Relativity and simple algebra

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ralfcis

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Relativity can be explained with basic algebra using only 2 formulae (the one for gamma and the relativistic velocity combo formula). These construct a simple graphical building block that can be joined by light signals to graphically show how relativistic phenomena such as time dilation, simultaneity, the muon experiment, the twin paradox can be explained through simple algebra.

There are no rotated frames here, only three types of lines v, v_t and v_h (half speed relativistic velocity), their reciprocals and their behavior when multiplied by Y (gamma). The math also avoids square roots and squares in the equations to make them work using simple addition and subtraction. There is no clock sync, only light signals and the assumption atomic clocks all run at the normal clock rate within their frames thanks to the principle of relativity.

I have a bunch of useful forms of the two main equations but I don't notice any easy way to put subscripts and superscripts here.
 
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Yes, it'll take some time to roll out the whole picture. It's mostly math and spacetime diagrams. However if you have specific questions I'll answer them.
 
The main equation (space and time velocity combination) is

c^2 = v^2 +v_t^2 also written as the gamma function
Y = c / sqrt(c^2-v^2) where ( v_t= c/Y and v = c/Y_t)

v_t is the velocity through time while v is the velocity through space. The faster you are observed through space, the slower your time rate is observed.

Here is the relativistic velocity combo equation of two velocities through space:

w =(v+ u) / (1 + vu/c^2)

So here is a more universal universal equation that includes relativistic velocity combination with space and time velocity combination:

c^2= ((v+u)^2+ v_t^2u_t^2) / ( 1 + vu/c^2)^2

The main equation is also written as:

or (ct')^2 = (ct)^2 - Yx^2 (Minkowski hyperbolic (difference of squares) form where hyperbolas intersect the same proper time for all velocity lines)

or (ct)^2= (ct')^2+ Yx^2 (Epstein pythagorean (sum of squares) form where circles intersect the same proper time for all velocity lines) [/tex]

The basic graphical building block will be shown next

I tried $$v_t$$. It doesn't work so my equations will be difficult to follow
 
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ralfcis said:
I tried $$v_t$$. It doesn't work so my equations will be difficult to follow
Click to expand...
It looks fine.
I see this:
$$v_t$$


[ TEX ]Y = \frac{c}{ \sqrt{(c^2-v^2)} } [ /TEX ]

$$Y = \frac{c}{ \sqrt{c^2-v^2} } $$


Note: LaTeX will not be immediately visible after you save your post and view it. You must refresh the page to see it it rendered correctly.
 
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Ok one more time

The main equation (space and time velocity combination) is

$$ c^2 = v^2 +v_t^2 $$ also written as the gamma function $$Y = \frac{c}{ \sqrt{(c^2-v^2)} } $$ where $$( v_t= c/Y$$ and $$ v = c/Y_t)$$

$$v_t $$ is the velocity through time while v is the velocity through space. The faster you are observed through space, the slower your time rate is observed.

Here is the relativistic velocity combo equation of two velocities through space:

$$w =(v+ u) / (1 + vu/c^2)$$

So here is a more universal universal equation that includes relativistic velocity combination with space and time velocity combination:

$$c^2= ((v+u)^2+ v_t^2u_t^2) / ( 1 + vu/c^2)^2$$

The main equation is also written as:

or $$(ct')^2 = (ct)^2 - x^2$$ (Minkowski hyperbolic (difference of squares) form where hyperbolas intersect the same proper time for all velocity lines)

or $$ (ct)^2= (ct')^2+ x^2 $$ (Epstein pythagorean (sum of squares) form where circles intersect the same proper time for all velocity lines)

The basic graphical building block will be shown next
 
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Ok now I need to create a sheet of all my equations with the latex control script visible so I can cut and paste equations in subsequent posts. How do I make the script words like [tex visible like you did in your examples?
 
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This is my equation sheet to cut and paste equations:
(Not all were successful, a 2nd page will be needed for corrections)

[ tex] [/tex]

[ tex] c^2 = v^2 +v_t^2[/tex]
[ tex]Y = \frac{c}{ \sqrt{(c^2-v^2)} } [/tex]

[ tex]v_t= c/Y [/tex]
[ tex] v = c/Y_t[/tex]

[ tex]w =(v+ u) / (1 + vu/c^2)[/tex]

[ tex]c^2= ((v+u)^2+ v_t^2u_t^2) / ( 1 + vu/c^2)^2[/tex]

[ tex](ct')^2 = (ct)^2 - x^2 [/tex]

[ tex](ct)^2= (ct')^2+ x^2 [/tex]

[ tex]v = v_h(v_t/c +1) [/tex]
[ tex]v_t = v_h_t(v/c +1)[/tex]
[ tex]v = 2c^2v_h / (c^2 + v_h^2) [/tex]
[ tex]v_t= 2c^2v_h_t/ (c^2+ v_h_t^2)[/tex]

