10c - c

Discussion in 'Physics & Math' started by BrJLa, Aug 12, 2008.

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  1. BrJLa Registered Senior Member

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    Interesting challenge. I'll have to chew on it.
     
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  3. BrJLa Registered Senior Member

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    Actually, I went awry on step 1. I'm making an intuitionist argument, and Brouwer's intuitionism rejected that you can define something by defining what it can't be or can't not be. He rejects excluded middle arguments. You need to define an object affirmatively. I'm not saying your points aren't valid. They're great. I just need to work on how to confront them.
     
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  5. Reiku Banned Banned

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    Repeating 0.9 equals to 1.
     
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  7. BrJLa Registered Senior Member

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    My initial response is that I'm not trying to prove anything about "the largest number less than 1". I was only trying to illustrate that "there is no number you can't keep adding to" is no different than "there is no number of iterations such that you can't do one more", to demonstrate that you can't really operate long division to the point where there is no remainder.

    I'm trying to argue that a decimal point followed by an actual infinite number of 9's isn't real. It's not really an argument about the largest number less than 1. It's that there is no actual infinity that you can incorporate into a real number. By itself, a decimal point followed by an infinite number of 9's is not a real number. As the product of a mathematical operation, an operation performed an infinite number of times isn't real. And as the finishing member in an infinite set it isn't real. That the largest real number less that 1 is .9r is a poor argument that I shouldn't have made.
     
  8. Guest254 Valued Senior Member

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    Decimal expansions are just a convenient (ish) way of defining numbers. An infinite decimal expansion is defined as the limit of a sequence of partial sums - and the limit is well defined.
     
  9. Steve100 O͓͍̯̬̯̙͈̟̥̳̩͒̆̿ͬ̑̀̓̿͋ͬ ̙̳ͅ ̫̪̳͔O Valued Senior Member

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    x = 0.9r
    10x = 9.9r

    no assumptions made that 0.9r = 1 yet

    10x - x = 9x
    9.9r - 0.9r = 9

    still no assumptions

    9.9r - 0.9r = 10x - x = 9
    9x = 9
    x = 1 = 0.9r

    Nowhere do we have to assume 0.9r = 1 to prove that it does.
    Which part do you think otherwise about?
     
  10. BrJLa Registered Senior Member

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    My argument is .9r isn't a real number.

    10(infinity) - (infinity) = 9(infinity) isn't a real expression. In a similar way, you can't plug in .9r and think it's giving you a real result.
     
    Last edited: Aug 12, 2008
  11. Steve100 O͓͍̯̬̯̙͈̟̥̳̩͒̆̿ͬ̑̀̓̿͋ͬ ̙̳ͅ ̫̪̳͔O Valued Senior Member

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    Sorry, I don't know what you're on about. Please explain what is wrong with the proof I posted.
     
  12. Guest254 Valued Senior Member

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    I think in this type of situation it's best to be blunt and to the point:

    0.9r is the limit of a Cauchy sequence in R, and is therefore also in R.
     
  13. BrJLa Registered Senior Member

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    Is 10(infinity) - (infinity) = 9(infinity)?

    10(infinity) - (infinity) might equal zero, instead.

    But, really it's just nonsense. It makes no sense to ponder 10(infinity) distinct from infinity.

    I'm saying if .9r isn't a real number, then the 10c - c = 9c operation isn't guaranteed to work.
     
  14. AlphaNumeric Fully ionized Registered Senior Member

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    Noone claiming that.

    0.9r is obviously between 2 and 0. And, as Guest points out, since it's the sum of real numbers, which is between 0 and 2, it's a real number.

    Remember, 'real' doesn't mean 'it's valid', it's got a specific mathematical meaning. That which Guest gave.
     
  15. Steve100 O͓͍̯̬̯̙͈̟̥̳̩͒̆̿ͬ̑̀̓̿͋ͬ ̙̳ͅ ̫̪̳͔O Valued Senior Member

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    9.9r = 9.9999999999999...
    0.9r = 0.9999999999999...

    Is it so hard to see that the first minus the latter = 9?

    Where has this 10(infinity) nonsense come from?
    Recurring decimals are not infinitely large numbers. It is easy to see that 0.9r is less than 2, and easy to see that 2 is less than infinity.
     
  16. BrJLa Registered Senior Member

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    Yeah, I'll have to get my head around the intuitionist argument on continuity. My post count is too low to post links, but I'm going to read up on the google results for "cauchy intuitionist" later.
     
  17. Steve100 O͓͍̯̬̯̙͈̟̥̳̩͒̆̿ͬ̑̀̓̿͋ͬ ̙̳ͅ ̫̪̳͔O Valued Senior Member

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    1-0.9r
    What is the answer BrJLa?
     
  18. Guest254 Valued Senior Member

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    To be fair, it matters not one jot what argument you are hoping for! The construction of the real numbers exists without a person's preference for intuitive mathematics.
     
  19. BrJLa Registered Senior Member

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    No, it's not obvious. It's not obvious it even exists. It can't be constructed without infinity. It's either got to be a fraction, expressed as a decimal to an actual infinity number of places, then multiplied by its reciprocal. Or it's got to be the sum of a sequence of numbers that includes as its actual last member "... + 9/10^(infinity)", or without some other recourse to an actual infinity.
     
  20. BrJLa Registered Senior Member

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    As inexpressable as infinity minus 1.
     
  21. BrJLa Registered Senior Member

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    More precisely, as meaningless as 1/infinity.
     
  22. Steve100 O͓͍̯̬̯̙͈̟̥̳̩͒̆̿ͬ̑̀̓̿͋ͬ ̙̳ͅ ̫̪̳͔O Valued Senior Member

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    Why are you bringing infinity into the argument again? We are speaking of recurring decimals, not infinitely large numbers.

    The answer is 0

    Most of the time when I ask someone that they will answer 0.0r1
    makes sense right?
    The thing is the 1 does not exist as the 0s go on forever.

    Any number - itself = 0
    1 = 0.9r.

    Also, what is you answer to the above?
     
  23. Guest254 Valued Senior Member

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    Please don't tell people what does and doesn't exist within the realm of the real numbers until you've taken the time out to understand their construction. I realise you find the result you're speaking of odd, but don't presume that this feeling of unwarinesses puts you in a position to tell others what is correct or not.

    Some might construe such actions as presumptuous, naive and a little bit arrogant.
     
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