origin..

ok we agree LS=c..

So, when travelling LS for 1 second it travels 300.000km correct ?

So, instead it has to travel 300.010 for we have 10 km/s as a starting speed..

And it will take therefore 300.010/300.000 correct ? (1 s + 1(30.000) second right ?

Now on the way back when emitted from that exact 300.010 km, and we are still travelling at that same speed

the point of origin will have moved 10 km closer when the light arrives again right ?

It'l be at 20km..300.010-20 km right ?

So asially when it travels back it reaches the destination sooner..299.990 km travel..

Since LS is constant it'll therefore be less then 1s, 299.990/300.000 <1 second yes ?

this MUST be true when LS is constant , and we agreed on that already..

Now, the distance travelled to and fro will be 300.010+299.990 km altogether yes ?

The start and return point are still 300.000 km apart from each other..from beginning till end..

So yes, IF LS =c and we agreed on that the entire journey will take 2 second right ?

Now, is there a difference in timing when you compare AB and BA against each other ?

300.010 to, 299.990 fro..

Now, when you check the timing in B it'll show a differnce..

NOT in LS, since that is c...so, what can explain the timing difference ?

The initial speed we had..

And thus you can establish an absolute speed, in accordance with V=LS-LS.

For when you take the speed of light which is absolute and constant, and subtract the speed of light you have absolute zero speed..

So, by checking the time light travels from one point to the next and both point are moving at the same speed, ANY AND ALL

timing differenecs can ONLY be from the initial speed..

LS = constant..and it will take 300.000+Vinit/300.000 second to get there..

My math in this case isn't off..

Every experiment failed for it was based on reflection..

300.010+299.990 = 600.000 km, so yes, in all there was 2 seconds passed..but from AB there's a difference in the time light travelled

at it's constant speed, and on BA there was also a difference in time travelled by the light as it was less than 300.000 km..

Total = 600.000 km = 2 lightseconds..

To 300.010 km= >1 second (1 second +1/30.000th) second

Fro 299.990 km= <1 second (1 second - 1/30.000th) second..

Total time 2sec..and yes constant ls =c..

The only way you can tell the initial speed is by using lightspeed since it IS a constant..

LS-LS= absolute zero speed, not relative, since LS isn't dependant on perspective, it's absolute..

Based upon LS's absolutism, you can get the absolute speed of anything, without perspective..

When you refract or bend back the same light it will have the same configuration as it had when it left..

It doesn't go faster or slower..

And that's why it will take 1sec + 1/30.000 second to get to it's destination when teh destination is moving at 10km/s away from the point of emission..

Let me make it simple for you...

When light has to travel 300.000 km or 300.010 km, does that make a difference ? Yes..

And that has nothing to do with MY understanding of the speed of light and velocity..

300.000 does NOT equal 300.010, no matter what physics element you want to apply..

So when light travels each distance:

300.000 ......300.010

--------- =/= ---------- must then also be true..

300.000.......300.000

so, timing difference will occur when the timing is done correctly, and not by any type of bounce..

Once you go bounce, it will read exactly the same every time..

300.010+299.990=600.000= EXACT 2LS...but 300.010 is NOT 300.000 km/s