[ tex]v_h = c(c-v_h_t) / (c+v_h_t) and v_h_t = c(c-v_h) / (c+v_h)[/tex]

[ tex]v/(c-v) = 2cv_h / (c - v_h)^2[/tex]

[ tex]Y = 2Y_h^2 - 1 = (c^2 + v_h^2)/(c^2 - v_h^2) = c/v_t = (1/(1-v_h/v)) -1 = 2c^2v_hv/(c^2 - v_h^2) = 2Y_h^2 v_h /v [/tex]

[ tex]v_h=Yv/(Y+1) [/tex]

[ tex](Yv)^2 = v^2/(1-v^2)[/tex]

[ tex]v= c sqrt(Y^2-1)/Y[/tex]

[ tex]v_t = c/Y = DSR(c+v) = v_h_t(1 +v/c)[/tex]

[ tex]t'=x(v_h +c)/c [/tex]

[ tex]v' = Yv[/tex]
[ tex]t = Yt'[/tex]
[ tex]x'=Yx[/tex]

[ tex]Yv =x/t'[/tex]

[ tex]Yu/Yw=DSR_v[/tex]

[ tex] t'(1-Y) [/tex]
[ tex]t'=x/Yv[/tex]
[ tex]vx/c^2[/tex]

[ tex]tpad=t′−x/Yv[/tex]

[ tex]t'=sqrt(t^2- x^2)[/tex]

[ tex]t' =xDSR_o/Yv[/tex]

[ tex]t_p_s= xv_p_s = xYv/(1+Y) [/tex]

[ tex]wt= c / Yw = c / (YvYu(1 + vu/c^2)) [/tex]

[ tex]Y_ww = (v+u)YuYv [/tex]

[ tex]v_h_t=cDSR [/tex]

[ tex] cDSR = sqrt((c-v)/(c+v)) [/tex]

[ tex]DSR_v= Yu/Yw[/tex]

[ tex]Y(c-v) = c/DSR[/tex]

[ tex]DSR_w= DSR_v* DSR_u [/tex]
[ tex]DSR_w^2= (c-w)/(c+w) [/tex]

[ tex]w = c(1-DSR_v^2 DSR_u^2 )/(1+DSR_v^2 DSR_u^2 )[/tex]

[ tex]DSR = Y(1-v/c)[/tex]

[ tex]t' = X(c+v_h)/c [/tex]

[ tex] t'(DSR - 1)[/tex]

[ tex]t' = X(-2v_h)/(c+v_h) [/tex]

[ tex]A = (v+u)[/tex]

[ tex]B= (1+vu/c2)[/tex]

[ tex]sqrt(c^2B^2-A^2) = c/YvYu =v_tu_t[/tex]



v Y $$v_h $$ $$v_t $$ $$v_h_t$$ DSR t'

1 1 1 0 0 0

3280/3281 3281/81 40/41 81/3281 1/81 81

40/41 41/9 4/5 9/41 4/36 9

255/257 65/16 15/17 16/65 1/8 8

24/25 25/7 3/4 7/25 1/7 7

35/37 37/12 5/7 12/37 6/36 6

12/13 13/5 2/3 5/13 1/5 5

77/85 85/36 77/121 36/85 8/36 9/2

15/17 17/8 3/5 8/17 9/36 4

4/5 5/3 1/2 3/5 12/36 3

3/5 5/4 1/3 4/5 18/36 2

1/2 1.155 .268 .866 .577 1.73

8/17 17/15 1/4 15/17 3/5 5/3

5/13 13/12 1/5 12/13 24/36 3/2

1/3 1.06 .17 .943 .707 1.41

12/37 37/35 1/6 35/37 5/7 7/5

7/25 1/7 24/25 27/36 4/3

16/65 1/8 255/257 15/17 17/15

9/41 1/9 40/41 4/5

0 0 1 1

21523360/21523361 21523360/21529922 6561/21523361 1/6561
 
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ralfcis said:
The main equation (space and time velocity combination) is

c^2 = v^2 +v_t^2 also written as the gamma function
Y = c / sqrt(c^2-v^2) where ( v_t= c/Y and v = c/Y_t)
Click to expand...
What is $Y_t$?

More importantly, what is $v_t$, physically? What do you mean by a "velocity through time"? Clearly, $v_t$ has dimensions of a regular velocity, so what is it, exactly?

So here is a more universal universal equation that includes relativistic velocity combination with space and time velocity combination:

c^2= ((v+u)^2+ v_t^2u_t^2) / ( 1 + vu/c^2)^2
Click to expand...
You haven't yet posted a derivation of this.

