how it works?

Discussion in 'Physics & Math' started by Ethernos D Grace, Sep 8, 2017.

  1. Ethernos D Grace Registered Senior Member

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    integral a to 0 accelartion x volume
    x time dx
     
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  3. origin Heading towards oblivion Valued Senior Member

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    Acceleration x volume x time? That leaves you with \(\frac{m^4}{s}\), what is that suppose to be?

    Are you just trolling here or is there something you want to discuss?
     
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  5. Ethernos D Grace Registered Senior Member

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    i also would like to know what it is.
     
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  7. origin Heading towards oblivion Valued Senior Member

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    11,888
    What is 'it'?
     
  8. Ethernos D Grace Registered Senior Member

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  9. origin Heading towards oblivion Valued Senior Member

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    \(m^4\) is nonsense in a physical sense. Mathematically you can take 1 m and raise it to the 4th power and it would give \(1 m^4\)
     
  10. Ethernos D Grace Registered Senior Member

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    in non physical sense does it make sense?
     
  11. origin Heading towards oblivion Valued Senior Member

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    11,888
    I have no idea how to respond to that.
    Try this, write out 3 - 5 complete sentences that describe what it is you are trying to discover.
     
  12. exchemist Valued Senior Member

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    Thread reported with request for it to go to the cesspool.

    Nothing Ethernos has posted makes any sense whatsoever.
     
  13. Kittamaru Ashes to ashes, dust to dust. Adieu, Sciforums. Valued Senior Member

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    Lets give this one last chance:

    Ethernos - what, exactly, are you trying to do? Is this a math problem from your homework?
     
  14. exchemist Valued Senior Member

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    Good to see you are on the case. Thanks.
     
  15. Ethernos D Grace Registered Senior Member

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    no! sorry. what i actually tried to ask was "could volume be reduced or increased due to acceleration and time?"
     
  16. Kittamaru Ashes to ashes, dust to dust. Adieu, Sciforums. Valued Senior Member

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    The only way I can think of off the top of my head for acceleration/deceleration to affect volume would be through resistance causing an increase in temperature in a substance resulting in a state change from liquid to gas (which would result in an increase in volume for a given mass).

    Beyond that, I don't believe it does - someone with a deeper physics background could probably explain better.

    As for time - again, I don't believe the passing of time itself affects volume. It could indirectly, via decomposition and the like.
     
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  17. Ethernos D Grace Registered Senior Member

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    thank you...
     
  18. hansda Valued Senior Member

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    If this object is accelerated to a relativistic speed, its volume will decrease as per Lorentz length reduction.
     
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  19. origin Heading towards oblivion Valued Senior Member

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    That depends on which frame you are in.
     
  20. hansda Valued Senior Member

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    See the Lorentz equation for length reduction.
     
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  21. Kittamaru Ashes to ashes, dust to dust. Adieu, Sciforums. Valued Senior Member

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    I was under the impression that Lorentz Length Reduction was only based on the stationary outside observer, not the "actual" length? Eg, a co-moving object within the vessels rest frame will not notice a reduction in length, and thus would not note a reduction in volume. As a result, the "actual" volume of the vessel would not decrease (ergo, if you have a vessel of one cubic meter full of water, and accelerate it to 90% the speed of light, water would not "spill out" due to Lorentz Reduction).
     
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  22. origin Heading towards oblivion Valued Senior Member

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    Already have, hence my comment that it depends on your frame.
    The observers own frame will not be length contracted.
     
  23. hansda Valued Senior Member

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    Kittamaru,

    See this link https://en.wikipedia.org/wiki/Length_contraction . When the electron travels at 0.0447c, its contracted length is 99.9% of the length at rest. At 0.141c the contracted length is 99%. So, you can see as the relativistic speed of electron increases its length reduces. This length reduction will cause a volume reduction.
     

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