It still says the field. That's the electromagnetic field. Then it talks about electrical and magnetic force. But you said the coordinate transform of E and B fields. They aren't fields, they're forces.
You're making a completely pointless distinction. In common parlance in physics, a "field" is just the attribution of any value or quantity to every point in space or space and time. The electric and magnetic fields attribute vector (and pseudovector) values to every point in space and time and are thus fields. Likewise, the local temperature and density of a block of matter, the local velocity of a fluid, and the population density and internal migration of residents of Great Britain are all (or could be described as) fields.
The magnitude of an electromagnetic field at a given location is fully specified or 'measured' by six real numbers, which can be collected together into a single asymmetric tensor-valued field ($$F_{\mu\nu}$$), two vector-valued fields ($$\bar{E}$$ and $$\bar{B}$$), or just six real-valued fields ($$E_{x}$$, $$E_{y}$$, $$E_{z}$$, $$B_{x}$$, $$B_{y}$$, and $$B_{z}$$). These are different notations with different uses and advantages, but the information content in each case is exactly the same. They're different notations for exactly the same physics.
The electric and magnetic fields also aren't forces in the Newtonian sense of the word. They aren't the mass x acceleration of anything and they don't have the SI units of force. You can talk about the electric and magnetic forces on a charge (given by the respective terms in the Lorentz force law), but it's strictly a misnomer to call the electric and magnetic fields themselves "forces".
You apply a rotational magnetic force and you get a linear electric force. You apply a linear electric force and you get a rotational magnetic force.
No you don't. In a vacuum (i.e. in the absence of electric charges and currents), the two relevant Maxwell equations are
$$\begin{eqnarray}
\bar{\nabla} \,\times\, \bar{E} &=& -\, \frac{\partial \bar{B}}{\partial t} \,, \\
\bar{\nabla} \,\times\, \bar{B} &=& \frac{1}{c^{2}} \, \frac{\partial \bar{E}}{\partial t} \,.
\end{eqnarray}$$
These relate the curl of the electric and magnetic fields, respectively, to the
time-variance of the magnetic and electric fields. The first equation implies that if the magnetic field is changing in magnitude over time, then the electric field must have nonzero curl, and vice-versa. The second equation similarly implies that if the electric field is changing in magnitude over time (in the absence of electric currents) then the magnetic field must have nonzero curl, and vice-versa.
Be aware this means it is perfectly possible for the
electric field to be completely concentric, i.e. you can't simply recover the electric and magnetic fields as the "radial" and "concentric" parts of a combined field, as you seem to suggest in a diagram in your opening post, because an electric field need not always be radial.