a story about special relativity,who can explain it?

Discussion in 'Pseudoscience' started by TonyYuan, Mar 17, 2020.

  1. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

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    852
    If the weakest gravitational wave could rise the fluctuation of the LIGO interference fringe of light, how should we neglect the gravity’s influences on light?

    If light is held by gravity, then measuring the speed of light anywhere on the earth will be a constant.

    If classical physics can explain the Morley experiment, it can explain the bending of light, and it can deduce the mass energy equation. So is it necessary to assume that the speed of light is constant ?
     
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  3. Write4U Valued Senior Member

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    20,069
    I believe it depends on the medium.
    Does the speed of light change in air or water?
    http://math.ucr.edu/home/baez/physics/Relativity/SpeedOfLight/speed_of_light.html
     
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  5. Halc Registered Senior Member

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    350
    The web sites make it look really complicated, but my intuitions generate the following:
    Rotate the picture 45 degrees. If Earth is moving at .9c diagonally, it must have component speed of .6364c, right?
    Similar, B has the same component speed in the final direction of motion.
    Add two of those using the above formula and you get .9059c.

    What's so complicated about that? Maybe I made some naive mistake. The web sites make it sound like more effort is needed. Maybe its only complicated if the two speeds being added are not identical, but even then it seems the technique I just used would be valid.

    Well, you can't ignore gravity, but there is no assumed significant gravity in your scenario.

    Anywhere period, if a local measurement. Earth to moon is not local, so light speed is a bit above c if measured as a trip to the moon and back, but if the same experiment is done on the moon with a reflector on Earth, you get a value less than c. All this is because of the gravity well depth difference.
     
    Last edited: Mar 18, 2020
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  7. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

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    My paper on special relativity has been uploaded to Google and you can download it.
    https://drive.google...gfk8XH_pE9iLTbR

    I have made a detailed analysis in several parts:
    • Impact of water on vehicle speed
    • Impact of air on light propagation
    • The influence of the gravitational field on the propagation of light
    • Eddington observed the solar eclipse to verify general relativity
    • Mass energy equation
    • Fiber optic gyroscope
    • Explanation of Sagnac effect
    • Ask questions to special relativity
     
  8. Halc Registered Senior Member

    Messages:
    350
    Ah, a denier. Your paper has many classic mistakes.

    The Sagnac section for instance has formulas that posit different light speed for the different directions, instead of noting that the light has more distance to travel with the spin than it does against it. It is this difference of distance that is measured by fiberoptic gyroscopes that utilize the effect for their measurements.

    The tail end of the page ends with a scenario that "cannot be explained by SR". Not sure why you'd assert that. Just because you're not up to it doesn't mean the theory fails there. It's actually a completely trivial scenario:

    1) Yes, B1 still reaches X in 4.36 seconds according to its own clock. This is true in any frame.
    2) All three ships are moving at .9c relative to Earth, so during 10 Earth seconds, in Earth frame, 4.36 seconds pass in any ship moving with that relative speed.
    I say 'in Earth frame' since the frame of the question is left unspecified, and the velocities are given in no one consistent frame, and hence the question is technically ambiguously worded.

    They all indeed have easy answers from classic Newtonian theory, which is 10 seconds for everybody. This is demonstrably incorrect, but Newton's theory also allows ships to move faster than light, just like airplanes can move faster than sound.
     
    Last edited: Mar 18, 2020
  9. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

    Messages:
    852
    You can challenge my third question.
     
  10. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

    Messages:
    852
    Wrong assumptions often lead to right results. For example: 1 - 9 = 7, then 1 - 9 + 9 = ?
    I believe that someone can prove that the result is 1, 1 + (9 - 9) = 1.

    It is easy to derive the mass energy equation in classical physics.
    The special theory of relativity also deduces the equation of mass and energy, which does not mean that this assumption is correct.
     
  11. Halc Registered Senior Member

    Messages:
    350
    A nit on the notation used: You write .9ls (lowercase .9 light seconds), but given the font used, it looks exactly like 0.91 s (about 10/11th of a second, a time interval instead of a distance). Use LS or Ls for light seconds, or at least put a space after the 9.
    Also, I think you didn't mean the put the decimal in that speed in the 2nd to last picture. It's 0.9 in one pic, and 9 in the other.

    Just a little constructive criticism to make a paper slightly less confusing, albeit still wrong.
     
  12. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

    Messages:
    852
    Thank you very much. It's LS,I will revise the article. 9LS is right.

