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05-15-12, 12:40 PM #1Valued Senior Member
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An equation for quantum gravity
I thought of an equation for quantum gravity . This is as follows :
Consider 'm' is the mass of a body with velocity 'v' , where 'g' is quantum-gravity applied on mass 'm' ; 'd' is the distance of the mass 'm' from the c.g of other masses which is causing the gravity field 'g' .
Principle followed here is , total energy of a mass = total potential energy + total kinetic energy .
Here total energy of mass 'm' is m*c^2 [as per Einstein's Equation] .
Total potential energy is mgd .
Total kinetic energy is (1/2)mv^2 .
So, mc^2 = mgd + (1/2)mv^2
or, gd = c^2 - (1/2)v^2 .
or, g = ( c^2 - (1/2)v^2 ) / d .
or, g = ( 2c^2 - v^2 ) / 2d .
This 'g' value can represent the quantum-gravity .
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05-15-12, 02:01 PM #2
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05-15-12, 02:15 PM #3Banned
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How is this ''quantum gravity''?
From a quantum gravity perspective, I'd rather believe in some equation of the EFE's which are directly linked to some quantum effects, maybe some's stuck in there, along with some other quantum ''things''.
I don't see how this has anything to do with quantum effects, more less than a quantum gravitational theory?
Can you explain in some more detail?
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05-15-12, 02:16 PM #4Banned
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A good example of some gravity theories becoming ''quantized'' is perhaps the Hawking Radiation.
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05-15-12, 10:23 PM #5
The total energy of a mass that has kinetic energy is not
.
There's nothing quantum about anything in the opening post, which has many errors.
I have moved this thread to the cesspool where it belongs.
hansda: please don't post rubbish like this in the science forums again. Thanks.
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05-16-12, 10:23 AM #6Valued Senior Member
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For a quantum particle , in addition to mass ; it will have a charge and motion . So, the quantum particle will be subjected to quantum-gravity , electrical force and magnetic force . These electrical force and magnetic force will be having additional components in the Total Potential Energy of the quantum particle . So , quantum-gravity for a charged particle can be calculated accordingly . My earlier equation in the previous post was for a charge-less mass .
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