Mohsen Ezz El-Din Al-Bakr
Registered Member
Personal Hypothesis: The Finite Energy of the Big Bang and the Cosmic Selection of Universes .....
We know that Newton’s law states that a body remains in its state of rest or uniform motion unless acted upon by an external force.
If the resistive force on a moving body is zero, then its velocity remains constant:
v = constant or v(t) = v₀
Position, velocity, and acceleration can be expressed as follows:
rᵢ(t), vᵢ(t) = drᵢ/dt, aᵢ(t) = dvᵢ/dt
If the energy required to lift a body to a certain height is the same as the energy released when it falls, and if the energy required to move a body equals the energy needed to stop it, and since work equals force multiplied by distance, then any motion over a given distance requires a specific amount of energy:
W = F × d, E₍lift₎ = E₍fall₎, E₍motion₎ = E₍stop₎
The interaction laws between masses in the universe can generally be written as:
Fᵢ = mᵢ aᵢ = Σ_{j ≠ i} G (mᵢ mⱼ (rⱼ - rᵢ)/|rⱼ - rᵢ|³) + F₍spacetime₎
But if a body never stops and continues moving infinitely, this would imply that the energy which initially set it in motion was infinite, which is illogical.
Even if we accept that all bodies in the universe have been moving since the Big Bang, their orbits can be viewed as folded distances, with each cycle adding to the total distance traveled:
d₍total₎ = Σ_{i=1}^{n} dᵢ, where each cycle is precisely counted
From this, it follows that the Big Bang was not of infinite energy, but of immense finite energy. Let us assume the initial energy is E₀, and the initial momentum of the universe is:
p₍initial₎ = m₍universe₎ × v₀
Over time, as matter condenses into stars, planets, and black holes, part of the energy becomes stored within masses, decreasing the remaining share that fuels cosmic motion. As time advances, the residual force of the initial explosion decreases until it reaches zero at the universe’s end:
E₍remaining₎(t) = E₀ - Σ_{i=1}^{N₍masses₎} E₍stored₎^{(i)}(t), lim_{t→t₍end of universe₎} E₍remaining₎(t) = 0
And each mass stores its rest, kinetic, and nuclear energy:
E₍stored₎^{(i)} = mᵢ c² + E₍kinetic₎^{(i)} + E₍nuclear₎^{(i)}
Through this accounting, one could estimate the initial energy, measure the reduction caused by matter storage (including black holes), and then derive the total distance and time expected for the end of the universe:
E₀ → compute Σ_i E₍stored₎^{(i)} → d₍total₎, t₍end of universe₎
Even black holes are finite in mass and density:
M₍black hole₎ ≤ M₍maximum₎, ρ₍black hole₎ ≤ ρ₍maximum₎
A clear example is stars, whose lifespans depend on their mass, with some never reaching the threshold for nuclear ignition, remaining as giant planets such as Jupiter:
t₍stars₎ ~ f(M₍stellar mass₎), M₍failed stars₎ < M₍ignition threshold₎
The motion of galaxies and stars is limited by the cosmic work that the initial energy can accomplish. Their travel distances are enormous but ultimately finite, as determined by the relation of remaining energy:
E₍remaining₎ = E₍initial₎ - M₍matter₎ c²
Wᵢ(t) = ∫₀^t Fᵢ · drᵢ ≤ E₍remaining₎(t)
d₍max₎^{(i)} = ∫₀^{t₍end of universe₎} |vᵢ(t)| dt ≤ E₍remaining₎(t)/Fᵢ
Thus, the physical constants we believe to be “designed” are merely a coincidence of the initial conditions of our universe’s explosion. They depend on the initial driver and are not necessarily the same for other universes. Cosmological lifetimes may range from fractions of a second to millions or billions of years, with each universe’s survival determined by its starting conditions, in accordance with the principle of cosmic natural selection:
t₍universe lifespan₎ ~ f(E₀, Σ_i mᵢ, Σ_i d₍max₎^{(i)})
Therefore, our current universe can be seen as one possible outcome among a chain of cosmic explosions that may succeed or fail depending on the in
itial energy and conditions. ...... .. Best regards,
We know that Newton’s law states that a body remains in its state of rest or uniform motion unless acted upon by an external force.
