# Is this real maths or somebody winding me up?

Discussion in 'The Cesspool' started by amber, Feb 4, 2018.

1. ### amberRegistered Member

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If u = <3,-2> and v = <4,5> then u · v = (3)(4) + (-2)(5) = 12 - 10 = 2. (b) If u = 2i + j and v = 5i - 6j then u · v = (2)(5) + (1)(-6) = 10 - 6=4. Proof: We prove only the last property. Let u = <a, b> . Then u · u = <a, b>·<a, b> = a · a + b · b = a2 + b2 = (/a2 + b2)2 except when quantified by any 7point artimace exemplified by stasus elements found in field mortification parameters.
Let u, v and w be three vectors in R3 and let λ be a scalar. (1) v × w = − w × v. (2) u × ( v + w) = u × v + u × w. (3) ( u + v) × w = u × w + v × w. (4) λ( v × w)=(λ v) × w = v × (λ w). We then end up in obvious paradoxity instigated by v x y intigers elevated beyond tartus secondary aspects.

3. ### DaveC426913Valued Senior Member

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These are not things.
Someone's having someone on.

BTW, simply Goggling a few of those terms would clear up the mystery.

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7. ### arfa branecall me arfValued Senior Member

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It looks like badly translated Russian, or perhaps Greek. Maybe Latvian.

That said, some of the equations look ok except for some of the notation and the lack of superscripts, i.e. exponents.

8. ### DaveC426913Valued Senior Member

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Yea, the ideas behind convincing gibberish is to make it look plausibly real.

But I assume any auto-translator would leave words alone it didn't understand, so we still shouldn't be seeing nonsense words.
And if it were a human translator, we're back to the same problem.

Actually, I guess that's the same thing. I see no way for gibberish words to get into a translated text - automatically or manually - unless it's deliberate.

9. ### Michael 345Bali tonightValued Senior Member

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YES

It's the upgrade Time Travel expodent oscillation modified frequency generator calculations formula giving new extra power to the TARTUS (TARDIS Mk 2) while being more eco friendly

Release date to be announced

TARTUS
Time And Relative Dimension Under Space

which is the next generation of the

TARDIS
Time And Relative Dimension In Space

10. ### arfa branecall me arfValued Senior Member

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5,749
Let's untranslate some of it:

Looks like the dot product of two vectors, u and v. But, <u,v> (the inner product) is another way to write the dot product (usually restricted to 2 or 3 dimensional vectors). Hence it should be: If u = (2, -2) and v = (4,5) . . ., otherwise it looks ok.
This uses the i,j,k unit vector notation, looks pretty standard for 2 dimensions.
ok so far, but the rest goes off the rails more than a little.
Yep. The cross product is antisymmetric. There seems to be no problem with the rest of it, including the scalar multiplication. I have no idea what the "paradoxicity" is. Perhaps it means you shouldn't take any without food or a parachute (or something).

Last edited: Feb 4, 2018
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11. ### amberRegistered Member

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HUh, all the other people said is gibberish?

I am not surprised it is difficult to learn on the net when some people are teaching false information.

12. ### amberRegistered Member

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Any mathematicians on who fancy a challenge?

Can any mathematician explain a 0*0 matrice that is in continuous expansion from 0 to infinitely?

matrice Au []

matrice Bu []

I want to explain that both these matrices expand on manifestation and vanish . (gone in a puff a smoke )

A and B are just tags, u is internal energy

13. ### amberRegistered Member

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Come on guys somebody must know how to explain

Δ0=Δ1u/t=1u/k where k is space

14. ### amberRegistered Member

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I have just learnt it is called an empty matrice, I simply want to expand this matrice at the speed of c proportional to the inverse then it is back to an empty matrice.

So far I have my abstraction as
Δ0=(+1u/t)/k how do I put at the speed of c to the end of this?

The visual looks like this

[]<<[..........1u...........]>>[]

or simply 010

or simply 0→1u→0/t

Last edited: Feb 4, 2018
15. ### amberRegistered Member

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0u+1u-1u=0u?

so can I express?

[]+[1u]-[1u]=[]??

16. ### DaveC426913Valued Senior Member

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The rest of us are examining the words.
Arfa brane is taking a stab at the math, to see if it is as ... gibberish-ish.

amber likes this.
17. ### amberRegistered Member

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Let u = <a> and v = <b>. Then u · v = <a>·<b> = a · b?

Would the above be meaningful in anyway? I am trying to learn this .

18. ### DaveC426913Valued Senior Member

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I'm not sure what the < and > are for (matrix?), but assuming it doesn't destroy commutativity, then yes:
If u=a, and v=b then
u·v = a·b

19. ### amberRegistered Member

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Thank you, much appreciated, I am trying to learn and practice this subject. I am not sure what the <> meant myself , I presumed it was to represent the force direction and showed a and b was in a state of expansion. Now I am at a loss for what it meant if you do not know yourself.
How would I explain that (a) manifests then inversely proportionally disperses at the speed of light c?

Coordinates a=0,0,0

I want to try and explain 0 point energy.

20. ### DaveC426913Valued Senior Member

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I am not sure what that means. Particularly, use of the word 'disperse'.

If c is inversely proportional to a, then its simply c ~1/a.

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22. ### amberRegistered Member

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How would I describe at?

example : Δu=(+1)-(+1) at c ~1/a

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