No, this is incorrect. Mass/energy would not be conserved either. As I carefully pointed out, according to your suggestion, at the instant of the new particle's creation there is less mass than there was previously, meanwhile the child particles are at rest and therefore have 0 KE. Therefore the missing mass is not accounted for by any extra KE. The KE is not restored in your view until after they accelerate, in the interim mass and energy and mass/energy are not conserved.Prosoothus said:Mass would not be conserved, but mass/energy would be. The decay would would create two masses at rest, and some energy that would accelerate the electron to its final speed.
OK, I can see this. You could propose another fundamental force, the Prosoothus force. This force could be conservative or at least it could have some sort of associated potential energy. At the instant of particle creation the particles would be at rest and the missing energy would be stored in the ProsoothusPE. It could then be released in order to accelerate the child particle, never to act on it again. Mass/KE would not be conserved but mass/(KE+ProsoothusPE) would be conserved.Prosoothus said:It would be a large, mysterious, and unkown repulsive force, and it would violate the conservation of energy, but it would not violate the conservation of mass/energy in the entire reaction. This is how the reaction would occur:
K-40 -> Ca-40 + electron + energy (unknown)->
The energy would create a force that accelerates the electron.
->Ca-40 + electron + energy (kinetic energy of electron).
At every step, mass and energy would not be conserver, but mass/energy would be.
That is fine, but don't attempt to claim that Occam's razor favors this position. I see nothing fundamentally wrong with your theory, but it is unarguably more complicated than the standard approach.
Again, I disagree. It may be easier for you to assume an unknown force, but it is easier for me to assume an initial velocity. Particles are weird enough that the idea of their being born moving at some speed doesn't bother me a bit. I see no justification for your assumption that the initial speed of a child particle is the same as the parent particle. Why that speed rather than some other? Since you have to pick a speed anyway it seems much easier and simpler to pick a speed that fits all of the observations and conservation principles without requiring the existence of an unknown and temporary fundamental force. Your Prosoothus force seems especially weird to me in the fact that it equally affects every single particle immediately after its creation and then never again thereafter. It would seem as though all particles are born with some Prosoothus "charge" that rapidly decays never to return. How is this preferable to being born with some relative velocity? Your suggestion seems self-consistent but needlessly complicated.Prosoothus said:It's far easier for me to assume that an unknown repulsive force accelerates the electron than to assume that the electron was created travelling at a high speed.
This would not be a problem. A finite force could yield an infinite acceleration for a massless particle, so a photon would never need to travel at less than c.Prosoothus said:When photons are emitted, relativists assume that they are "born" travelling at c. If a photon is actually born at a lower speed, and accelerates to c, then this causes two problems for relativity:
1) When the photon is travelling at a speed that's lower than c, then, according to Einstein's SR equations, the speed of light is not invariant to all inertial observers. This would eventually lead to the conclusion that light has a preferred frame of reference, or aether.
That would not be a problem either. Obviously your Prosoothus force causes the acceleration, no aether is required. Since the Prosoothus force only causes a particle's post-partum acceleration there is no reason to connect it with anything related to a particle's normal travel.Prosoothus said:2) If the photon accelerates to c, then what causes its acceleration? If it pushes against "something" to accelerate, then that "something" is the photon's aether. This would eventually lead to the conclusion that light only travels at c in its own aether, and not for all inertial observers.
-Dale