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View Full Version : My interpretation of cosmological red-shift.


Acitnoids
06-12-09, 03:20 PM
Please correct me if I'm wrong. From what I can tell the cosmological red-shift (Z) is a product of the ratio between the current age of the universe (size, temp, energy density ...), as observed from our perspective and the age of the universe (size, temp, energy density ...) from which the observed photons were emitted. Seeing as I can only post from a mobile, my equations will have to be written out.

First you must measure Z, add 2, divide by 2, square it, divide into 1 (1/x), subtract by 1 (1-x) then multiply by the current age (size) of the universe. This will equal the distance to the observed object. Instead of multiplying by the current age you can exchange it for the speed of light (c). This will tell you the recession velocity of space (H) at the observed distance.

This means you can divide the current age by a past age, square root it, multiply by 2 then subtract 2 (x-2) to find Z.

H is equal to the current age (size) divided by the distance, divided into c (c/x).

Acitnoids
06-18-09, 09:30 PM
These equations show that space is expanding faster the further you look without the need to invoke dark energy. Whould you say this statement is correct?