# Yang–Mills and Mass Gap

Discussion in 'Physics & Math' started by Thales, Nov 29, 2017.

1. ### hansdaValued Senior Member

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In particle photon, E-field and M-field are sine waves which are symmetrical relative to its line of propagation.

If the symmetry is broken, the two particles are asymmetrical.

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3. ### NotEinsteinValued Senior Member

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You have just proven you have utterly no idea what you are talking about. First of all, that's indeed exactly not the symmetry meant in the term symmetry breaking. More importantly, photons are the result of symmetry breaking: https://en.wikipedia.org/wiki/Spontaneous_symmetry_breaking#Higgs_mechanism
Remember that Higgs mechanism you mentioned? Well, there is it.

So, according to you photons are both symmetrical (because their EM waves are) and asymmetrical (because they are the result of symmetry breaking). You, sir, are being silly.

(See above.)

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5. ### hansdaValued Senior Member

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Ok. Here $r=\frac{2c}{\pi f}$

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7. ### NotEinsteinValued Senior Member

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Can you please re-post the entire derivation, but with this fix? Where did the error come from? Which formulae are affected?

8. ### hansdaValued Senior Member

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Can you quote the statement, where it is mentioned E-M waves generate from symmetry breaking. I am not able to find that line.

9. ### hansdaValued Senior Member

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For c and f, you put the same unit of time and put numerical value of f as 1.

10. ### NotEinsteinValued Senior Member

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Funny, I thought you were an expert in these things, throwing terms around like you did?

But I'll point it out to your explicitly:
Remember that the electromagnetic force is what gives rise to photons.

Oh look, it says it explicitly! Photons are the result of symmetry breaking!

11. ### NotEinsteinValued Senior Member

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This is nonsensical: frequency can't always have the numerical value of one. Take two objects. One rotates twice as fast as the other. Let's say one makes a full rotation once an hour, the other twice an hour. Yet, both have a $f$ of $1$. Question: What is the used unit of time?

12. ### hansdaValued Senior Member

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In pair production also you get photon particles along with massive particles.

13. ### NotEinsteinValued Senior Member

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True, but that has nothing to do with symmetry breaking, so I don't know why you are bringing that up?

14. ### hansdaValued Senior Member

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I am talking about minimum frequency.

15. ### hansdaValued Senior Member

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So in Higgs mechanism also you can get photon.

16. ### NotEinsteinValued Senior Member

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You were talking about "cycles" (which you haven't defined), and minimum mass generation (which you haven't defined). Then you were talking about pair production, confused that with symmetry breaking, mixed up different types of symmetries, and now you're jumping back to the incoherent idea of a "minimum frequency". Care to actually explain any of it?

Sure, but that doesn't mean the two processes are the same. You do understand that there can be multiple ways to get to the same point, right?

17. ### hansdaValued Senior Member

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Mass generation basically is symmetry breaking.

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