msbiljanica
Registered Senior Member
I believe that today's mathematics is limited, so I came up with a mathematics that consists of one axiom, everything else is obtained through proofs, see the attachment
adding or joining , as performed
R a+b=c same as now, combined numbers 222+33=2253, when they are the same along (gap) they are joined, here 2 and 3, we get 5
R[sup]2[/sup]
here there is an operation function (the same applies to other R[sup]n[/sup]) , 1(R[sub]2[/sub]) 3+[sub]1[/sub]4=(3,4[sub]2[/sub]) , 2(R,R[sub]2[/sub]) 3[sub]+2[/sub]4={7 ,(3,4[sub]2[/sub])} , 3(R-R[sub]2[/sub]) 3+[sub]3[/sub]4= (7, 4[sub]2)[/sub]},4(R,R[sub]2[/sub],R-R[sub]2[/sub]) , 3+[sub]4[/sub] 4={7,(3,4[sub]2[/sub]) , (7.4[sub]2[/sub])}
(2,3[sub]2[/sub])+(3.3[sub]2[/sub])=(5 .6[sub]2[/sub])
R[sup]3[/sup] 5(R,R[sub]2[/sub] , R[sub]3[/sub]) , 3+[sub]5[/sub]4={7 , (3 ,4[sub]2[/sub] ), (3 , 0 , 4[sub]3[/sub])} , 6(R-R[sub]2[/sub], R[sub]3[/sub]) , 3+[sub]6[/sub]4={( 7 , 4[sub]2[/sub]) , ( 3 , 0 , 4[sub]3[/sub]} , 7(R, R[sub]2[/sub]-R[sub]3[/sub]) , ...so on
latex doesn't work ,
adding or joining , as performed
R a+b=c same as now, combined numbers 222+33=2253, when they are the same along (gap) they are joined, here 2 and 3, we get 5
R[sup]2[/sup]
here there is an operation function (the same applies to other R[sup]n[/sup]) , 1(R[sub]2[/sub]) 3+[sub]1[/sub]4=(3,4[sub]2[/sub]) , 2(R,R[sub]2[/sub]) 3[sub]+2[/sub]4={7 ,(3,4[sub]2[/sub])} , 3(R-R[sub]2[/sub]) 3+[sub]3[/sub]4= (7, 4[sub]2)[/sub]},4(R,R[sub]2[/sub],R-R[sub]2[/sub]) , 3+[sub]4[/sub] 4={7,(3,4[sub]2[/sub]) , (7.4[sub]2[/sub])}
(2,3[sub]2[/sub])+(3.3[sub]2[/sub])=(5 .6[sub]2[/sub])
R[sup]3[/sup] 5(R,R[sub]2[/sub] , R[sub]3[/sub]) , 3+[sub]5[/sub]4={7 , (3 ,4[sub]2[/sub] ), (3 , 0 , 4[sub]3[/sub])} , 6(R-R[sub]2[/sub], R[sub]3[/sub]) , 3+[sub]6[/sub]4={( 7 , 4[sub]2[/sub]) , ( 3 , 0 , 4[sub]3[/sub]} , 7(R, R[sub]2[/sub]-R[sub]3[/sub]) , ...so on
latex doesn't work ,