a=b
a*a = a*b
a^2 = ab
a^2 - b^2 = ab - b^2
[(a-b)(a+b)] = b(a-b)
[(a-b)(a+b)] = b(a-b)
..... (a-b)......... (a-b)
a+b = b
b+b = b
2b = b
?
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everneo
05-23-03, 01:52 AM
...
..
2b = b
b+b = b
b = b - b
b = 0
a = b
a = b = 0 = -0 = 0*0 = n*0 etc...:bugeye:
nope, sorry, not the answer i was looking for.
suppose a and b did not = 0
everneo
05-23-03, 02:16 AM
Originally posted by Mors
nope, sorry, not the answer i was looking for.
suppose a and b did not = 0
how ?
also
a-b = 0 ; dividing by this in a derivation is surprising.
yay good job
your prize is blue pens and tea
arival date: 2841
everneo
05-23-03, 03:00 AM
no thanks. this was already discussed earlier. MacM started that..:D
Good job everneo! I didn't thought about it... :)