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Thread: calculating complex number

  1. #1
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    calculating complex number

    Calculate

    I tried with









    What should I do next?

  2. #2
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    It would be a lot easier if you started with i=e^(i.pi(2n+1/2)) (.= multiply, n is any integer)

    Then i^3/4=e^(i.pi(3n/2 + 3/8)). You will have 4 distinct results for n=0,1,2,3.

  3. #3
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    Ok, thank you..

  4. #4
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    Modulus is one so DeMoivre's Theorem should yield ...
    i^ [3/4] = cos [3 pi / 8] + i sin [3 pi / 8]

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