Urgent Two-folds serial Dillution help!!

Discussion in 'Chemistry' started by ciznet, Nov 27, 2013.

  1. ciznet Registered Member

    Messages:
    2
    Please i need help concerning how to prepare two-fold serial dilutions of my Antimicrobial agents for Minimum inhibitory concentration (MIC) as follows:

    I have 500mg/ml (0.5g in 10ml) stock solution and i want to prepare serial dilutions with the following concentrations from it : 250mg/ml, 125mg/ml, 62.5mg/ml and 31.25mg/ml

    Thanks for your help!
     
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  3. kumar11 Registered Member

    Messages:
    7
    This would be pretty straight forward, and is done quite frequently in the laboratory. The answer would depend on how much of each dilution you require. Assuming that a minimum of 5 mL of each dilution 250 mg/mL to 31.25 mg/mL is desired, you would prepare them as follows:
    (250 mg/mL) -Mix 5 mL of the 500 mg/mL stock solution with 5 mL of water and mix thoroughly.
    (125 mg/mL) -Mix 5 mL of the 250 mg/mL stock solution with 5 mL of water and mix thoroughly.
    (62.5 mg/mL) -Mix 5 mL of the 125 mg/mL stock solution with 5 mL of water and mix thoroughly.
    (31.25 mg/mL) -Mix 5 mL of the 62.5 mg/mL stock solution with 5 mL of water and mix thoroughly.

    This procedure would leave you with 5 mL of the 500 mg/mL stock through 62.5 mg/mL dilution, and 10 mL of the 31.25 mg/mL.
     
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