Why is there a problem with Quantum Gravity?

S

Suomy Nona

Registered Member
Why is there a problem with Quantum Gravity?

This may be a naive question but I'll go ahead and ask it.

In Classical Mechanics it seems trivial to produce gravity field values based on the electrostatic field, please see attached image.

I concede that there is a big difference between classical electrostatics and quantum dynamic systems but if Quantum Mechanics can produce highly accurate electric field values; why can't it deal with gravity?

After all , it is well known that Newton's and Gauss' law are mathematically equivalent, and I believe that quantum mechanics already uses Gauss' law within the Hamiltonian.

899iop


Backup link if image doesn't load. http://www.sendspace.com/pro/dl/899iop
 
Russ_Watters said:
What does it do?
Click to expand...

It animated gif file shows a simple way of calculating the gravity field from the electrostatic field. Basically just moving some summations around from Jackson. My follow up question is that if quantum mechanics does electric field calculations so well why can't it do gravity? Newtons law and Coulombs law are very similar and quantum already uses Coulombs law for electric gradient...
 
Suomy Nona said:
It animated gif file shows a simple way of calculating the gravity field from the electrostatic field.
Click to expand...
Show me. Calculate soemthing useful from it. Like the weight of an object on Earth or the force between the Earth and moon.
 
Russ_Watters said:
Show me. Calculate soemthing useful from it. Like the weight of an object on Earth or the force between the Earth and moon.
Click to expand...

I believe that I can do what you ask, mainly I need to know the number of electrons, protons, neutrons on earth and the moon in order to produce meaningful numbers. we know that the net electric field of earth is zero but clearly we have a gravity field; thus the positive and negative electric fields (using my method) can not be zero.

Anyway, please give me a few days.
 
Suomy Nona said:
I believe that I can do what you ask, mainly I need to know the number of electrons, protons, neutrons on earth and the moon in order to produce meaningful numbers. we know that the net electric field of earth is zero but clearly we have a gravity field; thus the positive and negative electric fields (using my method) can not be zero.

Anyway, please give me a few days.
Click to expand...
Yikes, that sounds very difficult if not impossible.

Here is an idea that I think Russ_Watters would think is a good substitution.

What would be the gravitational force between 2 masses that are both 100 moles of iron? You pick the distance between the masses.
 
origin said:
Well, we both know it really doesn't matter. :wink:
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Sure it matters, took me a few days to figure out that it was a simple problem classically. Turns out that there are 1.29E28 volt/meter's per newton/kilogram. Sure that it's one of those facts in life that you always wanted to know. If you know the g field, you can get to the E sub-fields.

Now wondering if someone can write a sub-field operator in Quantum? If someone could write an electric sub-field operator that returns only the contributions of a particle species, then quantum gravity solves itself.

download link if needed: http://www.sendspace.com/pro/zyg1qx/dl



zyg1qx
 
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Suomy Nona said:
Sure it matters, took me a few days to figure out that it was a simple problem classically. Turns out that there are 1.29E28 volt/meter's per newton/kilogram. Sure that it's one of those facts in life that you always wanted to know. If you know the g field, you can get to the E sub-fields.
Click to expand...

That is swell but you have not calculated the gravitational force between the 2 masses. I thought that was the task at hand.
 
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