Why doesn't my reflection follow the inverse square law ?

Discussion in 'The Cesspool' started by Jerimiah, Sep 27, 2021.

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  1. billvon Valued Senior Member

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    Nothing. The light reflects anyway, as several people have pointed out.

    But if you care WHAT YOU SEE, your eyes are pretty important, don't you think?
     
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  3. Jerimiah Registered Member

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    Our eyes are the pinnacle of observation , indeed they are very important .

    The Sun does not reflect light , it emits light ?

    Why does the Sun look ''orange'' in colour when the light emitted is a mixture of frequencies?
     
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  5. exchemist Valued Senior Member

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    This is all quite irrelevant. If you want to discuss these issues, they need a separate thread.
     
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  7. Jerimiah Registered Member

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    The thread topic is about the inverse square law and reflections which are light based events . Light is the topic and rather than spamming the forum with individual threads on light , isn't it more suiting to keep to one thread when the subject material is light ?
    The question is very relevant in consideration of the photon electrical effect ! The reflection in a mirror has spectral content (colour) .
    The Sun emits light rather than having incident rays strike the surface , unlike the mirrors image . How can the photon electrical effect apply to the sun , allowing us to observe visually an ''orange'' colour ?
    I personally think we have something wrong in regards to how light works !
     
  8. DaveC426913 Valued Senior Member

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    Perhaps you might finish with one question before starting another.

    In fact, someone predicted you'd go off on a new tangent before your first questions were answered. They must be psychic.
     
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  9. exchemist Valued Senior Member

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    No. The topic is the inverse square law and reflection, not any old crap you care to dream up about light.

    But this behaviour of yours is indeed what I predicted.
     
  10. Jerimiah Registered Member

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    My first question was answered but was the answer satisfactory enough to satisfy my curiousness ?

    The Inverse square law is related to lights intensity , Exchemist - ''It is brightness that decreases with the square of distance from a source.''

    The answer was part satisfactory but I must still question the mechanics of reflected mirror images . In doing so I may have to go down other ''paths'' to find a satisfactory answer . From my studies I can conclude that we only observe visual constant frequencies of light (colour) . We cannot and do not observe the random frequency of light travelling between sources . Reflections in a mirror are visual constants , the information of an objects colour changes from constant to random before becoming a constant again in the mirror while the light travels from A to B . How can a mirror even ''work'' at all ? How does the mirror reflect the source image when the incident rays are random frequencies ?
     
  11. Jerimiah Registered Member

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    I am not dreaming up anything , every thing I have mentioned are real points and asks !
     
  12. Kristoffer Giant Hyrax Valued Senior Member

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    Getting some serious Theorist vibes...
     
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  13. exchemist Valued Senior Member

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    You might think that. I couldn't possibly comment.

    Please Register or Log in to view the hidden image!

     
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  14. billvon Valued Senior Member

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    It does both. But the amount it emits is far, far, far higher than the light it reflects.
    Because of Rayleigh scattering in the atmosphere. (That's also why the sky is blue.)
    That is a completely different phenomenon.
    You can question whatever you like. All your questions have been answered. If you refuse to accept the answers, so be it. But that's on you.
     
  15. James R Just this guy, you know? Staff Member

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    Jeremiah was a sock puppet of a previously-banned user. He has been removed.
     
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