If you are not presently under the care of a physician I recommend that you contact your health care provider and have a talk with him about some of your ideas. Good luck.
Regardless of the value of x (so long as it is finite) the formula x-(x-25) ALWAYS reduces to 25. Is there a point to this exercise? If you cannot elaborate, at least a little, and make this thread into an actual discussion, I will move it to the Cesspool. Fraggle Rocker Moderator Linguistics
That's nothing! Prepare to have your mind blown... y = 2(x-(x-27))/2 For any x, y is always 27!!! I know! Unreal!
\( \lim_{x\to 1} x = 1\) \( \lim_{x\to 1} ( \frac{1}{x-1} - ( \frac{1}{x-1} - 4! ) ) = 24\) \( \lim_{x\to 1} ( \frac{x}{x-1} - ( \frac{1}{x-1} - 4! ) ) = 25\)
My father used to be impressed that you could add two numbers together, then subtract one number from the sum and get the other number back. I'm not equally surprised but I do find it comforting that in mathematics you can often unbake the cake.