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05-19-08, 02:03 PM #1Registered Senior Member
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calculating complex number
Calculate
I tried with
What should I do next?
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05-19-08, 04:47 PM #2Registered Senior Member
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It would be a lot easier if you started with i=e^(i.pi(2n+1/2)) (.= multiply, n is any integer)
Then i^3/4=e^(i.pi(3n/2 + 3/8)). You will have 4 distinct results for n=0,1,2,3.
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05-20-08, 03:05 AM #3Registered Senior Member
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Ok, thank you..
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05-21-08, 08:16 AM #4Registered Senior Member
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Modulus is one so DeMoivre's Theorem should yield ...
i^ [3/4] = cos [3 pi / 8] + i sin [3 pi / 8]
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