My argument is that you got the Pauli explanation all wrong, all along. Why is it so hard for you to admit that you were wrong?
You now have the correct writeup on what it means, I suggest that you spend some time understanding it.
Because I don't have it wrong.
I understood it back in Post 46, which you subssequently agreed to:
So then all one has to do to prove you wrong about rolling wheels is prove that an elementary point on a mirror has some component of motion that is perpendicular to the surface of the mirror, and you will admit you are in error right?
Yes, this is the discussion with pete
The only thing I have done is apply the equivalence principle to it, in other words, a moving mirror is equivalent to a moving observer watching a stationary mirror.
The person who has been trolling all along is you. You simply did not understand that the angle wrt the observer, while it plays a role in the Doppler effect it plays no role in the Doppler effect from moving mirrors. This is what the math of the Bateman paper (reprised by Pauli , in his book) teaches you:
-Velocity of the mirror perpendicular to the normal to the mirror => zero Doppler shift
-Velocity of the mirror has a non-zero component along the normal to the mirror => Doppler shift.
Yes, I got it 9 pages and 176 posts ago, thankyou.
Now, apply the principle of relativity.
-NOTHING to do with the motion of the observer, ok? And, before you ask again, since the statement is expressed in coordinate-free format, nothing to do with any frame of reference be that "the camera", "the observer" or whatever. It is a relationship between two vectors, valid in any system of coordinates (this is why it is "coordinate-independent").
Let me put it another way.
Post 212 I said this:
So... If I have a mirror in 3d space, that is oriented in the plain (X,Y,0).
And I have a Camera some height Z above the plain of the mirror.
And in the cameras rest frame I boost the mirror by (0,V,0).
You're arguing that the motion of the camera in the rest frame of the mirror is something other than (0,-V,0)?
That was for paralell motion. Now we're talking about perpendicular motion.
As I said yesterday:
...pauli suggested if the mirror is moving perpendicular to itself, doppler shift will be observed...
Which is the post we're discussing, I applied the equivalence principle to come to this:
[if] in the mirrors rest frame, [an] observer has any motion perpendicular to the surface of the mirror, then [that] observer will measure a doppler shift?
In other words, to use the formalism in post 212, boosting the mirror by (0,0,V) is equivalent to boosting an observer by (0,0,-V) in the mirrors rest frame.
In other words, the statement:
in the mirrors rest frame, the observer has any motion perpendicular to the surface of the mirror, then [any] observer will measure a doppler shift?
Is implied as a corollary when considering Pauli's statement in light of the equivalence of inertial frames.
in the mirrors rest frame, the observer has any motion perpendicular to the surface of the mirror, then [any] observer will measure a doppler shift?
Now, at this point you can do the honest thing and admit that you were wrong all along or you can continue to troll my posts on the subject as you have been doing for quite a while. If it is the latter, I will no longer respond.[/QUOTE]
I have not trolled you. I have simply tried to engage you in a reasonable, rational discussion, as I am now. All I am asking is if we apply the principle of relativity, is if a mirror moving perpendicular to its surface is equivalent to an observer moving perpendicular to the mirrors surface - or to rephrase it, is boosting a mirror by (0,0,V) the same as boosting an observer by (0,0,-V)?
It's a straight forward yes or no question.