If the resistive force on a moving body is zero, then its velocity remains constant:
v = constant or v(t) = v₀
Position, velocity, and acceleration can be expressed as follows:
rᵢ(t), vᵢ(t) = drᵢ/dt, aᵢ(t) = dvᵢ/dt
If the energy required to lift a body to a certain height is the same as the energy released when it falls, and if the energy required to move a body equals the energy needed to stop it, and since work equals force multiplied by distance, then any motion over a given distance requires a specific amount of energy:
W = F × d, E₍lift₎ = E₍fall₎, E₍motion₎ = E₍stop₎
The interaction laws between masses in the universe can generally be written as:
Fᵢ = mᵢ aᵢ = Σ_{j ≠ i} G (mᵢ mⱼ (rⱼ - rᵢ)/|rⱼ - rᵢ|³) + F₍spacetime₎
But if a body never stops and continues moving infinitely, this would imply that the energy which initially set it in motion was infinite, which is illogical.
Even if we accept that all bodies in the universe have been moving since the Big Bang, their orbits can be viewed as folded distances, with each cycle adding to the total distance traveled:
d₍total₎ = Σ_{i=1}^{n} dᵢ, where each cycle is precisely counted
From this, it follows that the Big Bang was not of infinite energy, but of immense finite energy. Let us assume the initial energy is E₀, and the initial momentum of the universe is:
p₍initial₎ = m₍universe₎ × v₀
Over time, as matter condenses into stars, planets, and black holes, part of the energy becomes stored within masses, decreasing the remaining share that fuels cosmic motion. As time advances, the residual force of the initial explosion decreases until it reaches zero at the universe’s end:
E₍remaining₎(t) = E₀ - Σ_{i=1}^{N₍masses₎} E₍stored₎^{(i)}(t), lim_{t→t₍end of universe₎} E₍remaining₎(t) = 0
And each mass stores its rest, kinetic, and nuclear energy:
E₍stored₎^{(i)} = mᵢ c² + E₍kinetic₎^{(i)} + E₍nuclear₎^{(i)}
Through this accounting, one could estimate the initial energy, measure the reduction caused by matter storage (including black holes), and then derive the total distance and time expected for the end of the universe:
E₀ → compute Σ_i E₍stored₎^{(i)} → d₍total₎, t₍end of universe₎
Even black holes are finite in mass and density:
M₍black hole₎ ≤ M₍maximum₎, ρ₍black hole₎ ≤ ρ₍maximum₎
A clear example is stars, whose lifespans depend on their mass, with some never reaching the threshold for nuclear ignition, remaining as giant planets such as Jupiter:
t₍stars₎ ~ f(M₍stellar mass₎), M₍failed stars₎ < M₍ignition threshold₎
The motion of galaxies and stars is limited by the cosmic work that the initial energy can accomplish. Their travel distances are enormous but ultimately finite, as determined by the relation of remaining energy:
E₍remaining₎ = E₍initial₎ - M₍matter₎ c²
Wᵢ(t) = ∫₀^t Fᵢ · drᵢ ≤ E₍remaining₎(t)
d₍max₎^{(i)} = ∫₀^{t₍end of universe₎} |vᵢ(t)| dt ≤ E₍remaining₎(t)/Fᵢ
Thus, the physical constants we believe to be “designed” are merely a coincidence of the initial conditions of our universe’s explosion. They depend on the initial driver and are not necessarily the same for other universes. Cosmological lifetimes may range from fractions of a second to millions or billions of years, with each universe’s survival determined by its starting conditions, in accordance with the principle of cosmic natural selection:
t₍universe lifespan₎ ~ f(E₀, Σ_i mᵢ, Σ_i d₍max₎^{(i)})
Therefore, our current universe can be seen as one possible outcome among a chain of cosmic explosions that may succeed or fail depending on the in
itial energy and conditions. ...... .. Best regards,
