There was a young fencer named Fisk, Whose thrust was exceedingly brisk. So fast was his action, The Lorentz-FrizGerald contradiction Reduced his rapier to a disk - Anonymous I got it off an awesome physics textbook :D

Okay I realized an error I made, instead of P being zero, P doesn't have to be taken into account, thus removing /p.

I don't think so. Because the value for P can be zero. We can get a good estimate of the composition and the pressure of the atmosphere.

Ah, I see. That equation would only work for explosions in atmosphere, though, and you would need to know the atmospheric pressure within the shockwave.

Using the picture of the Trinity test shown here (which had been publicly released by the U.S. government and published in "Life" magazine), Taylor estimated that at "t" = 0.025 s the blast radius was 140 metres. Taking "ρ" to be 1 kg/m³ and solving for "E", he obtained that the yield was about 22 kilotons of TNT (90 TJ). This very simple argument agrees within 10% with the official value of the bomb's yield, convert|20|ktonTNT, which at the time that Taylor published his result was considered highly-classified information. (See G. I. Taylor, "Proc. Roy. Soc. London" A201, pp. 159, 175 (1950).)

YES! I found it, something about the equation I gave you. A good approximation of the yield of the Trinity test device was obtained from simple dimensional analysis by the British physicist G. I. Taylor. Taylor noted that the radius "R" of the blast should initially depend only on the energy "E" of the explosion, the time "t" after the detonation, and the density ρ of the air. The only number having dimensions of length that can be constructed from these quantities is: R=left({fracE{t^{2{ ho ight)^{frac {1} {5

If R = (Et ( squared )/p) ( to the power of 1/5 ) work, then ricery is going to be smashed so badly........ ( even worse if C is included, I forgot if it does or not, I am pretty sure it doesn't :D )

Oh, I missed what do they represent, sorry. R = radius, E = energy, t = time, p = density ( I think ).

I remember it from a textbook ( I think ) that I bought......I think it is for calculating weapons yields of nuclear weapons....I am not 100% sure. I read it quite some time ago. The yields I am trying to calculate are for (eg. turbolasers, laser cannons .etc )

I have a question: Does R=left({fracE{t^{2{ ho ight)^{frac {1} {5 R = (Et ( squared )/p) ( to the power of 1/5 ) work for calculating yields for Scifi? ( or is it R = C (Et ( squared )/p) ( to the power of 1/5 ) ) If not can you tell me the one to use?

No, I'm not. Get off my damn lawn before I come out there and give you a solid whipping with my cane!

In three years, maybe. Now shut up, I need to get back to work. I can't hear myself think over all you young whipper-snappers prattling on. And get off my damn lawn!!!