    Revised article:
    https://drive.google.com/open?id=1-MH48BVnbt2T1TRSgh6KKM-1HDDMCO9G
     
    Last edited: Mar 18, 2020
  13. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

    Messages:
    852
    I have changed the editorial errors you pointed out.
    So let's talk about our key points. Where do you think it is, which statement is wrong, which makes you confused. You can refute it, and I will be happy to answer your question.
    Generally speaking, an article is wrong and irresponsible. Now that I have published the article, I can accept your questions and give you my answers.

    At the same time, I'm looking forward to your answering the third question.
     
    Last edited: Mar 18, 2020
  14. Halc Registered Senior Member

    Messages:
    350
    I pointed out several things in post 25. The beginning starts off with some kind of analogy of a car on a road with water on it. Light, to the surprise of the scientists of the late 19th century, does not behave like it travels through a medium, so not sure what all that was trying to prove. I pretty much skipped to the bottom where I found bad physics concerning fiberoptic gyroscopes and then a section at the bottom that asserted that SR cannot handle a pair of trivial questions.

    Meanwhile, what's the 3rd question? There were only two at the bottom of the page. You mean your perpendicular scenario above? I answered that in post 23.
     
  15. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

    Messages:
    852
    I see your answered that in post 23 . According to your formula: w = (u+v)/(1+uv/c^2) , the calculation is correct.

    “The beginning starts off with some kind of analogy of a car on a road with water on it.”
    This is the bedding for introducing light. If you can look down patiently, you will understand. But you don't have to look at it at all. What the article wants to explain is the influence of gravity on light, just like LIGO observed that weak gravitational waves can affect the propagation of light.

    Forget the fiber optic gyroscope. Let's continue to focus on my questions.
     
  16. DaveC426913 Valued Senior Member

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    18,935
    This is a simple hypotenuse.
    Work out the naive speeds relative to each other, (using the hypotenuse formula) then apply the relativistic velocity addition formula.
     
  17. DaveC426913 Valued Senior Member

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    18,935
    Let's focus on you getting to where you can answer your own questions, rather than using us as a library.

    Try the above calculation. Break it down into two components.
     
  18. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

    Messages:
    852
    Fourth scene:
    A------------------L=9LS---------------->Earth<------------------L=9LS-----------------------B
    v=0.9C
    ............................................................................................................v=0.9C

    With Earth as the reference, A's time goes slower, and with Earth as the reference, B's time goes slower. So when they meet, the time is same.
    but
    With A as the reference, B's time goes slower, and with B as the reference, A's time goes slower. When they meet, please tell me whose time is slower?
     
  19. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

    Messages:
    852
    Yes, it is very simple, this calculation process comes from classical physics.
     
  20. DaveC426913 Valued Senior Member

    Messages:
    18,935
    No. From straight math.
    Figure out the hypotenuse length of a right triangle with sides .9
    That will get you the classical receding velocity.
    Then apply the formula.
     
  21. TonyYuan Gravitational Fields and Gravitational Waves Registered Senior Member

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    852
    OK, are you sure you're right?
     
  22. DaveC426913 Valued Senior Member

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    18,935
    Yes.
     
  23. Janus58 Valued Senior Member

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    2,394
    0.0c.
    In the first case we are finding the velocity between A and B as measured by A or B, so the directions of the velocities must be taken as measured by which of the two we are making the measurement from.
    In the case of A we get:
    The Earth is moving to the right relative to A and B is moving to the right relative to the. If we assign motion to the right as positive then both u and v are positive.
    In your second scene The Earth, as measured from A is moving to to the Left while B is still moving to the right relative to the Earth, for A, the scene looks like.
    <--Earth---------------------------A
    0.9c
    -------------------------------------B-->
    0.9c

    u is -0.9c and v is 0.9c
    Which yields (-0.9c)+0.9c)/(1+(-(0.9c)(0.9c)/c^2) = 0c

    Third scene We will look at it from the rest frame for A where you get:
    0.9c
    <--Earth-----------------A
    |
    |
    |
    \/ B

    Since the Earth-B pair share a 0.9c to the left velocity, this pair is time dilated by a factor of 0.436 as measured by A. This includes the vertical speed of B with respect to the Earth. That means that B vertical speed component is 0.392c (which is why I drew the Earth-B line shorter than the Earth-A line.
    Now we can just do vector velocity addition to get sqrt ((0.9c)^2+ (0.392c)^2) = 0.9817c
     

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