Sorry it has been awhile for me. 1. Do you guys know how to integrate y(x) = 2x / (x^2 + 3) ??? 2. The integral of e^(x^2) is 1/(2x)*e^(x^2) correct? Thanks
i would probably know how to do that, had i not dropped my current calculus class. so the best i can do is say check for yourself!!!!!! http://integrals.wolfram.com/ the integrator .. works nice
<i>1. Do you guys know how to integrate y(x) = 2x / (x^2 + 3) ???</i> Yes. Put u = x^2 + 3 Then du/dx = 2x Integral (2x / (x^2 +3)) dx = Integral ((du/dx) / u) dx = Integral (1/u) du = ln u + c = ln (x^2 + 3) + c <i>2. The integral of e^(x^2) is 1/(2x)*e^(x^2) correct?</i> No. You can see that's wrong by differentiating your answer.
mathematica says the answer is Log(3+x^2) Log in mathematica is ln i believe, from the version i used at school
On Radioactive Waves, Indeed it is, mostly log = ln, and log10 equals just what it says (the inverse function of powers of ten). Some books/courses prefer the distinct notation log for log10 and ln for the inverse of the exponential. The lesson is: always check the convention used in a text before reading the formula's. Something which goes far beyond ln/log confusion Please Register or Log in to view the hidden image! Bye! Crisp
I advise you to buy Micheal Kelley's Mastering the AP Calculus AB + BC by ARCO It's the best calculus prep book out there. It'll help you to understand everything - limits, integrals, differentiation, to slope/field solutions graphs.
man i used to be good at this now im just lazy Please Register or Log in to view the hidden image! Q2. im pretty sure thats wrong. I always just used to work backwards if i wasnt sure. Good Luck
Hm. I thought the denominator would be an arctan when you integrated it...I dunno. I took calculus and I ended up with an A but I'm a slacker. I'll try to work it out. If the arctan is wrong you might try substitution.
