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    omega can't be on for awhile. (internet down.)
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    There was a young fencer named Fisk,
    Whose thrust was exceedingly brisk.
    So fast was his action,
    The Lorentz-FrizGerald contradiction
    Reduced his rapier to a disk

    - Anonymous

    I got it off an awesome physics textbook :D
  3. View Conversation
    Also can you do a news report about the "pirate attack" on the stolen Dark Tiger?
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    Can you make like people speculating that the Vichi Empire is sending aid and supplies to ESSCPA?
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    Okay I realized an error I made, instead of P being zero, P doesn't have to be taken into account, thus removing /p.
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    I don't think so. Because the value for P can be zero.

    We can get a good estimate of the composition and the pressure of the atmosphere.
  7. Ah, I see. That equation would only work for explosions in atmosphere, though, and you would need to know the atmospheric pressure within the shockwave.
  8. View Conversation
    Using the picture of the Trinity test shown here (which had been publicly released by the U.S. government and published in "Life" magazine), Taylor estimated that at "t" = 0.025 s the blast radius was 140 metres. Taking "ρ" to be 1 kg/m³ and solving for "E", he obtained that the yield was about 22 kilotons of TNT (90 TJ). This very simple argument agrees within 10% with the official value of the bomb's yield, convert|20|ktonTNT, which at the time that Taylor published his result was considered highly-classified information. (See G. I. Taylor, "Proc. Roy. Soc. London" A201, pp. 159, 175 (1950).)
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    YES! I found it, something about the equation I gave you.

    A good approximation of the yield of the Trinity test device was obtained from simple dimensional analysis by the British physicist G. I. Taylor. Taylor noted that the radius "R" of the blast should initially depend only on the energy "E" of the explosion, the time "t" after the detonation, and the density ρ of the air. The only number having dimensions of length that can be constructed from these quantities is: R=left({fracE{t^{2{ ho ight)^{frac {1} {5
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    what's up?
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