# SR Issue

Uhhh, check the preceding post. I would appreciate a retraction from you since your statement is false.

When you answer my many previous questions.
You have nothing chingy. If you did have anything, you would not be here.
You would be presenting a proper peer reviewed scientific paper.
Time and space are not absolute. While you continue to fight that, you'll continue to be wrong.
Live with it.

When you answer my many previous questions.
You have nothing chingy. If you did have anything, you would not be here.
You would be presenting a proper peer reviewed scientific paper.
Time and space are not absolute. While you continue to fight that, you'll continue to be wrong.
Live with it.

OK, can you prove the math is flawed?

OK, can you prove the math is flawed?

Why do you not accept that time and space are not absolute, despite observational evidence to 100% support that?
While you so stubbornly refuse to accept that, you will continue to always be in error, and applying misinterpretations as to what is really happening.
This has been shown to you, many times in many threads, that obviously you do not want to discuss.
That's OK, you shall run away again.

Light can be located at 2 different places given 2 different times.

Oh good, so we agree on this. The coordinates you gave in the OP say the light is located at two different places at two different times. But you are claiming the light should be located at the same place at two different times. Who should we believe, you or SR?

chinglu said:
Light can be located at 2 different places given 2 different times. But, this make no difference in the OP.

The OP notices that given C' and M are co-located, the primed frame light postulate places the light at $$(d',0,0,d'/c)$$. This is the only correct answer.
No it isn't; the correct answer includes which observer sees the event at $$(d',0,0,d'/c)$$, you have failed to specify this, so you aren't describing special relativity but something else.
However, given C' and M are co-located, the unprimed frame applies LP and LT and puts the light at primed frame $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$.
Again, the correct answer includes an observer, there are two of these, one for each frame. Which observer are you (intentionally not) referring to?
Therefore, LT gets the answer wrong.
No, chinglu got the answer wrong, or came to a completely false conclusion. You have, in fact, only demonstrated that, given a vague enough description of simultaneity, you can get all kinds of wrong answers.
Now, you are applying scales and all that, except LT takes all that into account and LT was used by the OP. So, that is a non-argument on your part.

Further, the OP proved the co-located event was unique since it was proven both frames agreed on the clock times at C' and M for the co-location event.
You haven't defined what you mean by "unique", and it is not something you find described in special relativity. There are no unique events, or times, or distances; what the hell are you doing introducing a term that has nothing to do with the physical reality? Wait, don't answer that.
So, LT simply gets the answer wrong. Remember, the job of LT is to translate into the other frame in terms of what it deems to be true. LT failed to do that.
What you seem to be incapable of comprehending is that each observer sees what they "deem to be true", and truth is not unique (how can it be?).
You are also getting the direction wrong in the logic. You are claiming the OP starts with two different primed frame times and claims light should be at the same place. That is not at all what is going on. The OP shows given the unique configuration of the coordinate systems where C' and M are co-located, SR claims light is at 2 different space-time coordinates in the primed frame and that is wrong. Given C' and M are co-located the light pulse is at one space-time coordinate.
SR doesn't "claim" anything, observers do.

It doesn't matter what a Lorentz transform "says" about where another observer moving relative to a stationary frame will see an event; the stationary observer sees the event in their own system of coordinates, the moving observer does too. It doesn't matter what they calculate about their relatively moving counterpart or how many transforms they try, they cannot, and will never, see what the other sees.
That's why your attempt at discrediting Einstein is so pathetic; you think the transform can "do something" or something . . .

You are a complete idiot.

Oh good, so we agree on this. The coordinates you gave in the OP say the light is located at two different places at two different times. But you are claiming the light should be located at the same place at two different times. Who should we believe, you or SR?

This is not what the OP says.

It says, given M and C' are co-located, the primed frame puts the light at $$(d',0,0,d'/c)$$.

Given M and C' are co-located, the unprimed frame puts the light at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$.

Einstein wrote,
It is essential to have time defined by means of stationary clocks in the stationary system, and the time now defined being appropriate to the stationary system we call it “the time of the stationary system.”
https://www.fourmilab.ch/etexts/einstein/specrel/www/

So, the OP is talking about one time and only one time, that being $$d'/c$$. If M and C' are co-located, then all clocks in the primed frame are $$d'/c$$ according to Einstein.

