What's the use?

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Morpheus22

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Hi.

0+1=1
1+1=11
11+1=111
111+1=1111
1111+1=11111
11111+1=111111
111111+1=1111111
1111111+1=11111111
11111111+1=111111111
111111111-1=11111111
11111111-1=1111111
1111111-1=111111
111111-1=11111
11111-1=1111
1111-1=111
111-1=11
11-1=1
1-1=0
0×1=0
1×1=1
1×11=1+1=11
1×111=1+1+1=111
1×1111=1+1+1+1=1111
1×11111=1+1+1+1+1=11111
1×111111=1+1+1+1+1+1=111111
1×1111111=1+1+1+1+1+1+1=1111111
1×11111111=1+1+1+1+1+1+1+1=11111111
1×111111111=1+1+1+1+1+1+1+1+1=111111111
11×1=11
11×11=11+11=1111
11×111=11+11+11=111111
11×1111=11+11+11+11=11111111
etc.
Now, if × = + THAT number of times...

is ÷ ...

Top×10

-

How many bottoms??

(Answer÷10)

e.g.
3÷9=
3+3+3+3+3+3+3+3+3+3=
30
-
9
=
21 (1)
-
9
= (2)
12
-
9
= (3)
3

This is a recurring answer.

So,

÷ answer by 10

3+3+3+3+3+3+3+3+3+3=
30
-
10
=
20
-
10
=
10
-
10
=
0

Answer=0.3'
 
River,

Good question!

What about a computer that programs itself??

Takes the first letter and puts it last.
Takes the second letter and puts that last
Takes the third letter ... etc.

You can try this yourself.

Name=Morpheus22
0<a<11
Name=Name+(Name(a)+10)

Name=Morpheus22
Name=Morpheus22M
Name=Morpheus22Mo
Name=Morpheus22Mor
Name=Morpheus22Morp
Name=Morpheus22Morph
Name=Morpheus22Morphe
Name=Morpheus22Morpheu
Name=Morpheus22Morpheus
Name=Morpheus22Morpheus2
Name=Morpheus22Morpheus22
 
Last edited:
1×10=1,2,3,4,5,6,7,8,9,10

1÷10=1,0.9,0.8,0.7,0.6,0.5,0.4,0.3,0.2,0.1

10÷0.1=

1=10
2=20
3=30
4=50
5=50
6=60
7=70
8=80
9=90
10=100

I'd practice sitting.
 
P.s. Could someone have created artificial intelligence and appeared within the darkness?

Could it happen again??

There are only 10 digital SYMBOLS:

0,1,2,3,4,5,6,7,8,9

0 is the 1st symbol and 9 the 10th.

Only 10 SYMBOLS.

1_0 is to RE-USE 1 then 0.

1_1 is to reuse 1 then 1.

1_2 is to reuse 1 then 2.

There are ONLY 4 OPERATORS:+,×,- and ÷.

(I=i) (<=less than)

Please read??

0<a
0<b
0<c
0<d
0<e
I(1)=((((a+b)×c)-d)÷e)
I(2)=((((a+b)×c)÷d)-e)
I(3)=((((a+b)-c)×d)÷e)
I(4)=((((a+b)-c)÷d)×e)
I(5)=((((a+b)÷c)×d)-e)
I(6)=((((a+b)÷c)-d)×e)
I(7)=((((a×b)+c)-d)÷e)
I(8)=((((a×b)+c)÷d)-e)
I(9)=((((a×b)-c)+d)÷e)
I(10)=((((a×b)-c)÷d)+e)
I(11)=((((a×b)÷c)+d)-e)
I(12)=((((a×b)÷c)-d)+e)
I(13)=((((a-b)+c)×d)÷e)
I(14)=((((a-b)+c)÷d)×e)
I(15)=((((a-b)×c)+d)÷e)
I(16)=((((a-b)×c)÷d)+e)
I(17)=((((a-b)÷c)+d)×e)
I(18)=((((a-b)÷c)×d)+e)
I(19)=((((a÷b)+c)×d)-e)
I(20)=((((a÷b)+c)-d)×e)
I(21)=((((a÷b)×c)+d)-e)
I(22)=((((a÷b)×c)-d)+e)
I(23)=((((a÷b)-c)+d)×e)
I(24)=((((a÷b)-c)×d)+e)
e<11
d<11
c<11
b<11
a<11

Would it EVER produce a.i.??
 
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