I'm getting a little burnt out on this and I'm sure this would be easy stuff for most but frustration has taken it's toll.

I understand I get the integral of v(t) to get s(t). I then solve for s(b)-s(a) to get the displacement over the timed interval of a<t<b.

How would you solve this one?
v(t)= abs(t-3) or lt-3l 0≤t≤5


answers are displacement=6.5 and distance=6.5



What I'm also getting really stumped on is distance. How do you get the distance for

v(t)=t^2+t-2 0≤t≤2 distance=3


thanks for any help,



Fred