Chinese Scholar Yang Jian liang Putting Wrongs to Rights in Astrophysics

Discussion in 'Pseudoscience' started by heyuhua, Apr 22, 2018.

  1. NotEinstein Valued Senior Member

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    1,503
    It is? Test: \(G^\mu_\nu\)

    Then post them elsewhere and link them, or post them as images.

    Edit: Not so bad... Let's try this: \({G^\mu}_\nu\)
    Edit 2: Seems to work just fine for me? What problems are you having?
     
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  3. heyuhua Registered Senior Member

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    All right for you! though you cann't understand the new theory I believe the other are sure to be able get into the new results, I'm not playing with you any more! this is too taxing
     
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  5. NotEinstein Valued Senior Member

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    1,503
    Are you suggesting the forum software is conspiring against you?

    Erm, it's you that's unable to answer the most basic questions. It's you that's shown zero understanding so far.

    How many people have shown such interest in Yang's articles over the past 8 years?

    I wasn't playing, but if you are unable to answer even the most basic questions, then yeah, there's no sense in continuing, I agree.

    Answering the most basic questions is too taxing? Then why did you post this here in the first place?
     
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  7. heyuhua Registered Senior Member

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    432
    in fact, your the most basic question isn't a question at all if you can follow Yang to calculate . unfortunately, here I cann't give detailed calculation since mathematics equations are not supported, you can only go to chew hard the original articles of Yang
     
  8. heyuhua Registered Senior Member

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    432
    about the derivation of coupling constant see here:
    http://prep.nstl.gov.cn/preprint/inte.html?action=getFile&id=2c928282510e4d7301630a0a73c62114
     
  9. heyuhua Registered Senior Member

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    432
  10. NotEinstein Valued Senior Member

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    1,503
    You keep claiming that, but you keep refusing to back up that claim. It appears you also aren't able to follow Yang.

    This has already been demonstrated to be false. Please stop lying.

    No, it's you that needs to do that. You posted this here, it's up to you to defend it.

    That document contains the same problems, and doesn't go into further depth. You are repeating yourself. Why are you unable to answer this simple question?

    That document also contains the same problems, and also doesn't go into further depth. You are repeating yourself once again. Why are you so unable to answer this simple question?

    Why do you refuse to answer questions? Why do you refuse to address criticism? Why do you refuse to post calculations? I starting think this thread belongs in the fringe-section of this forum.
     
  11. heyuhua Registered Senior Member

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    432
    I don'y know what your questions are, what are you saying? what questions cann't I answer? indeed I cann't understand what these symbols
    " \(G^\mu_\nu\): \({G^\mu}_\nu\)" mean.
     
    Last edited: Apr 28, 2018
  12. NotEinstein Valued Senior Member

    Messages:
    1,503
    Just scrolling through this thread, I've found at least the following things you haven't adequately addressed yet:
    There is the refutation in post #12 that you couldn't address properly.
    There is the rejection of GR pointed at in post #21.
    There is the counter to your "but the metric counteracts it" argument in post #32.
    There is your failure to understand the type of universe Yang is using, in posts #38, #65, #67, #69.
    There is your failure to explain what the flipping of the sign in the EFE means, in post #38.
    There is your continuous failure to post any equations, and your debunked excuses as to why you are unable to do so.
    There is your continuous failure to post any evidence confirming Yang's work.
    There is your continuous failure to refer to relevant sections of Yang's work, in posts #25, #49, #51, #53, #65.
    There is the failure to explain where \(q_0\) came from in post #63.
    There is your failure to address the sign of the force of gravity in post #63.
    There is your failure to understand what the equations of motion look like in a static universe in post #67.

    Those symbols mean that you have your excuse that sub- and superscript doesn't work on this forum has been disproven.
     
  13. heyuhua Registered Senior Member

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    432
    I cann't understand you accurately, please you type in doc format, then put a place to give a link
     
    Last edited: Apr 28, 2018
  14. NotEinstein Valued Senior Member

    Messages:
    1,503
    What do you mean?
     
  15. heyuhua Registered Senior Member

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    The other questions will not be discussed for the time being , I ask you, do you understand the short discussion in the address http://prep.nstl.gov.cn/preprint/inte.html?action=getFile&id=2c928282510e4d7301630a2d22c2211a ?
     
  16. heyuhua Registered Senior Member

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    432
    if you cann't understand the short discussion it is no value to continue the other questions
     
  17. NotEinstein Valued Senior Member

    Messages:
    1,503
    That document contains the minus-sign difference in the Ricci tensor calculation, without addressing it at all, right above equation (1). So everything derived from that is suspicious. It also contains the double mistake where it is talking about a moving particle in a static universe with only a perfect fluid. So what short discussion were you talking about specifically?

    If you can't understand why there's that minus-sign difference in the Ricci tensor calculation, or why talking about a moving particle in a static universe with only a perfect fluid is nonsense, there indeed is no value to continue.
     
  18. heyuhua Registered Senior Member

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    the equation (1) is just the harmonic condition which is often used, can be see in any a textbook , don't you know? and again, in the short discussion we only deal with the static gravitational field of spherical symmetry and how a free particle moves in the static gravitational field of spherical symmetry, obviously don't come down to universal question, why must you talk about universe here?
     
  19. NotEinstein Valued Senior Member

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    1,503
    Please re-read my post; I wasn't talking about equation (1), I was talking about the (unlabeled) equation right above that.

    You really don't have a clue about how the stress-energy tensor works, do you? In all Yang's articles, there is only one contribution to the stress-energy tensor: a perfect fluid. In the derivation, this fluid is made static. In other words, the only thing existing in Yang's universe is a static perfect fluid. A moving particle thus cannot exist, because:
    1) there can be no particles, only perfect fluids;
    2) there can be no movement, because everything is static.
     
  20. heyuhua Registered Senior Member

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    432
    and for spherically symmetric gravitational source, namely celestial body, its energy-momentum tensor belongs to the one of perfect fluid, the gravitational field's metrics can be worked out from field equation, this is well known
     
  21. NotEinstein Valued Senior Member

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    1,503
    Sure, and when you make it static, there can be no moving particles. That's also well known.
     
  22. heyuhua Registered Senior Member

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    in static gravitational field there is the motion of free particle, for example, the earth moves round the sun, obviously the earth is in the static gravitational field of the sun, the matter that forms the sun is the source of the gravitational field, of course, its stress-energy tensor becomes to perfect fluid, in a word, you cann't say there isn't motion in static field
     
  23. NotEinstein Valued Senior Member

    Messages:
    1,503
    Only if you ignore the gravitational contribution of the earth, which might be a fine approximation in some situations.

    Have you even read Yang's articles yourself? We're not talking about a static gravitational field. Yang's explicitly sets the velocity of the perfect fluid to zero. In other words, we're talking about a static perfect fluid. And yes, that leads to a static gravitational field, but it also means that there can be no moving particles, because there can be no movement.
     

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