Now, given M and C' are co-located, where does LT claim the light is located? The answer is $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$. Well, that is false. First, given M and C' are co-located, there is only one time in the primed frame and that is $$d'/c$$. So, LT gets the time wrong.

LT is required to provide what is true in the primed frame, but it gets it wrong.

Further, the light is located at $$(d',0,0)$$. Yet LT says it is at $$(d'(1-v/c),0,0)$$. LT got that wrong also.

So, there is only one time in the primed frame with M and C' co-located and that time is $$d'/c$$ for all clocks in the primed frame.

LT is required to match the truth in the primed frame, but as we can all see it fails.

No it isn't; the correct answer includes which observer sees the event at $$(d',0,0,d'/c)$$, you have failed to specify this, so you aren't describing special relativity but something else.

Nope that is not the way SR works. All observers in the primed frame agree the light pulse is at $$(d',0,0,d'/c)$$ given M and C' and all observers in the primed frame agree their clocks read $$d'/c$$ with M and C' co-located.

Again, the correct answer includes an observer, there are two of these, one for each frame. Which observer are you (intentionally not) referring to?
No, chinglu got the answer wrong, or came to a completely false conclusion. You have, in fact, only demonstrated that, given a vague enough description of simultaneity, you can get all kinds of wrong answers.
Again you are confused. The OP with the primed frame is only concerned with primed frame observers. All agree on events in the primed frame and all have the same time on their clocks.

You somehow think primed frame observers disagree on events and that is completely false under SR.

So, it is OK that M has a different space and time coordinate from C' but it is not OK that LT gets the space-time location of the light flash in the primed frame wrong with M and C' are co-located.

You haven't defined what you mean by "unique", and it is not something you find described in special relativity. There are no unique events, or times, or distances; what the hell are you doing introducing a term that has nothing to do with the physical reality? Wait, don't answer that.
What you seem to be incapable of comprehending is that each observer sees what they "deem to be true", and truth is not unique (how can it be?).
SR doesn't "claim" anything, observers do.

I explained unique in the OP by proving each frame agrees on the same times on the clocks at C' and M given they are co-located. That means neither clock can have a different time with C' and M being co-located. Therefore, it is a unique event.

It doesn't matter what a Lorentz transform "says" about where another observer moving relative to a stationary frame will see an event; the stationary observer sees the event in their own system of coordinates, the moving observer does too. It doesn't matter what they calculate about their relatively moving counterpart or how many transforms they try, they cannot, and will never, see what the other sees.
That's why your attempt at discrediting Einstein is so pathetic; you think the transform can "do something" or something . . .

You are a complete idiot.

You completely got this wrong again.

Given C' and M are co-located, the light flash is at $$(d',0,0,d'/c)$$ period and no where else.

But, given C' and M are co-located, M claims it is at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$, which is false.

So LT got it wrong.

To all. It is easy to think about the problem this way.

Assume you are the C' observer in the primed frame. Given C' and M are co-located, you place the light pulse at $$(d',0,0,d'/c)$$. That is the correct answer period based on the light postulate. There are not 2 correct answers.

Now, at your common location, the M observer in the unprimed frame says you are full of it and your light is actually located at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$.

What would you say to M? You would tell that observer they are wrong. It is that simple.

LT gets the answer wrong so LT fails and contradicts the primed frame light postulate.

To all. It is easy to think about the problem this way.

Assume you are the C' observer in the primed frame. Given C' and M are co-located, you place the light pulse at $$(d',0,0,d'/c)$$. That is the correct answer period based on the light postulate. There are not 2 correct answers.

Now, at your common location, the M observer in the unprimed frame says you are full of it and your light is actually located at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$.

What would you say to M? You would tell that observer they are wrong. It is that simple.

LT gets the answer wrong so LT fails and contradicts the primed frame light postulate.

You couldn't be more wrong chinglu. Why you're allowed to 'stonewall' the scientific truth over 550 posts is outside my ability to comprehend.

chinglu said:
This is not what the OP says.

It says, given M and C' are co-located, the primed frame puts the light at $$(d',0,0,d'/c)$$.

