(Real Math) Looking for a fancy matrix trick

Discussion in 'Physics & Math' started by CptBork, Aug 11, 2013.

  1. CptBork Valued Senior Member

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    All the same, I'd have to collect all the terms just to calculate A, B and C- how would I do it in general?
     
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  3. Tach Banned Banned

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    See the pattern that emerges:

    \(A+B+C=0\)
    \(Aa_4+Ba_2+Ca_3=-1\)
     
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  5. CptBork Valued Senior Member

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    Ok, I'll play around a bit and see... You're suggesting I'll get a general pattern for all the coefficients A, B, C, D,... without having to work recursively? Can you show how the argument proceeds in the first example where you calculated A and B?
     
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  7. Tach Banned Banned

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    Yes, I think so.

    \(A+B=0\)
    \(Aa_3+Ba_2=-1\)



    \(A+B+C=0\)
    \(Aa_4+Ba_2+Ca_3=-1\)


    I think the next one emerges as:


    \(A+B+C+D=0\)
    \(Aa_5+Ba_4+Ca_3+Da_2=-1\)
     

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