Impossible Equation?

Discussion in 'Physics & Math' started by Steve100, May 31, 2008.

  1. D H Some other guy Valued Senior Member

    Messages:
    2,257
    The only solution is obviously zero, but OK: \(x\log 2 = x\log 3\), or \( x(\log 3 - \log 2) = 0\). Since \(\log 2 \ne \log 3\), the only solution is \(x=0\).
    How did that fall out? BTW, this is not the problem posed in the OP.
     
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  3. paulfr Registered Senior Member

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    227
    Sorry, I made a typo.
    Meant to write ...
    2^x = 3^(x+1)

    One of the x's should be x+1 for my solution to be correct.
    This is a standard problem for my students when studying
    Log and Exponential equations.

    Again, the simple ommision of the constant of 50 in the original
    problem makes it very easy to solve in closed form.
     
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  5. mathmaster Registered Member

    Messages:
    1
    [HR][/HR][HR][/HR]
    It should be 10 cause 2+3=5�10 squared = 50 cause if u add the two x's that x squared
    At least thats how I got an answer really didn't know how he wanted it to be answered if was supposed to be a specific way
     
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  7. Mathers2013 Banned Banned

    Messages:
    190
    Surely there must be a solution to the equation...
     
  8. Fraggle Rocker Staff Member

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    24,690
    And this month's Thread Necromancy Award goes to:

    MathMaster, for reviving a discussion that died 5 1/2 years ago!

    Congratulations!
     
  9. RJBeery Natural Philosopher Valued Senior Member

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    4,222
    Seriously. And I fall for it too because I don't often check the OP's posting date. Then I saw BenTheMan respond and I was like "wait a minute......."
     
  10. Captain Kremmen All aboard, me Hearties! Valued Senior Member

    Messages:
    12,738
    Is there an equation for predicting the proportion of banned people on a 5 year old thread?
     

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