The following equation produces a curve, as the sun passes across the sky: (100-x)/100)*x S0 then the time can be read by choosing any value and ADVANCING at the same rate across the curve to discover the same value. The third column has not been input but either side of 25 produces the same value. x/(100-x)/(25-x)/x/(100-x)/25-x 1/99/24/-74/26/74/-1/-49 2/98/23/-73/27/73/-2/-48 3/97/22/-72/28/72/-3/-47 4/96/21/-71/29/71/-4/-46 5/95/20/-70/30/70/-5/-45 6/94/19/-69/31/69/-6/-44 7/93/18/-68/32/68/-7/-43 8/92/17/-67/33/67/-8/-42 9/91/16/-66/34/66/-9/-41 10/90/15/-65/35/65/-10/-40 11/89/14/-64/36/64/-11/-39 12/88/13/-63/37/63/-12/-38 13/87/12/-62/38/62/-13/-37 14/86/11/-61/39/61/-14/-36 15/85/10/-60/40/60/-15/-35 16/84/9/-59/41/59/-16/-34 17/83/8/-58/42/58/-17/-33 18/82/7/-57/43/57/-18/-32 19/81/6/-56/44/56/-19/-31 20/80/5/-55/45/55/-20/-30 21/79/4/-54/46/54/-21/-29 22/78/3/-53/47/53/-22/-28 23/77/2/-52/48/52/-23/-27 24/76/1/-51/49/51/-24/-26 25/75/0/-50/50/50/-25/-25 The key is to advance at THE SAME RATE as time, as walking. Please Register or Log in to view the hidden image! (x)
That might work if the earth's orbit were circular, but it is not. What proceeds at a uniform rate is the area swept out by the sun to earth radial line.
That's not an equation. An equation has an equals sign in it. Perhaps you meant something like \(y=((100-x)/100)*x\) This is the same as \(y=(1 - x/100)*x =x -x^2/100\) You haven't explained which variable is time in this question (is it x?) or how the "curve" relates to the sun in the sky. Please explain.
