noDoes water flow through a funnel faster clockwise or counterclockwise?
That's it.
Also, would this be different in northern or southern hemisphere?
OK
Clarification:
When pouring water from one container to another through a funnel:
Surmising that water normally flows out of a drain clockwise here in Iowa so "going with the flow" by pouring the water into the funnel so that it starts clockwise would logically seem to allow it to flow faster
the question obtains
even if that is true, would it be only initially?
or would that extra boost of speed last throughout the complete pour?
(assuming that I could keep a constant height of water in the funnel)
It does not. This is a myth.Surmising that water normally flows out of a drain clockwise here in Iowa
I was told the same about water rotation while in school.It does not. This is a myth.
Agree with those saying rotation direction is in practice irrelevant. But as to what empties a bottle faster - YouTube to the rescue:Does water flow through a funnel faster clockwise or counterclockwise?
That's it.
Also, would this be different in northern or southern hemisphere?
OK
Clarification:
When pouring water from one container to another through a funnel:
Surmising that water normally flows out of a drain clockwise here in Iowa so "going with the flow" by pouring the water into the funnel so that it starts clockwise would logically seem to allow it to flow faster
the question obtains
even if that is true, would it be only initially?
or would that extra boost of speed last throughout the complete pour?
(assuming that I could keep a constant height of water in the funnel)
Aha, but that is, he says in the video, because with the bottle there is an advantage in allowing air to enter as the water leaves. So that would not apply to the general case of water going down a plughole. So there is no conflict with what Janus said earlier.Agree with those saying rotation direction is in practice irrelevant. But as to what empties a bottle faster - YouTube to the rescue:
And many more just like it.
Both of these actions: lengthening the path and narrowing the stream, each reduce the rate of water exiting.My take: by lengthening the total path and thinning the stream
Well there are small plugholes, and then again there are big, multi-hole plugholes. So it would depend on the specifics. But if you check back, the argument got to be over emptying via a funnel. I've no doubt one could make it empty slower than the the straight-down gurgle-gurgle method, by creating excessive vortex speed. The trick to optimum emptying rate would be getting enough swirl motion to create that central evacuated vortex, without too much centrifugal force fighting against gravity.Aha, but that is, he says in the video, because with the bottle there is an advantage in allowing air to enter as the water leaves. So that would not apply to the general case of water going down a plughole. So there is no conflict with what Janus said earlier.
This may be of interest:Well there are small plugholes, and then again there are big, multi-hole plugholes. So it would depend on the specifics. But if you check back, the argument got to be over emptying via a funnel. I've no doubt one could make it empty slower than the the straight-down gurgle-gurgle method, by creating excessive vortex speed. The trick to optimum emptying rate would be getting enough swirl motion to create that central evacuated vortex, without too much centrifugal force fighting against gravity.
Anyone planning on doing the optimization calcs via hydrodynamics maths? Didn't think so.![]()
https://www.straightdope.com/column...-counterclockwise-in-the-northern-hemisphere/The erroneous bit of folk wisdom you refer to says water always drains in a clockwise direction in the Southern Hemisphere and in a counterclockwise direction in the Northern Hemisphere. The supposed reason for this is the Coriolis effect, which has to do with the effect of the earth’s rotation on moving objects.
Now, there is such a thing as the Coriolis effect. It explains why macroevents such as hurricanes rotate in a clockwise direction in the Southern Hemisphere and counterclockwise in the Northern Hemisphere.
However, when you get down to itty-bitty phenomena such as the water draining out of your bathtub, the Coriolis effect is insignificant, amounting to roughly three ten-millionths of the force of gravity (in Boston, at least, which is where they happened to do the measuring).
Yeah I think we are all on board now re clockwise vs counterclockwise on bathtub scale situations. How you pull the plug out will be the main determinant, not piddling Coriolis effect, all other things being equal (shape of basin, position of plughole etc.). But my last post was regarding the case of deliberately creating swirling motion - as in that YouTube vid. Clock 'speed' not direction is what matters there.This may be of interest: https://www.straightdope.com/column...-counterclockwise-in-the-northern-hemisphere/
Not if they enable a more than compensating increase in average velocity via laminar flow - which appears to be the case, in certain common situations.Both of these actions: lengthening the path and narrowing the stream, each reduce the rate of water exiting.
There is always displacement of air to consider - even from an open source. Also, there is turbulence created within the stream - not just by returning air - to consider.Aha, but that is, he says in the video, because with the bottle there is an advantage in allowing air to enter as the water leaves. So that would not apply to the general case of water going down a plughole.
Didn't we once have a thread in which we examined the truth of the claim that a railway track running North-South would get greater wear on the inner side of the western rail, because of the Coriolis effect? I seem to recall a sideways thrust equivalent to several tens of kg weight, for a fast-ish locomotive. But maybe that was on a different forum......Yeah I think we are all on board now re clockwise vs counterclockwise on bathtub scale situations. How you pull the plug out will be the main determinant, not piddling Coriolis effect, all other things being equal (shape of basin, position of plughole etc.). But my last post was regarding the case of deliberately creating swirling motion - as in that YouTube vid. Clock 'speed' not direction is what matters there.
Yes I recall it too, and iirc it was a 'confirmed'. Too lazy to check the sums, but I'll blind wager the true figure will be hugely swamped by such other factors as prevailing cross winds, bias in lateral inclines & radius of bends along the journey.Didn't we once have a thread in which we examined the truth of the claim that a railway track running North-South would get greater wear on the inner side of the western rail, because of the Coriolis effect? I seem to recall a sideways thrust equivalent to several tens of kg weight, for a fast-ish locomotive. But maybe that was on a different forum......
The force would be dependent on the latitude of the train. The tangential velocity for any point on the surface of a sphere is w cos(x)r where w is the angular velocity, x the angle from the equator, and r the radius of the sphere.Didn't we once have a thread in which we examined the truth of the claim that a railway track running North-South would get greater wear on the inner side of the western rail, because of the Coriolis effect? I seem to recall a sideways thrust equivalent to several tens of kg weight, for a fast-ish locomotive. But maybe that was on a different forum......
Indeed, it must logically be zero at the equator as it reverses direction as you move into the opposite hemisphere. I think I assumed a latitude of 45 degrees for the exercise for convenience.The force would be dependent on the latitude of the train. The tangential velocity for any point on the surface of a sphere is w cos(x)r where w is the angular velocity, x the angle from the equator, and r the radius of the sphere.
If we use an example where both r and w = 1 we can easily compare the change in tangential velocity for moving from the pole to one degree from the pole and moving from the equator to 1 degree from the equator.
Moving 1 degree from the pole gives a difference of cos(89)-0 = 0.01745
Moving 1 degree from the equator gives a difference 0f 1- cos(1) = 0.0001523, a much smaller difference.
Thus the sideways acceleration felt by the train as it moves North-South is weakest near the equator and strongest at near the poles.