I need help with the following question... Calculate the mass (in grams) of sodium acetate required to prepare 100ml of 0.1 molar solution of sodium acetate (molecular weight 82.03). Please Register or Log in to view the hidden image! If anyone could help me with this it would be great.Thankyou.Please Register or Log in to view the hidden image!
0.1L x 0.1mol/1L x 82.03 grams/mol = probably use 90ml H20, pH the buffer and add the remaining vol by weighting to 100g (1g = 1ml for H20 or a buffer).
Sounds like a homework problem. So here's a little help anyway The molecular wt means that is the grams per mole. 0.1 molar solution means 0.1 moles per liter (1000 mls) So you know how much to add to make a 1 liter solution. So all you have to do is add just enough grams to make 100 ml sample at 0.1 (instead of a 1000 ml solution at 0.1). Get it?
Thankyou so much for your help! Please Register or Log in to view the hidden image! It's been a while since I studied A Level Chemistry and I couldn't find my notes,so I wasn't quite sure how to work out the calculations.