Given M and C' are co-located, the unprimed frame puts the light at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$.
No, the unprimed frame has unprimed coordinates. You are committing the sin of mixing primed and unprimed frames, exactly what you were accused of on page 1.
Einstein wrote,
It is essential to have time defined by means of stationary clocks in the stationary system, and the time now defined being appropriate to the stationary system we call it “the time of the stationary system.”
https://www.fourmilab.ch/etexts/einstein/specrel/www/

So, the OP is talking about one time and only one time, that being $$d'/c$$. If M and C' are co-located, then all clocks in the primed frame are $$d'/c$$ according to Einstein.
How did you manage to work out that Einstein's reference to a stationary frame with stationary clocks is about a moving frame? This is something nobody else has ever done!
Now, given M and C' are co-located, where does LT claim the light is located?
Who cares? what matters is where the primed or unprimed frames "observe" this light.
The answer is $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$. Well, that is false. First, given M and C' are co-located, there is only one time in the primed frame and that is $$d'/c$$. So, LT gets the time wrong.

LT is required to provide what is true in the primed frame, but it gets it wrong.

Further, the light is located at $$(d',0,0)$$. Yet LT says it is at $$(d'(1-v/c),0,0)$$. LT got that wrong also.

So, there is only one time in the primed frame with M and C' co-located and that time is $$d'/c$$ for all clocks in the primed frame.

LT is required to match the truth in the primed frame, but as we can all see it fails.
No, you fail to see your error. You've been failing since the OP. Are you a failure, or what? Wait, don't answer that.

Here is your mistake, once again:
Assume you are the C' observer in the primed frame. Given C' and M are co-located, you place the light pulse at $$(d',0,0,d'/c)$$. That is the correct answer period based on the light postulate. There are not 2 correct answers.

Now, at your common location, the M observer in the unprimed frame says you are full of it and your light is actually located at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$.
The M observer doesn't see anything at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$, because those coordinates are in the primed frame, not the frame M is actually in.

You couldn't be more wrong chinglu. Why you're allowed to 'stonewall' the scientific truth over 550 posts is outside my ability to comprehend.

Then you will state why you think I am wrong and that way I can correct you.

No, the unprimed frame has unprimed coordinates. You are committing the sin of mixing primed and unprimed frames, exactly what you were accused of on page 1.
Well, when you translate from the unprimed frame to the primed frame and compare that to what the primed frame see, how exactly is that frame mixing?

You see, it is a comparison of primed to primed coordinates. That was the whole point of the OP. Perhaps you should re-read it.

How did you manage to work out that Einstein's reference to a stationary frame with stationary clocks is about a moving frame? This is something nobody else has ever done!
Who cares? what matters is where the primed or unprimed frames "observe" this light.
No, you fail to see your error. You've been failing since the OP. Are you a failure, or what? Wait, don't answer that.

1) I am operating only in the primed frame and what is true there. This is not the moving frame. Then, the moving frame (unprimed frame) gives its incorrect answer.

2) OK, you answer the OP. Where is the light in the primed frame if C' and M are co-located. Since you say you are right, answer this question.

Here is your mistake, once again:
The M observer doesn't see anything at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$, because those coordinates are in the primed frame, not the frame M is actually in.

Good, at least you have that right.

Where is the light in the primed frame if M and C' are co-located. M says it is at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$ and that is wrong and I have proven that. Prove it is right if you disagree.

chinglu said:
This is a thought experiment with strange results.

Assume M and M' are the origins of 2 frames and in the M' frame, there is an observer C' located at $$(\frac{-vd'}{c},0,0)$$ with $$d'>0$$.0

What it looks like you've tried to define is a single observer, C'. But the location of this observer is defined by a velocity, so M and M' have a relative velocity.
When M and M' are co-located, lightning strikes their command location.
This appears to be you implying that colocation of M and M' means that event is common to both frames. This is not true, however, and it can't possibly be true if observer C' has a velocity relative to M.
Here is the question, when C' and M are co-located, where is the lightning along the positive x-axis for both frame coordinate systems?

First, we have to know the time on the clocks at M and C' when they are co-located.

