#### TIMO MOILANEN

**Registered Member**

Amount of dq integral -RtoR for r=-1to1 , a=arccosR ,dq =2pi R*sina The force F =Sigma dq |Rcosa| /(r+Rcosa)^2 ,r/R=p , dividing with pi to obtain average and so on. Shortly I get INT -1 to1 of 2|R|(1+R^2)^0.5 /(p+R)^2 . Is=4(((p^2-1)^.5*(2P^2-1)*arcsin(1/p) )-2p^2+2)/(P^2-1) . This multiplied with p^2 goes to 4/3 for p=>infinity. For "Coloumbs force law I get F=4/3Q^2/r^2*const. For constant I put mass of proton Mp*c^2 So I have F=K*Q^2/r^2 , where K=4/(3Mp*c^2) . Force per mass(in nuc. units) of proton. I use index i to separate "invented" from official . Ki=8.9*10^9 Nm^2/Ai^2 and electric constant E0i =3*Mp*c^2/(16pi)= 8.9*10^-12 Fi/m , magnetic constant (µ0i=16pi/(3Mp*c^4) =1.25*10^-6 N/Ai^2 . Planck constant is not per mass and removing 4pi to , but electron fall in (kin+pot energy and photon take both energies with it =>*4). hi=16/3c^4 =6.6*10^-34 Js Fitting these into formula e^2=2aE0hc give fine structure coefficient get value of and "look like a fit" to be ai=2*(3/16pi)^2 =7.12*10^-3 =1/140 . Elementary charge become ei= 3/8*(Mp/pi^3*c)^.5 =1.58*10^-19 Ci . But ai should also apply for ei so ei = 2ai/c^2 =4/c^2*(3/16pi)^2 .

As a sum up putting in all "assumptions" ei^2 = 2*ai*E0i*hi*c become : (2*2*(3/(16pi))^2/c^2)^2 = 2*2(3/16pi)^2*3Mp*c^2/(16pi)*16/(3*c^4)*c and from this Mp=9/(64pi*c^3)=1.66*10^-27 kg. I read that a physical constant can not be anything even or such , and by my opinion it can't if you calculate and measure with a random unit , in this case the SI ampere. Since codata e =1.602176634*10^-19 C and I get ei=1.584968575*10^-19 Ci , the metric ampere Ai=ei/e =0.989259574 A(SI)

As the mass of a proton is a result of calculations

__the only input are 4/3 from integral pi and c .__

Some constants: Ki =4/3*Mp*c^2= 8929903726 Ci

E0i=3*Mp*c^2/(16pi)= 8.9113470857 *10^-12 Fi/m

µ0i=1/(e0i*c^2)= 1.2485767251*10^-6 N/Ai

ei=2ai/c^2 = 1.585336228 *10^-19 Ci

hi=16/(3c^4)= 6.602614118592*10^-34 Js

Rki=hi/ei^2= 26270.7909 (ohm)i and so on

A value for mass of proton 9/(64pi*c^3)= 1.661309521*10^-27kg

Of course this work only with the metric values , Vi= 1/ 0.989259572 V(SI) and so on.

Now this looks easy but these affiliations was "not easy" to find and the process would fill a little book.

There are many particulars on a iron lever 1.10-20 Timo Moilanen