Ghost:
Your basic misunderstandings of Newton's 3rd law are really a topic for a different thread. But we should be able to correct them in one post. If you still don't understand after this, then a separate thread for educating you on this particular topic may be required, but let's try.
If you want to examine your hand as the system of interest, then you can do an F=ma analysis for that. Determine all the forces acting on your hand (including the push-back force from the ball, of course). Add up all those forces. If there is a net force on your hand, then your hand will accelerate.
Here's where the learning happens in one sentence: A "Reaction" force in Newton's 3rd law always act on a different system from the force to which the reaction force applies.
Example: Your hand (system 1) pushes on a ball (system 2). The force of your hand on the ball is a force acting on the ball. By Newton's 3rd law of motion, the ball exerts an equal an opposite "reaction" force. The reaction force is a force that acts on your hand. Notice: force of hand on ball acts on system 1. Reaction force of ball on hand acts on system 2.
Learning should now be complete. Homework exercise: Choose some other examples where two objects or systems interact. Try to identify the action-reaction force pairs and the objects/systems on which they act.
Your basic misunderstandings of Newton's 3rd law are really a topic for a different thread. But we should be able to correct them in one post. If you still don't understand after this, then a separate thread for educating you on this particular topic may be required, but let's try.
The net force on the ball is non-zero, so the ball accelerates. But the ball's push back on your hand is a not a force that acts on the ball; it is a force that acts on your hand.The very fact that I accelerated the ball is evidence to the fact that the net force was greater than zero. So the ball did not "push back" with the same force as I pushed it. The net is the difference.
If you want to examine your hand as the system of interest, then you can do an F=ma analysis for that. Determine all the forces acting on your hand (including the push-back force from the ball, of course). Add up all those forces. If there is a net force on your hand, then your hand will accelerate.
Here's where the learning happens in one sentence: A "Reaction" force in Newton's 3rd law always act on a different system from the force to which the reaction force applies.
Example: Your hand (system 1) pushes on a ball (system 2). The force of your hand on the ball is a force acting on the ball. By Newton's 3rd law of motion, the ball exerts an equal an opposite "reaction" force. The reaction force is a force that acts on your hand. Notice: force of hand on ball acts on system 1. Reaction force of ball on hand acts on system 2.
Learning should now be complete. Homework exercise: Choose some other examples where two objects or systems interact. Try to identify the action-reaction force pairs and the objects/systems on which they act.
Claims like that make you look like an uneducated fool, given that it is clear from your post that you haven't understood Newton's 3rd law prior to now. You should probably avoid extravagant self-serving claims in future. They may make you feel good about yourself, but they risk making you look like a fool to others when they are unjustified.Sorry, Newton was wrong, and I proved that decades ago!
I know. It's ridiculous. But that's what you said you were doing.Measuring mass? Measuring a number?
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