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Thread: Actual electrostatics question

  1. #1
    is feeling caustic
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    Actual electrostatics question

    If 13 stationary source charges are placed at the vertices of a 13-sided polygon (a triskaidecagon), what is the total electric field provided by them at the geometric center of the triskaidecagon?

    I have a numeric/symbolic answer but I'd like to see someone solve it to see if our results are the same, especially since explaining my way would involve appeals to geometric ideas I can't convey in ascii.

  2. #2
    I really should be studying Pete's Avatar
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    Are the charges identical, or arbitrary?
    Is the polygon a regular polygon?

  3. #3
    Registered Senior Member
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    Quote Originally Posted by Pete View Post
    Are the charges identical, or arbitrary?
    Is the polygon a regular polygon?
    I understand the thread.

    Pete: in order, your questions answered:
    Yes
    Yes

    Pete; your solution?

  4. #4
    I really should be studying Pete's Avatar
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    Thanks CANGAS.
    It is indeed natural to assume that the answers are as you suggest, but since the question is posed by SouthStar I'd rather he clarified it.

  5. #5
    is feeling caustic
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    Cangas is right. Yes to both. I'd like also to see if anyone has the same ideas I do on generalizing to an n-gon (n>2).

  6. #6
    I really should be studying Pete's Avatar
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    By symmetry, the field at the center must be zero.

    Did you mean the total electrostatic potential?

  7. #7
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    Ah yep. You're right. I had an analytic way of doing it though and Mathematica came up with ~3^-15, which is a poor excuse for 0.

    I'm having trouble with this one though. You have a spherical shell of charge, radius a and surface density sigma from which a SMALL circular piece of radius b << a is removed. What is the direction and magnitude of the field at the center of the hole in the shell (ignoring the removed circular piece).

    I got a field of 2*pi*sigma. I'd like to see if anyone can replicate.

  8. #8
    I really should be studying Pete's Avatar
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    Too much work for me, I think.

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