn't dodge it" but then dodge it in the same post. :rolleyes:

************ Correction using Dale's velocity addition value *********

Using the VAF V3 = 3,410.7001953125m/s instead of just 3,410.7m/s. You still want to ignore the -5.8us/day SR figure vs the actual GPS figure of -7.2us/day using a local preferred common rest frame instead of SR?

Correction: I had posted from memory and the -5.8us/day according to SR is incorrect it is -5.583779us/day. That versus -5.583780us/day using your velocity addition formula value for V3.

An increase by 1.000000179/1. Picky, picky. Can you imagine had I pulled this on one of you?

However that hardly changes the fact that the correct value is -7.2us/day based on using absolute velocity to a local common preferred rest referance instead of SR's relative velocity. (It is absolute in the sense that it has no reciprocity, not that the value is absolute).

BTW are my calculations correct?
****************************************************

Wiggle, wiggle. We await.
 
MacM said:
I would have no idea. But that was the inferance of your post.
I don't know how you infered my opinion on GR v. SR effects from a comment on socks.


MacM said:
Funny how you can post "I didn't dodge it" but then dodge it in the same post. :rolleyes:
...
Wiggle, wiggle. We await.
OK, here goes take 3:
DaleSpam said:
However, why would we want to calculate that? Both sets of clocks are (approximately) in rotating frames so c is not constant in their frames. Therefore we want to synchronize each set of clocks with hypothetical colocated inertial clocks. For that, the relevant velocity is relative to the inertial frame, not the other clocks. It is not that difficult to grasp.
What exactly do you think was the design goal of all of the timing correction factors used in GPS?

-Dale
 
MacM:

You lying sack of crap.

Speaking of lying sacks of crap...

When I first posted GPS information you didn't seem to know anything about it.

I knew the basics of the relativistic corrections necessary. I admit I had never had the need to look up the details of the system prior to having to explain them to you.

2Inquisitive gave you some quick courses and nothing, NOTHING, I have said has ever been demonstated invalid by you.

2inquisitive was very helpful.

Practically everything your have said has been demonstrated invalid, and not only by me.

You infact have flip flopped from GPS proves SR to GPS doesn't use SR. You have flipped from orbit is not inertial since it is an accelerated frame to it is inertial since it is in free-fall.

The GPS system relies on general relativity to work correctly. SR is a subset of GR, so if GR applies so does SR. I have never claimed that orbits are not inertial in the context of GR, since by definition free-fall frames are inertial.

Get real all this is available for readers to research back through.

Yes. Which is why I'm not bothering to go over it again, years later. But you're still stuck at the same place you were when we started. That's the only point I was making.

Have a nice life, MacM.
 
James R said:
I knew the basics of the relativistic corrections necessary. I admit I had never had the need to look up the details of the system prior to having to explain them to you.

Not on your best day. When I introduced the GPS issues you were all over the map (wrong BTW) and not once corrected anything I had to say.

2inquisitive was very helpful.

You bet he was. FYI he and I were in general agreement with a couple of symmantical exceptions. I clearly knew 6 times what you knew and he knew 6 times what I knew but wht I knew was generally corect and what you tried to claim was outright BS.

Practically everything your have said has been demonstrated invalid, and not only by me.

Outrightly false. Liar.

The GPS system relies on general relativity to work correctly. SR is a subset of GR, so if GR applies so does SR. I have never claimed that orbits are not inertial in the context of GR, since by definition free-fall frames are inertial.

You have claimed GPS orbit to be inertial and you have also claimed they were accelerating frames. You have argued your "Subset to GR" view before and it doesn't hold water. Not that it isn't a subset of GR but that it must therefore be valid.

GR restores the preferred view and eliminates reciprocity. SR is about relative velocity between clocks. Surface clocks at the equator or poles have the same tick rate because SR and GR cancel. The velocity compensation made is for the absolute orbit velocity using the ECI FOR.

(absolute in this context means no reciproicty, not in value).

Yes. Which is why I'm not bothering to go over it again, years later. But you're still stuck at the same place you were when we started. That's the only point I was making.

Good since my jpoint hasn't changed and has (and still does properly describe GPS. Yours hasn't).

Have a nice life, MacM.

I do. Get a life James R
 
DaleSpam said:
I don't know how you infered my opinion on GR v. SR effects from a comment on socks.


OK, here goes take 3:What exactly do you think was the design goal of all of the timing correction factors used in GPS?

-Dale

You choose to ignore the content of my post. I will ignore yours.
 
MacM:

When I introduced the GPS issues you were all over the map (wrong BTW) and not once corrected anything I had to say.

If you're going to dredge up ancient history, do it properly. Quote the relevant posts. I dare you.

To use your favorite word, I'm not interested in your "innuendo".

You have claimed GPS orbit to be inertial and you have also claimed they were accelerating frames.

I assume this is a misunderstanding on your part, as usual. Let me clarify for you. In GR, orbits are inertial, since they are free-fall frames. On the other hand - and this is where you probably got confused - in Newtonian physics orbits are not inertial, since a force of gravity acts to accelerate the orbiting object at all times.

Are we clear now?

You have argued your "Subset to GR" view before and it doesn't hold water. Not that it isn't a subset of GR but that it must therefore be valid.

Simple logic:

1. SR is a special case of GR.
2. GR is a correct theory.
3. Therefore, all parts of GR are correct, including SR.

You can't attack (1), since it is the simple truth. You can try to attack (2) if you wish. But once (1) and (2) are established, the only possible conclusion is (3).

Are we clear?

GR restores the preferred view and eliminates reciprocity.

No. There are no preferred frames in GR.
 
