Downwind faster than the wind

A.T. said:
J/s = N*m/s
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You still did not give me understanding. How do you get VELOCITY from that?

Is lifting 50 lbs 10 feet not the same work as lifting 10 lbs 50 feet? If the work is the same and the time is the same at 3 seconds, then the power is the same, but the velocity is not the same.

Power=Work/Time
Power=(50*10)/3
Power=(500)/3=166.66 work per second=.303HP
Velocity=feet/second=3.33 ft/s


Power=Work/Time
Power=(10*50)/3
Power=(500)/3=166.66 work per second=.303HP
Velocity=feet/second=16.66 ft/s
 
A.T. said:
That's a formula for power, not for work.
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Work per second is power. 550 ft-lbs of work per second is equal to 1 HP.

You claimed Power=Force*Velocity, so I gave you the force and velocity, and you did not tell me the power. Why not? Is it because you don't know the work, the distance, or the time?? (rolls eyes)
 
Motor Daddy said:
So let's apply your logic to a simple example:

You lift a 100 lb rock 10 feet away from the center of the earth. How much energy is that, 1,000 joules?
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No. There is no weight at the center of the Earth and the offset 10' from center can't be calculated, since the errors in modeling the Earth as a perfect sphere are greater than the minuscule gravitational differential at that coordinate.

To correctly pose the question you should ask me if you lift a weight of 100 N a distance of 10 m from the surface of the Earth whether it requires 1000 Joules, and the answer is yes. It's just not the conventional way of treating weight; we measure in in kg. So suppose you ask me how many Joules it takes to lift 100 kg a distance of 10 m from the surface of the Earth. In this case the answer is 9,800 J.

Weight = mass x gravitational constant = 100 kg x 9.8 m/s[sup]2[/sup] = 980 kg-m/s[sup]2[/sup] = 980 N = Force

Work = Force x distance = weight x distance = 980 N x 10 m = 9,800 J
 
Aqueous Id said:
No. There is no weight at the center of the Earth and the offset 10' from center can't be calculated, since the errors in modeling the Earth as a perfect sphere are greater than the minuscule gravitational differential at that coordinate.
Click to expand...

I said I lift it away from the center of the earth, I didn't say it was at the center of the earth and then lifted away. If I lift a rock off the ground in a direction away from the center of the earth it doesn't mean that I lifted the rock from the center, it means I lifted the rock in a direction AWAY from the center of the earth. It's just like you to come up with some BS because your BS is just that, BS!
 
Motor Daddy said:
I said I lift it away from the center of the earth, I didn't say it was at the center of the earth and then lifted away. If I lift a rock off the ground in a direction away from the center of the earth it doesn't mean that I lifted the rock from the center, it means I lifted the rock in a direction AWAY from the center of the earth. It's just like you to come up with some BS because your BS is just that, BS!
Click to expand...

I just got here. I see your panties are pre-wadded for me. Has the wind machine guy been torquing your wrench?
 
Edit, If you just got here, then did someone hijack your account in post #53?

No, if they had they wouldn't have been so generous as me to lend you a helping hand with your physics questions. They would have been all over you like a 200 ft-lb torque wrench on a Coors Lite.

What I meant was, I hadn't been here for hours, not in this current confusion over the definitions of energy, work and power. Yes , I was here during the prior confusion over that. Hopefully it's making some sense to you.
 
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