# Thread: srdan math

1. Presupposition-Part number (the number of gaps) negates the second number(gap number)
-one of then must be gaps numbers, other parts who have contact where is deleted together
Process:
P1- 0=¤3(1)2(1)2¤n-(.0)¤2(2)2¤=1
2
P2- 1 =¤3(1)2(1)2¤n-(.1)¤2(2)2¤=1
¤1(6)2¤
P3- ¤1(2)1¤ =¤3(1)2(1)2¤n-(.2)¤2(2)2¤=2
¤2(6)1¤
P4- 1 =¤3(1)2(1)2¤n-(.3)¤2(2)2¤=1
3
P5- 0 =¤3(1)2(1)2¤n-(.4)¤2(2)2¤=1
¤3(6)1¤
P6- 1 =¤3(1)2(1)2¤n-(.5)¤2(2)2¤=2
¤3(1)1(4)2¤
P7- 1 =¤3(1)2(1)2¤n-(.6)¤2(2)2¤=1
¤3(1)2(4)2¤
P8- 0 =¤3(1)2(1)2¤n-(.7)¤2(2)2¤=0
¤3(1)2(5)2¤
P9- 0 =¤3(1)2(1)2¤n-(.8)¤2(2)2¤=0
¤3(1)2(1)1(1)1(2)2¤
P10- 0 =¤3(1)2(1)2¤n-(.9)¤2(2)2¤=0
¤3(1)2(1)4(2)2¤
--images--
General form
negates 1 =an-(.c)b=negates 2
suptraction
or
negates 1 =an-(.c)b
negates 2
suptraction
[S47]-negates subtraction
CM-[S47] -dot no know
________

2. Presupposition-Part number (the number of gaps) negates the second number(gap number)
-one of then must be gaps numbers,contact remains , the rest is deleted
Process:
P1- 0 =¤3(1)2(1)2¤n-(.0)¤2(2)2¤=1
¤2(2)2)¤
P2- 1 =¤3(1)2(1)2¤n-(.1)¤2(2)2¤=1
¤2(2)1¤
P3- ¤1(2)1¤ =¤3(1)2(1)2¤n-(.2)¤2(2)2¤=2
¤1(4)1¤
P4- 1=¤3(1)2(1)2¤n-(.3)¤2(2)2¤=1
¤1(2)2¤
P5- 0 =¤3(1)2(1)2¤n-(.4)¤2(2)2¤=1
¤2(2)1¤
P6- 1 =¤3(1)2(1)2¤n-(.5)¤2(2)2¤=2
1
P7- 1 =¤3(1)2(1)2¤n-(.6)¤2(2)2¤=1
1
P8- 0 =¤3(1)2(1)2¤n-(.7)¤2(2)2¤=0
2
P9- 0 =¤3(1)2(1)2¤n-(.8)¤2(2)2¤=0
1
P10- 0 =¤3(1)2(1)2¤n-(.9)¤2(2)2¤=0
0
--IMAGES--
General form
negates 1 =an-(.c)b=negates 2
opposite subtraction
or
negates 1 =an-(.c)b
negates 2
opposite subtraction
[S48]-negates opposite subtraction
CM-[S48] -dot no know

3. Presupposition-In an operation number can be replaced by other numbers
Process:

P1 2+(s.0)3=5
P2 2+(s.0)4=6
P3 2+(s.0)5=7
P4 2+(s.0)6=8
P5 2+(s.0)x|316|=y
General form
a#(s.q)b=c
a#(s.q)d=e
...
a#(s.q)f=g
a#(s.q)x|bhf|=y ,#-calculation operations
[S49]-function
CM-[S49] -axiom ,real and infinite
_________________
2.write in abbreviated form (if the function can be final and natural)
2+5=7 , 2+10=12 , 2+15=17, 2+20=22 , 2+25=27 , 2+30=32 , 2+35=37 , 2+38=40,
2+40=42, 2+41=43 , 2+44=46 , 2+45=47, 2+47=49 , 2+50=52 ,2+57=59 , 2+60=62 ,
2+64=66, 2+70=72, 2+71=73 , 2+78=80 , 2+80=82 , 2+85=87 , 2+90=92 ,2+92=94

2+(s.0)x|55383(_50_)1090792|=y

4. because I do not get it, here's the work of the occurrence arranged by the sheer number of mathematical notation, mathematical journals refused to publish it, see if it's worth.

Page 3 of 3 First 123

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•