M frame calculations.
1) M clock - Apply LT $$x'=(x-vt)\gamma$$ with $$x'=\frac{-vd'}{c}$$ and $$x=0$$. Then, solve for t so $$t=\frac{d'}{c\gamma}$$
2) C' clock. Apply LT $$t'=(t-vx/c^2)\gamma$$ with $$t=\frac{d'}{c\gamma}$$ and $$x=0$$. Then $$t'=\frac{d'}{c}$$

M' frame calculations
1) C' clock - Apply LT $$x=(x'+vt')\gamma$$ with $$x'=\frac{-vd'}{c}$$ and $$x=0$$ and solve for t'. Then, $$t'=\frac{d'}{c}$$.
2) M clock - apply LT $$t=(t'+vx'/c^2)\gamma$$ with $$t'=\frac{d'}{c}$$ and $$x'=\frac{-vd'}{c}$$. Then, $$t=\frac{d'}{c\gamma}$$.

So far so good. SR agrees in the calculations of both frames the times on the clocks at C' and M when the two are co-located.
No, observers located at M and M' (if they are there) will be able to calculate all of that if the relative velocity between frames is known.

Note though, how you appear to imply that the time on the clock at M can be defined in terms of d', as if d' is a common distance for M and M'.
You should have an equation that relates d' to units of distance in frame M; you intentionally leave this step out because it makes it more confused and that's what you really want. you want to show everyone how confusing Einstein's theory is when you leave out some critical details. You want us to believe that colocation is some kind of unique event that means an axis is shared. That idea is obviously crazy, and so, I guess, are you.
Now we ask the question where is the lightning along the positive x-axis when C' and M are co-located?

M frame calculations for the space-time coordinates of the lightning along the positive x-axis when C' and M are co-located.

1) M coordinate system location. Since the time on the M clock is $$t=\frac{d'}{c\gamma}$$, apply the light postulate $$x=ct$$. So, $$x=d'/\gamma$$.
Thus, the space-time coordinate of the lightning in the M coordinate system is $$(d'/\gamma,0,0,\frac{d'}{c\gamma})$$
2) M' coordinate system location. Apply LT $$x'=(x-vt)\gamma$$ and $$t'=(t-vx/c^2)\gamma$$ with $$x=d'/\gamma$$ and $$t=\frac{d'}{c\gamma}$$. Then, $$x'=d'(1-v/c)$$ and $$x'=d'(1-v/c)/c$$.
Thus, the space-time coordinate of the lightning in the M' coordinate system is $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$
You say this is the M frame solutions, but you've added solutions for M', why? Doesn't that contradict what we as observers actually do? You then repeat this procedure (adding the other frame's solutions) below.
M' frame calculations for the space-time coordinates of the lightning along the positive x-axis when C' and M are co-located.
1) M' coordinate system location. The time on the clock at C' is $$t'=\frac{d'}{c}$$. The lightning struck at M', so apply the light postulate from M', which is also the origin of the primed frame $$x'=ct'$$, with $$t'=\frac{d'}{c}$$. Then, $$x'=d'$$.
Thus, the space-time coordinate of the lightning in the M' coordinate system is $$(d',0,0,d'/c)$$
2) M coordinate system location. Apply LT $$x=(x'+vt')\gamma$$ and $$t=(t'+vx'/c^2)\gamma$$ with $$x'=d'$$ and $$t'=\frac{d'}{c}$$. Then, $$x=d'\gamma(1+v/c)$$ and $$t=d'\gamma(1+v/c)/c$$.
Thus, the space-time coordinate of the lightning in the M coordinate system is $$(d'\gamma(1+v/c),0,0,d'\gamma(1+v/c)/c)$$.
You say the M' frame has solutions for itself and for M. This is confused, misleading rubbish.

Conclusions:

When C' and M are co-located, SR claims the lightning is located at M frame space-time coordinates of $$(d'/\gamma,0,0,\frac{d'}{c\gamma})$$ and $$(d'\gamma(1+v/c),0,0,d'\gamma(1+v/c)/c)$$.

When C' and M are co-located, SR claims the lightning is located at M' frame space-time coordinates of $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$ and $$(d',0,0,d'/c)$$.

Therefore, if these calculations are correct, then SR claims when M and C' are co-located, one lightning strike is located at 2 different positions along the positive x-axis in both coordinate systems, which of course is inconsistent with nature.

So, where is the error in the calculations?
Where is the logic in your extremely vague and misleading definition of a "problem"? When are you going to stop pushing this piece of shit up the hill?

