# Yang–Mills and Mass Gap

Discussion in 'Physics & Math' started by Thales, Nov 29, 2017.

1. ### NotEinsteinValued Senior Member

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I never claimed that you did said that in post #148, so I don't know where you are getting that from?

Alright, let's take a fresh look.

I agree so far.

This part is utter nonsense, because the units don't match.

3. ### hansdaValued Senior Member

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Good. You agree to this that $T\leq t$ as per my post #148.

Where the units are not matching.

5. ### NotEinsteinValued Senior Member

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Only in order to get at least one complete oscillation, as you yourself state. My point is that this is not generally true.

You wrote: $f=\frac{t}{T}$
$t$ has units of time.
$T$ has units of time.
$f$ has units of inverse time.
The left-hand side thus has units of inverse time, while the right-hand side is unitless. This makes the equation nonsense.

7. ### hansdaValued Senior Member

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Yes.

Why?

Seems you are not getting the point. To get the numerical value of rpm, you have to use this formula.

8. ### NotEinsteinValued Senior Member

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Because it is physically possible to rotate an object 180 degrees, i.e. half of a full rotation.

But the formula is nonsense. It's equivalent to asking if you are 5 apples old, or if you are 6 waters high? You seem to not understand the importance of units. Without understanding how units work, one cannot do any meaningful maths in physics at all!

9. ### hansdaValued Senior Member

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We know that massive, spinning particles are generated in pairs from particle photon through symmetry breaking, as in pair production. Here minimum energy of photon will be for one cycle. So, that minimum energy should correlate with minimum mass.

10. ### NotEinsteinValued Senior Member

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That's circular reasoning. You started out by saying that you are generating massive particles. Obviously there will be a minimum mass; their rest mass.

11. ### hansdaValued Senior Member

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You can see wiki article on pair production.

12. ### NotEinsteinValued Senior Member

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The words "symmetry" and "cycle" are not present on it, thus this article does not back up your statements. Please provide an actual source.

13. ### hansdaValued Senior Member

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Symmetry breaking is known from higgs mechanism

14. ### NotEinsteinValued Senior Member

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Which also isn't mentioned on that page. Are you even trying to back up your statements?

15. ### hansdaValued Senior Member

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You dont know higgs mechanism?

16. ### NotEinsteinValued Senior Member

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Please explain how it is relevant to your original statement, as it is not mentioned on that Wikipedia article.

17. ### hansdaValued Senior Member

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Particle photon is symmetrical. When its symmetry is broken, two assymetric massive particles are generated as in pair production.

18. ### hansdaValued Senior Member

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So, in pair production, the two particles generated can be considered as two half-photons.

19. ### hansdaValued Senior Member

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Thus minimum one photon cycle is necessary for minimum mass generation.

20. ### hansdaValued Senior Member

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So, the minimum mass will be $E=mc^2=h$ or $m=\frac{h}{c^2}$ .

21. ### NotEinsteinValued Senior Member

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Please provide a source that states that the photon is symmetrical in the same sense of the word as it is used in "symmetry breaking".

In what sense are the resulting particle asymmetrical?

False; electrons are not half-photons. Positrons are not half-photons. They are completely different types of particles.

Please define how you are using the word "cycle". Please define what you mean by "minimum mass generation".

The units don't match: the constant of Planck doesn't have units of energy, but energy time. Please correct your equations.

I see you still haven't managed to provide even a single source for your original statement. Why is that so difficult for you?

22. ### hansdaValued Senior Member

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From my equations $mr=\frac{4\hbar}{c}$ or $m=\frac{1}{r}\frac{4h}{2\pi c}$ .

Comparing these two equations of mass, we can write maximum radius $r$ will be $r=\frac{2c}{\pi}$ .

23. ### NotEinsteinValued Senior Member

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That last equation has a radius with units of length per time. A fine demonstration of "garbage in, garbage out".