I took it to mean: error > 300,000 - freezing message 100,002 <= error <= 300,000 - freezing and cold message error = 100,001 - cold message...
Ahh yes, It should be 90°. My simple character drawing in the previous post is misleading. I made a new one to show a couple of things. This is...
Define what you mean by "energy for physics". You are right that there is a constant stuggle, but the magnet is not a participant in this struggle....
I assume the "angle of penetration" is θ<sub>max</sub>, that is with a sphere of radius R and at a point of separation r from the center of the...
Your problem has already been answered for you, you just choose to ignore it and focus on a bad answer. Whilst standing in your "motionless"...
You are right, by symmetry the point is always on the z axis and the x & y axes are irrelevant. OK so given (4) and (5): (4) f[r,θ,φ] == UG ρ...
MacM, I don't think your mathematics is what has been looked into in those threads. Mathematics applied to the ideas you have proposed, yes - but it...
DaleSpam, I was attempting to verify the excellent work you have done but I unfortunately ran into a bit of a snag. Can you explain your equation:...
For those of us without Mathematica: equation 2 is simply: (2) [X, Y, Z] = [0, 0, r] + t*[cosφ sinθ, sinφ sinθ, cosθ] (2) into (1): (t...
OK - I agree with everything thus far. Up to this point, we have done everything exactly the same. OK - here I don't think I agree. Yes it is true...
Actually, we did a simplified version. Remember we assumed constant density throughout.
Well it looks like all of your forces point towards the centroid. Mine do not, which is why I have a suspicion there is some error, maybe just a...
Yes the path curves. As a side note, that circle is just where I suspect the centroid is. Unfortunately the centroid equation is going to be...
Here is an image that maps out the force gradient for a path from the surface to centroid: [IMG] These forces were computed with a full...
I figured it was understood by everyone that the cross-sections, all the cross-sections were parallel to the z plane. Therefore if you define a line,...
I don't really have any idea what you are alluding to here. You speak of expansion when the volume of the eggoid is equal to that of the sphere (I...
It's just another way of saying they will not cancel out (i.e. they add upon each other) or: Same thing. I suppose compound can have the wrong...
Thanks. I didn't think it was an error, per say - just that it was in there somewhere. As it turns out the it was in the A equation. Luckily we...
Those are the lines from which φ is measured. They really aren't important. I don't think it is this simple. It is true that the net force will...
Billy T, assuming this first image is a sphere and it is to virtually deform into the second image that is an eggoid, and assuming the points in each...
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