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Jun 10, 2010
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Dragon Overlord

Registered Senior Member
Ilithi_Dragon was last seen:
Jul 31, 2013
    1. razordude
      omega can't be on for awhile. (internet down.)
    2. Shogun
      There was a young fencer named Fisk,
      Whose thrust was exceedingly brisk.
      So fast was his action,
      The Lorentz-FrizGerald contradiction
      Reduced his rapier to a disk

      - Anonymous

      I got it off an awesome physics textbook :D
    3. Shogun
      Also can you do a news report about the "pirate attack" on the stolen Dark Tiger?
    4. Shogun
      Can you make like people speculating that the Vichi Empire is sending aid and supplies to ESSCPA?
    5. Shogun
      Okay I realized an error I made, instead of P being zero, P doesn't have to be taken into account, thus removing /p.
    6. Shogun
      I don't think so. Because the value for P can be zero.

      We can get a good estimate of the composition and the pressure of the atmosphere.
    7. Ilithi_Dragon
      Ah, I see. That equation would only work for explosions in atmosphere, though, and you would need to know the atmospheric pressure within the shockwave.
    8. Shogun
      Using the picture of the Trinity test shown here (which had been publicly released by the U.S. government and published in "Life" magazine), Taylor estimated that at "t" = 0.025 s the blast radius was 140 metres. Taking "ρ" to be 1 kg/m³ and solving for "E", he obtained that the yield was about 22 kilotons of TNT (90 TJ). This very simple argument agrees within 10% with the official value of the bomb's yield, convert|20|ktonTNT, which at the time that Taylor published his result was considered highly-classified information. (See G. I. Taylor, "Proc. Roy. Soc. London" A201, pp. 159, 175 (1950).)
    9. Shogun
      YES! I found it, something about the equation I gave you.

      A good approximation of the yield of the Trinity test device was obtained from simple dimensional analysis by the British physicist G. I. Taylor. Taylor noted that the radius "R" of the blast should initially depend only on the energy "E" of the explosion, the time "t" after the detonation, and the density ρ of the air. The only number having dimensions of length that can be constructed from these quantities is: R=left({fracE{t^{2{ ho ight)^{frac {1} {5
    10. razordude
      what's up?
    11. razordude
    12. Shogun
      IIRC the radius is the blast radius.
    13. Shogun
      If R = (Et ( squared )/p) ( to the power of 1/5 ) work, then ricery is going to be smashed so badly........ ( even worse if C is included, I forgot if it does or not, I am pretty sure it doesn't :D )
    14. Shogun
      Oh, I missed what do they represent, sorry.

      R = radius, E = energy, t = time, p = density ( I think ).
    15. Shogun
      I remember it from a textbook ( I think ) that I bought......I think it is for calculating weapons yields of nuclear weapons....I am not 100% sure. I read it quite some time ago. The yields I am trying to calculate are for (eg. turbolasers, laser cannons .etc )
    16. Shogun
      I have a question:


      R=left({fracE{t^{2{ ho ight)^{frac {1} {5

      R = (Et ( squared )/p) ( to the power of 1/5 )

      work for calculating yields for Scifi?

      ( or is it R = C (Et ( squared )/p) ( to the power of 1/5 ) )

      If not can you tell me the one to use?
    17. razordude
      ohhh. that's who's lawn this is well anyways don't go near the oak I just crappd there. :D
    18. Ilithi_Dragon
      No, I'm not. Get off my damn lawn before I come out there and give you a solid whipping with my cane!
    19. razordude
      Lol........wait you were kidding right?
    20. Ilithi_Dragon
      In three years, maybe.

      Now shut up, I need to get back to work. I can't hear myself think over all you young whipper-snappers prattling on.

      And get off my damn lawn!!!
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