What it looks like you've tried to define is a single observer, C'. But the location of this observer is defined by a velocity, so M and M' have a relative velocity.
Prove this with the Winstein paper.

This appears to be you implying that colocation of M and M' means that event is common to both frames. This is not true, however, and it can't possibly be true if observer C' has a velocity relative to M.
No, observers located at M and M' (if they are there) will be able to calculate all of that if the relative velocity between frames is known.

You are refuting Einstein.

At the time t=t'=0, when the origin of the co-ordinates is common to the two systems
https://www.fourmilab.ch/etexts/einstein/specrel/www/

Note though, how you appear to imply that the time on the clock at M can be defined in terms of d', as if d' is a common distance for M and M'.
You should have an equation that relates d' to units of distance in frame M; you intentionally leave this step out because it makes it more confused and that's what you really want. you want to show everyone how confusing Einstein's theory is when you leave out some critical details. You want us to believe that colocation is some kind of unique event that means an axis is shared. That idea is obviously crazy, and so, I guess, are you.
You say this is the M frame solutions, but you've added solutions for M', why? Doesn't that contradict what we as observers actually do? You then repeat this procedure (adding the other frame's solutions) below. You say the M' frame has solutions for itself and for M. This is confused, misleading rubbish.

I simply used LT for my calculations. Is LT wrong?
Where is the logic in your extremely vague and misleading definition of a "problem"? When are you going to stop pushing this piece of shit up the hill?

I can't understand why it threatens you to ask where is the light in the primed frame. Can you explain that?

Further, can you explain given M and C' are co-located why the unprimed frame gets the position of the light in the primed frame wrong?

How do you reconcile this:
Albert Einstein said:
At the time t=t'=0, when the origin of the co-ordinates is common to the two systems
chinglu said:
First, we have to know the time on the clocks at M and C' when they are co-located.

M frame calculations.
1) M clock - Apply LT $$x'=(x-vt)\gamma$$ with $$x'=\frac{-vd'}{c}$$ and $$x=0$$. Then, solve for t so $$t=\frac{d'}{c\gamma}$$
2) C' clock. Apply LT $$t'=(t-vx/c^2)\gamma$$ with $$t=\frac{d'}{c\gamma}$$ and $$x=0$$. Then $$t'=\frac{d'}{c}$$

M' frame calculations
1) C' clock - Apply LT $$x=(x'+vt')\gamma$$ with $$x'=\frac{-vd'}{c}$$ and $$x=0$$ and solve for t'. Then, $$t'=\frac{d'}{c}$$.
2) M clock - apply LT $$t=(t'+vx'/c^2)\gamma$$ with $$t'=\frac{d'}{c}$$ and $$x'=\frac{-vd'}{c}$$. Then, $$t=\frac{d'}{c\gamma}$$
where you have something other than what Einstein specifies in his paper? You have nonzero values for t and t', but they're supposed to be zero at colocation.

You can see why you've done this and why you use d' exclusively: it's confusing, and it has an immediate problem, which is that t is not defined in the stationary system, but rather in the moving system.

To all. It is easy to think about the problem this way.

Assume you are the C' observer in the primed frame. Given C' and M are co-located, you place the light pulse at $$(d',0,0,d'/c)$$. That is the correct answer period based on the light postulate. There are not 2 correct answers.

Now, at your common location, the M observer in the unprimed frame says you are full of it and your light is actually located at $$(d'(1-v/c),0,0,d'(1-v/c)/c)$$.

What would you say to M? You would tell that observer they are wrong. It is that simple.

LT gets the answer wrong so LT fails and contradicts the primed frame light postulate.

Your mistake is in thinking that M does not understand relativity. If M understands relativity, then he will know that the location where he places the light at the time when C' and M are co-located is not the place where C' would place the light. All M would have to do is look at the co-located C' clock and see that it displays $$t'=d'/c$$ and he will know that C' would place the light at $$x'=ct'=cd'/c=d'$$.

