1. How do you define Gravity in 'Schmelzer Gravity' ?
The gravitational field defines the most important properties of the ether, namely its energy-momentum tensor, the fields used in the energy and momentum conservation laws. These properties are the ether density, its velocity, and its stress tensor.
2. How do you give velocity to ether? When an object is moving how it shares its energy with ether?
I take a look at what I have guessed to be the continuity equation, namely $$\partial_m (g^{0m}\sqrt{-g} = 0$$, and compared this with the continuity equation $$ \partial_t \rho + \partial_i (v^i \rho) = 0$$. This gives $$v^i = g^{0i}/g^{00}$$. Then, there is nothing but the ether. Matter are waves of the ether. If a water wave is moving, how does it share its energy with water?
(The difference between water and ether is that we see only one type of water waves. If water has an thin oil film on the top, you can see also some color waves. The ether has, in this sense, much more properties, all fields of the SM are such properties.)
3. What gives a negative pressure to ether (apart from mathematics)?
Essentially they are nothing but mathematics.
4. Why a Gravastar should not have equation of state?
He has, of course, an equation of state. And for different types of material, the state will be different, and even the resulting radius of the gravastar will be different.
But this does not really matter, because for the qualitative prediction if there will be a stable gravastar or not nothing changes. For $$\Upsilon>0$$ there will be a stable gravastar, for arbitrary equations of state, and for $$\Upsilon<0$$ there will be none. And the radius of the gravastar will be, for values small enough to fit BB observations, in any way of type Schwarzschild radius + something very very small, something like Planck length or smaller.
5. Water Waves do not have density in the traditional sense, but water has, so Ether wave need not have density but ether must have. So anything which has density, will provide drag to all other celestial objects, it must interact, unless and untill you are claiming that your ether is Dark Ether.
Of course, the ether has a density, and this density is defined by $$\rho= g^{00}\sqrt{-g}$$. But matter does not have to swim through the ether like a swimmer in the water, but moves through the ether like a sound wave.
6. there is some argument on Gravitational Lensing in another thread which you are following, how does your theory explain Gravitational Lensing?
In the same way as GR, the equations are in no way different. If you want an informal explanation, think about sound waves in an inhomogeneous medium.
7. Your free parameter < 0 Gravastar and > 0, BH......this is the question of life and death, giving two distinct and nature changing results. How can you have such a free parameter in your theory? pick one pl?
I have a derivation, but this derivation does not fix it. A similar effect we have for the cosmological constant. There the derivation also tells us, that above signs are possible, in agreement with the Strong Equivalence Principle.
If I had to choose, I would choose the most beautiful universe, which would be the one with $$\Xi, \Upsilon > 0, \Lambda<0$$. The universe would be periodic, and there would be a unique vacuum state for the ether. But I see no reason to make such a choice. Most of the good properties of the theory are independent of this choice.
8. Since you claim quantizations, so how is life at Plancks scale or more reasonably at Quantum Level ?
I don't understand the question. The Planck length is some combination of various natural constants, inclusive Planck's constant, and is seen as the length where to ignore quantum effects of gravity is no longer possible. That's all. What my ether theory cares about is that quantization is possible without the conceptual problems of GR quantization. Here, the main issue is that I have a fixed background. The Planck length plays no role in these conceptual quantization problems.
9. Don't you think use of GR equations is oxymoron? Please note that GR equations are primarily for the curvature of spacetime in the presence of stress. But your background has no such thing called curvature of spacetime, so left hand of the EFE is meaningless for you. I can understand you may be talking about change in your ether distribution profile, but where is metric, where is the geometry of spacetime ?
The "geometry of spacetime" is anyway only an inaccurate analogy. A metric has to be positive definite, the spacetime "metric" is not. It is some purely mathematical analogy, which does not go very far even in mathematics.
The mathematical expression for "curvature" of the spatial part of the "metric" has a well-defined meaning. This spatial part of the "metric" is the stress tensor. Now one can ask if the stress is only the result of deformation from an undistorted stress-free reference state or not. If not, this is named "inner stress". And the mathematical formula for this inner stress is that for curvature.
The four-dimensional "curvature tensor" defines also similar properties with taking into account the change of the stress tensor, the changes in velocity and density too. So, it answers the question if the whole history of the ether can be simply described by a deformation of the same stress-free reference state during all the time.
Last but not least, I use a variant of the GR equations because the derivation of the theory tells me that I have to do this. (Ok, not completely fair, I have found the derivation later, after I have already known the equations, and the initial motivation was to have equations in agreement with observation. But so what, this history is not what counts, but the theory which has been obtained, and this includes the derivation which has been found.)