No, that's incorrect. Pt#1 in the quote is true for the entire range of density from arbitrarily small value to very high nuclear level density.
I thought you had understood this after post #107. I will attempt again.
The density of an object of mass M, under uniformity assumption,
Right here you assume constant density, which is an unrealistic proposition for stellar objects. In fact, neutron stars specifically do not follow this density distribution.
when 'just at EH' is dependent on (c^6)/(G^3*M^2), this can be any value depending on M and need not be constant. Keeping this aspect in mind if you refer to my post#107, you will come to conclusion that pt#1 in quote is true for almost the entire range of density.
The same problem exists in post #107: you assume a uniform density, which a neutron star doesn't have. The calculation that
I did in post #100 (because you were unable/unwilling to) does indeed show that it is possible to have the event horizon on the outer surface of such an object, but it also signals such an object is unstable (any addition to the mass, and the entire thing starts collapsing), which is problematic, because that will happen very quickly. And it's up to you to show that neutron stars have a uniform density.
This again is incorrect. As shown above for any density value
That is for a
constant density value, which is not generally the case for celestial objects.
when the object is at its EH, the inner fractions will not be under their respective EHs, so a photon can at least attempt to move away till it encounters the point wherein it falls beneath the EH.
Look, if you want to start discussing this non-existent uniform density object, that's fine, but I thought you were talking about neutron stars.
(For Neutron Star) Please calculate the value of inward gravitational pressure in GR without invoking gravitational force or gravitational potential energy.
Pl show any reference which shows gravity countering NDP, without invoking these concepts.
Why? How is this related to what I told you? What would this add?
So, please give quantitative value, beyond which escape velocity becomes well defined thing.
When GR reduces to Newtonian gravity:
https://en.wikipedia.org/wiki/Newtonian_limit
Following the source:
https://arxiv.org/pdf/gr-qc/9712019.pdf Equation 4.10 and 4.13
This is basic GR stuff; if you're working with event horizons, you should know this.
I am sure you will understand that approximation cannot create a new set of "now applicable" parameters. For example as you are saying PE and escape velocity is not there in GR, then your invoking these parameters in "approximation of GR" is not justifiable. Approximation gives you mathematical simplification, it does not give you new set of physical parameters.
They are not parameters, but even if they were, your argument doesn't follow. GUT falls apart into several separate theories, each with their own parameters, but some of these can be expressed in GUT-parameters. In other words: the approximated theories contain parameters that are fully described by the full GUT. But here, they are not even parameters, there are values/variables. Under the Newtonian limit these variables work well enough to use them. In fact, you can derive this by starting with GR, taking the Newtonian limit, deriving Newton's laws of motion, and then proving that the escape velocity follows from that.
So under the Newtonian limit, escape velocity is well-defined.
No, there is no absence of argument from my side. It is just that you are not able to cross the bar, and repeating "its not there" argument.
And you haven't shown it to be there, not even once.
1. Take for example in GR perspective, the earth is moving in a straightline around the sun, but it never leaves the sun. How can it be made to leave the sun to infinity?
Simple. Start with a good metric, and derive the equations of motion of a stable orbit:
https://en.wikipedia.org/wiki/Schwarzschild_geodesics#Orbits_of_test_particles
Now my relativistic orbital mechanics aren't too good, but I think you'll find that as you increase the specific relative angular momentum, so does the radius of the orbit.
2. Again in GR perspective, a bullet is fired upward with some momentum from earth's (or say even Neutron star's, so that you do not invoke weak gravity argument), it falls back. How much momentum should we impart to this bullet so that it does not fall back and goes to infinity.
Why do I have to do
your homework? Actually, I don't have to do it either, I just have to look it up:
http://astro.cornell.edu/academics/courses/a290/lectures/A2290_36 (Free Fall).pdf
Up to and including slide 11. A particle escaping to infinity is simply the reverse process of a particle falling in (since we have no time-dependent in our metric). So just calculate what velocity the infalling particle would have at the coordinates where you fired the bullet, and that's your escape velocity.
But see how it depends on the metric, many calculations, etc.? It's not fundamental in GR at all!
[These are well defined issues in Physics, so please respond in GR without hand waving,
I have done as you asked. Will you now please also do as I asked?
this will give you an idea that the concept of escape velocity or binding energy is fundamental to Physics,
Wrong, as I have been saying, it does exactly the opposite.
so making a claim that it is not fundamental or irrelevant or meaningless in GR is your choice of words.]
I've just shown (you know, with proof) that they are indeed not fundamental. I've never claimed that they are irrelevant or meaningless in general; they are only useful (relevant, meaningful) in specific circumstances, such as environments where the Newtonian limit is a good approximation.
Now, please show me
your answers to
your questions, where you demonstrate that I'm wrong about all of this.