And the situation is reciprocal. If C' understands relativity then he will know that the location where he places the light at the time when C' and M are co-located is not the place where M would place the light. All C' would have to do is look at the co-located M clock and see that it displays $$t=d'/c\gamma$$ and he will know that M would place the light at $$x=ct=cd'/c\gamma=d'/\gamma$$. Now it is true that the event $$(x,y,z,t)=(d'/\gamma,0,0,d'/c\gamma)$$ transforms to the primed frame as $$(x',y',z',t')=(d'(1-v/c),0,0,d'(1-v/c)/c)$$ but the time coordinate $$t'=d'(1-v/c)/c$$ does not match the time when C' and M are co-located, which is $$t'=d'/c$$. So relativity is telling you straight to your face that event is not simultaneous with the co-location of C' and M according to the primed frame. Thus, the only way to make relativity get the 'wrong' answer is to totally misunderstand what relativity is telling you, as you, chinglu, have been doing all along. Next!

With this definition:
chinglu said:
This is a thought experiment with strange results.

Assume M and M' are the origins of 2 frames and in the M' frame, there is an observer C' located at $$(\frac{-vd'}{c},0,0)$$ with $$d'>0$$.0

chinglu can apply a bit of mathematical trickery: without ever defining d', or which observer measures d', and then defining t and t' in terms of d', he can produce something that appears to contradict "nature".

Of course, it doesn't matter too much what d' is (as Neddy just showed, and others have shown this), as long as you stick to the "rules" of frame dependence, something chinglu wants us to believe is unnecessary because, according to him, two frames can share a common x-axis (we are supposed to interpret "share" and "common" freely, since neither terms are defined by him anywhere).

He is just trying to pull the fast one.

With this definition:

chinglu can apply a bit of mathematical trickery: without ever defining d', or which observer measures d', and then defining t and t' in terms of d', he can produce something that appears to contradict "nature".

Of course, it doesn't matter too much what d' is (as Neddy just showed, and others have shown this), as long as you stick to the "rules" of frame dependence, something chinglu wants us to believe is unnecessary because, according to him, two frames can share a common x-axis (we are supposed to interpret "share" and "common" freely, since neither terms are defined by him anywhere).

He is just trying to pull the fast one.

Pull a 'slow one' is more appropriate to his scholarship on this subject. I enjoyed reading the posts which demonstrate chinglus complete lack of scholarship and intellectual honesty during his presentation. Otherwise ?

How do you reconcile this:
with your calculations: where you have something other than what Einstein specifies in his paper? You have nonzero values for t and t', but they're supposed to be zero at colocation.

You can see why you've done this and why you use d' exclusively: it's confusing, and it has an immediate problem, which is that t is not defined in the stationary system, but rather in the moving system.

Well, if you have x and t, you can use :T acquire x' and t' of the corresponding observer and clock time at that event.

That is how I reconcile it. It is simple SR.

Your mistake is in thinking that M does not understand relativity. If M understands relativity, then he will know that the location where he places the light at the time when C' and M are co-located is not the place where C' would place the light. All M would have to do is look at the co-located C' clock and see that it displays $$t'=d'/c$$ and he will know that C' would place the light at $$x'=ct'=cd'/c=d'$$.

And the situation is reciprocal. If C' understands relativity then he will know that the location where he places the light at the time when C' and M are co-located is not the place where M would place the light. All C' would have to do is look at the co-located M clock and see that it displays $$t=d'/c\gamma$$ and he will know that M would place the light at $$x=ct=cd'/c\gamma=d'/\gamma$$. Now it is true that the event $$(x,y,z,t)=(d'/\gamma,0,0,d'/c\gamma)$$ transforms to the primed frame as $$(x',y',z',t')=(d'(1-v/c),0,0,d'(1-v/c)/c)$$ but the time coordinate $$t'=d'(1-v/c)/c$$ does not match the time when C' and M are co-located, which is $$t'=d'/c$$. So relativity is telling you straight to your face that event is not simultaneous with the co-location of C' and M according to the primed frame. Thus, the only way to make relativity get the 'wrong' answer is to totally misunderstand what relativity is telling you, as you, chinglu, have been doing all along. Next!

Now, what you are saying here is that LT is completely useless and fails to give the correct answer. Try to keep in mind, LT is part of SR.

Keep in mind, we are only talking about primed frame coordinates. So you are confessing that M will not place the light pulse at the same location in the primed frame that the primed frame light postulate places it given M and C' are co-located.

Therefore, LT contradicts the light postulate in the primed frame.