On Einstein's explanation of the invariance of c

Discussion in 'Pseudoscience Archive' started by RJBeery, Dec 8, 2010.

  1. Beer w/Straw Transcendental Ignorance! Valued Senior Member

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    There's 20 pages of this!

    Is it tit for tat or science?
     
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  3. Tach Banned Banned

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    We put you inside the box and you measure the light transit time. Is the transit time E-W equal to the transit time W-E?
     
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  5. Motor Daddy Valued Senior Member

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    You don;t understand the concept of light traveling independently of frames.

    Play along...

    You have two light sources in space, separated by a distance. If the lights emit light simultaneously, does the light impact each other at the midpoint?
     
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  7. Tach Banned Banned

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    First answer my simple question.


    In what frame , Motor Mouth?
     
  8. Motor Daddy Valued Senior Member

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    Two lights in space that maintain an exact distance between them at all times. Do the lights impact each other at the midpoint if they are emitted simultaneously???
     
  9. RJBeery Natural Philosopher Valued Senior Member

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    Yet...
    Motor Daddy, the above reason is why MMX does not need to rely on synchronized clocks and one-way light travel times. As you time the round-trip journey of the light in various directions, you would expect to get different times in your world. I could only make you see this by having the country cruise along at .9c absolute velocity, but the principle is the same with ANY absolute velocity.

    Make sense?

    And Tach, I don't think you're being constructive to the thread. If you disagree with folks and find yourself unable to change their thinking just move on...no need to act like a douche.
     
  10. Tach Banned Banned

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    In which frame, Motor Mouth? The way you ask the question shows that you don't even understand what you are trying to ask.
     
  11. Tach Banned Banned

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    Based on the mistakes in your posts, you should look in the mirror, you might see the douche.
     
  12. Motor Daddy Valued Senior Member

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    What choices of frames do I have? There is two light sources in space, maintaining an equal distance between them at all times.
     
  13. Tach Banned Banned

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    Two:

    1. The frame containing the light sources
    2. A frame moving with speed v > 0 wrt the light sources.

    The distance between the light sources is D.
    Please answer separately for each one.
     
  14. Motor Daddy Valued Senior Member

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    A frame moving with speed v > 0 wrt to the light sources? Which frame would that be, as there is two lights in space?
     
  15. Tach Banned Banned

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    Any frame.
     
  16. Motor Daddy Valued Senior Member

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    There is 2 light sources in space. Are you saying there is a peeping tom off to the side, that I don't know about?
     
  17. Tach Banned Banned

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    Right, there is an infinity of peeping toms moving at arbitrary speeds v. Now, stop stalling and answer the question.
     
  18. Motor Daddy Valued Senior Member

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    wrong, there are no peeping toms, just two light sources at this point.
     
  19. Motor Daddy Valued Senior Member

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    Better yet, is there a midpoint between two sources that maintain a fixed distance between them?
     
  20. Motor Daddy Valued Senior Member

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    I gotta go, anyway. I'm already late. You think about it long and hard, as I am going to give you enough rope to hang yourself.
     
  21. RJBeery Natural Philosopher Valued Senior Member

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    Tach, if I've made errors in my posts then you can call me wrong (I'd be curious to know where I've erred, though). You can even call me an idiot if you wish, which would be rude but still related to your point. But a "douche" is related to behavior, not knowledge, and I try to stay mature and civil. I'd like to point out that Motor Daddy generally appears to maintain civility as well.
    These are good examples of douche-baggery. They aren't addressing the posts, they are attacking the poster. Your posts sound a bit like AlphaNumeric if he were about 20 IQ points dumber...(ok, NOW you can call me a douche

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  22. phyti Registered Senior Member

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    MMX ain't what it used to be!
    In the MMX, the difference in calculated transit time for equal path
    lengths (as setup) was expected to produce an interference pattern. None
    were seen. The explanation at that time was length contraction.
    Later the Kennedy-Thorndike experiment was done, with unequal path
    lengths (as setup). No interference pattern was seen.

    If length contraction explained the MMX result, it surely could not
    explain the KDX result.
    If path length was the determining factor for producing intereference,
    and neither experiment produced any, it seems reasonable that
    interference does not depend on path length. Therefore length
    contraction is not the explanation for the MMX result.

    A fact of unknown value.
    The MMX used a continuous light source, therefore light from an earlier
    part of the x beam, could have coincided with the arrival of the y beam
    when recombined. This raises issues of persistence of vision for high
    frequency changes of interference (if any).

    The KDX was actually testing time dilation and concluded that the light
    frequency changed according to SR. My understanding of this is a doppler
    shift along the inbound and outbound paths which conserves wave number,
    an invariant. A receiver can only detect the same number of wave lengths
    that are emitted. This results in no phase shift, and thus no
    interference.
     
  23. phyti Registered Senior Member

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    People like you restore our faith in each other, always willing to help out!
     

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