The main equation is also written as:

or (ct')^2 = (ct)^2 - Yx^2 (Minkowski hyperbolic (difference of squares) form where hyperbolas intersect the same proper time for all velocity lines)
Click to expand...
What does $t'$ indicate, in this equation, as opposed to $t$? I notice there are no $x'$ terms in the equation...
 
Ok problem solved with the equations that weren't coming out properly:


[ tex] v = v_h(v_t/c +1) [/tex]

[ tex] v_t = v_{ht}(v/c +1) [/tex]

[ tex] v = 2c^2v_h / (c^2 + v_h^2)[/tex]

[ tex] v_t = 2c^2v_{ht} / (c^2 + v_{ht}^2)[/tex]

[ tex] v_h = c(c - v_{ht}) / (c +v_{ht}) [/tex]

[ tex] v_ht = c(c - v_h) / (c +v_h) [/tex]

[ tex] v_t = c/Y = DSR(c+v) = v_{ht}(1+ v/c)[/tex]

[ tex] t_{ps} = xv_{ps}= xYv/(1+Y)[/tex]

[ tex] v_{ht} =cDSR[/tex]

v Y [ tex]v_t[/tex] [ tex]v_h[/tex] [ tex]v_{ht}[/tex] DSR
 
I will answer your questions now but you might not understand the answers until I get to that part of my thread.

$$ v_t = c/Y = ct'/ct$$ is the velocity or rate of time through time. Now all clocks in their frames beat at the normal rate c through time. It's like looking at video in fast forward or slow motion. There are 3 types of rates through time in relativity. One the permanent slowing of time during an imbalance of relative velocities when one participant initiates a change which takes time for the other to register the change, another is the Doppler Shift Ratio which is partly an apparent rate caused mostly by the rate of info delay from a moving clock. The third is $$ v_t $$ which satisfies the main equation so that the faster you are observed through space, the slower your time rate is observed. As you can see from the equation, it's basically reciprocal time dilation.

For example if v=3/5c, $$ v_t = 4/5$$, DSR = .5c and if the participant was to turn around after 3 ly, she would age 2 yrs less when the two re-unite at Earth (i.e. the twin paradox.)

I'll answer each question in a separate post.
 
$$v_t= c/Y and v = c/Y_t $$

For example if v=3/5c , Y = 5/4 but there is a symmetry between velocity through space and the one through time. So if v = 3/5c $$ , v_t= 4/5$$ and $$Y_t = 5/3$$.

You may find this view unorthodox but I swear it came about from a discussion with Don Lincoln on the SPCF forum I was on years ago.
 
ralfcis said:
$$ v_t = c/Y = ct'/ct$$ is the velocity or rate of time through time.
Click to expand...
Relative to what? Some absolute standard of time?

Now all clocks in their frames beat at the normal rate c through time.
Click to expand...
That doesn't make sense. c is a velocity with dimensions of distance over time.

There are 3 types of rates through time in relativity. One the permanent slowing of time during an imbalance of relative velocities when one participant initiates a change which takes time for the other to register the change, another is the Doppler Shift Ratio which is partly an apparent rate caused mostly by the rate of info delay from a moving clock.
Click to expand...
Can you please give a specific example of the permanent slowing of time and show your calculations of that. What effect does a permanent slowing of time have on the rest of the universe?

The third is $$ v_t $$ which satisfies the main equation so that the faster you are observed through space, the slower your time rate is observed.
Click to expand...
By whom?

You're not making the "relativity" part very clear in what you're writing.

Do you understand reference frames? Do your equations or derivations use the idea of different reference frames?

---
Are you attempting to re-derive special relativity here, or is this a new theory of your own with its own postulates, supposed to replace special relativity? It's not clear to me.
 
You haven't yet posted a derivation of this.

I did on another forum. I can cut and paste it here but it's long and not written in TEX. I have found that no one has ever taken the trouble to look at my math because it takes a lot of effort to do so. It's not like Good Will Hunting where mathematicians read math like it was a language. So I'd suggest if you doubt the formula, plug in some values and make sure the numbers come out correctly.
 
Please answer one post at a time.

We are all stationary in our own frames and while our velocities through space in our own frames are zero, according to the main equation I posted, our velocities or rates through time are c. I did give examples of rates through time but for example if a ship was leaving earth at v=3/5c and both the earth and the ship were broadcasting a TV signal, it would appear that each would see the other moving in slow motion at .5c or half the normal rate that they would be moving in their own frames. If the ship was coming back, both would eventually see each other moving at double the normal rate in fast forward at 2c. Their clocks would appear to be moving double fast forward to each other while in their own frames, their clock rates would be normal at c.

This is just an example of an apparent rate through time and how things might look if we could actually see time dilation in real time which is not possible. It can only be calculated after the fact and is not the same rate as DSR shows us in real time. These are not absolute, they are relative and due to relative velocity between the two participants.
 
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