Presupposition-Part number (the number of gaps) negates the second number(gap number) -one of then must be gaps numbers, other parts who have contact where is deleted together Process: P1- 0=¤3(1)2(1)2¤n-(.0)¤2(2)2¤=1 2 P2- 1 =¤3(1)2(1)2¤n-(.1)¤2(2)2¤=1 ¤1(6)2¤ P3- ¤1(2)1¤ =¤3(1)2(1)2¤n-(.2)¤2(2)2¤=2 ¤2(6)1¤ P4- 1 =¤3(1)2(1)2¤n-(.3)¤2(2)2¤=1 3 P5- 0 =¤3(1)2(1)2¤n-(.4)¤2(2)2¤=1 ¤3(6)1¤ P6- 1 =¤3(1)2(1)2¤n-(.5)¤2(2)2¤=2 ¤3(1)1(4)2¤ P7- 1 =¤3(1)2(1)2¤n-(.6)¤2(2)2¤=1 ¤3(1)2(4)2¤ P8- 0 =¤3(1)2(1)2¤n-(.7)¤2(2)2¤=0 ¤3(1)2(5)2¤ P9- 0 =¤3(1)2(1)2¤n-(.8)¤2(2)2¤=0 ¤3(1)2(1)1(1)1(2)2¤ P10- 0 =¤3(1)2(1)2¤n-(.9)¤2(2)2¤=0 ¤3(1)2(1)4(2)2¤ --images-- General form negates 1 =an-(.c)b=negates 2 suptraction or negates 1 =an-(.c)b negates 2 suptraction [S47]-negates subtraction CM-[S47] -dot no know ________ images are in pdf (Download pdf) PDF - https://docs.google.com/open?id=0B3WUvmmPIWZ4MmpzME5YNF9UbXF3eFJES1dsNkZPUQ
Presupposition-Part number (the number of gaps) negates the second number(gap number) -one of then must be gaps numbers,contact remains , the rest is deleted Process: P1- 0 =¤3(1)2(1)2¤n-(.0)¤2(2)2¤=1 ¤2(2)2)¤ P2- 1 =¤3(1)2(1)2¤n-(.1)¤2(2)2¤=1 ¤2(2)1¤ P3- ¤1(2)1¤ =¤3(1)2(1)2¤n-(.2)¤2(2)2¤=2 ¤1(4)1¤ P4- 1=¤3(1)2(1)2¤n-(.3)¤2(2)2¤=1 ¤1(2)2¤ P5- 0 =¤3(1)2(1)2¤n-(.4)¤2(2)2¤=1 ¤2(2)1¤ P6- 1 =¤3(1)2(1)2¤n-(.5)¤2(2)2¤=2 1 P7- 1 =¤3(1)2(1)2¤n-(.6)¤2(2)2¤=1 1 P8- 0 =¤3(1)2(1)2¤n-(.7)¤2(2)2¤=0 2 P9- 0 =¤3(1)2(1)2¤n-(.8)¤2(2)2¤=0 1 P10- 0 =¤3(1)2(1)2¤n-(.9)¤2(2)2¤=0 0 --IMAGES-- General form negates 1 =an-(.c)b=negates 2 opposite subtraction or negates 1 =an-(.c)b negates 2 opposite subtraction [S48]-negates opposite subtraction CM-[S48] -dot no know
Presupposition-In an operation number can be replaced by other numbers Process: P1 2+(s.0)3=5 P2 2+(s.0)4=6 P3 2+(s.0)5=7 P4 2+(s.0)6=8 P5 2+(s.0)x|3[sub]1[/sub]6|=y General form a#(s.q)b=c a#(s.q)d=e ... a#(s.q)f=g a#(s.q)x|b[sub]h[/sub]f|=y ,#-calculation operations [S49]-function CM-[S49] -axiom ,real and infinite _________________ 2.write in abbreviated form (if the function can be final and natural) 2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40, 2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 , 2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94 2+(s.0)x|5[sub]5[/sub]38[sub]3[/sub](_50_)[sub]10[/sub]90[sub]7[/sub]92|=y
because I do not get it, here's the work of the occurrence arranged by the sheer number of mathematical notation, mathematical journals refused to publish it, see if it's worth. https://docs.google.com/file/d/0BzkWG0xdRpPYVTZxVThoUkJlRWs/edit