MacM said:
You choose to ignore the content of my post. I will ignore yours.
ROFL! Reading your posts is so much fun. I respond each time to your point and you try to pretend each time that I didn't, and then you claim that I am the one ignoring the content of your posts. You really have exchanged sense for non-sense. This is truly amusing.

-Dale
 
James R said:
MacM:



If you're going to dredge up ancient history, do it properly. Quote the relevant posts. I dare you.

Ditto.

To use your favorite word, I'm not interested in your "innuendo".

Ditto.

I assume this is a misunderstanding on your part, as usual. Let me clarify for you. In GR, orbits are inertial, since they are free-fall frames. On the other hand - and this is where you probably got confused - in Newtonian physics orbits are not inertial, since a force of gravity acts to accelerate the orbiting object at all times.

Are we clear now?

Never has been any issue on my part. You were not teaching you were (as you are here) trying to find anything you could say to give the appearance of correcting my views. Doing so you have posted statements which are completely contridictary.

And no I am not wasting my time seaching through 4 years of crap to prove my assertion since you seem to feel you can make any false statement against me without doing the same.

Any such requirements is a two way street.

Simple logic:

1. SR is a special case of GR.
2. GR is a correct theory.
3. Therefore, all parts of GR are correct, including SR.

Rhetoric.

A and B are parts of a theory. A says it is Red, B says it is green; since we have pictures of it being red, it must therefore also be green.

You can't attack (1), since it is the simple truth. You can try to attack (2) if you wish. But once (1) and (2) are established, the only possible conclusion is (3).

Are we clear?

You cannot advocate validity of a theory which is based on faulty physics.

Are we clear?

No. There are no preferred frames in GR.

Preferred frame in the sense that GR has no reciprocity. Back with some referances.
 
Huh?

In GR, when a scenario contains one participant who has accelerated, and one participant who has not accelerated, the one who has NOT suffered acceleration is given the preferred title of prime, or, stationary.

As much as I have a personal phobia against another rehash of Dreaded Twin Paradox, Einstein himself claimed that the DTP, created by SR, was solved by GR with its mechanism for selecting, on the basis of who accelerated and who did not, the preferred frame of stationary observer, or participant.

Of course, it may depend on what definition of "preferred" is preferred.
 
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James R said:
The GPS system relies on general relativity to work correctly.
This is only in theory i.e. if positions would be determined directly by comparison of the satellite time signal with a ground clock. In practice however positions are determined by differences of the time signal for different satellites. This means that there is actually no accumulation of positional errors due to the different rate of clocks in orbit. Taking the usually quoted a clock rate difference due to Relativity of 38 microseconds/day, this translates into a positional error of merely 1 cm, which is even less than the presently claimed accuracy of the GPS system (see my page Global Positioning System (GPS) and Relativity for more).

Anyway, I am not so sure if one should necessarily trust information that comes from the military (as they are still running the GPS system). For obvious reasons, they surely won't release all the information they have.

Thomas
 
DaleSpam said:
ROFL! Reading your posts is so much fun. I respond each time to your point and you try to pretend each time that I didn't, and then you claim that I am the one ignoring the content of your posts. You really have exchanged sense for non-sense. This is truly amusing.

-Dale

Considering that this is at least the 3rd or 4th time I've posted this question and your responses have been negative innuendo, I'll post it again and see just how long you choose to ignore thie issue.

Funny how you can post "I didn't dodge it" but then dodge it in the same post. :rolleyes:

************ Correction using Dale's velocity addition value *********

Using the VAF V3 = 3,410.7001953125m/s instead of just 3,410.7m/s. You still want to ignore the -5.8us/day SR figure vs the actual GPS figure of -7.2us/day using a local preferred common rest frame instead of SR?

Correction: I had posted from memory and the -5.8us/day according to SR is incorrect it is -5.583779us/day. That versus -5.583780us/day using your velocity addition formula value for V3.

An increase by 1.000000179/1. Picky, picky. Can you imagine had I pulled this on one of you?

However that hardly changes the fact that the correct value is -7.2us/day based on using absolute velocity to a local common preferred rest referance instead of SR's relative velocity. (It is absolute in the sense that it has no reciprocity, not that the value is absolute).

BTW are my calculations correct?
****************************************************
 
tsmid said:
This is only in theory i.e. if positions would be determined directly by comparison of the satellite time signal with a ground clock. In practice however positions are determined by differences of the time signal for different satellites. This means that there is actually no accumulation of positional errors due to the different rate of clocks in orbit. Taking the usually quoted a clock rate difference due to Relativity of 38 microseconds/day, this translates into a positional error of merely 1 cm, which is even less than the presently claimed accuracy of the GPS system (see my page Global Positioning System (GPS) and Relativity for more).

Anyway, I am not so sure if one should necessarily trust information that comes from the military (as they are still running the GPS system). For obvious reasons, they surely won't release all the information they have.

Thomas
I took a quick look at your page, tsmid. What you are effectly calculating is a change in the speed of light due to frequency shift, then calculating the difference in travel times over 20000 meters based on the difference in travel speeds. Think this through again. Light travels almost 300 meters in one microsecond. In 38 microseconds, light will travel 11,400 meters. If there is a descrepency of 38 microseconds between the clocks, the calculated distance will be off by 11,400 meters. IIRC, the GPS clocks are synchronized to within about 42 nanoseconds per day of UTC time (other than leap seconds, which corrections for are included in the signal). This precise time is broadcast by the satellites for precision users on Earth, including the Arecibo radio telescope in Puerto Rico. Or at least, Arecibo used to use GPS signals, I believe they have recenty gone to using pulsars for precise timing purposes.
 
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