My dad had 5 kids Me-got married, had a son. divorced. Got pregnant out of wedlock, had a daughter Brother-got pregnant out of wedlock, had a daughter, married had son. divorced. Got pregnant out of welock, had another daughter Brother-got pregnant out of wedlock, had a daughter, married had 5 sons Sister-got pregnant out of wedlock, had daughter Sister-got pregnant out of wedlock, had daughter Every daughter (6 of them) was from an out of wedlock pregnancy while every son (7 of them) wasn't. What are the odds?
Were you and your sister born out of wedlock ? Oh and by the way CONDOMS ! LOL. Not saying the daughters aren't great. Just saying.
I think either one of those would qualify for the Guinness Book of Records. Please Register or Log in to view the hidden image! Mmm, Guinness. /drool.
It depends entirely on how you go about computing things. For instance, if you say "13 children are born, 6 girls, 7 boys. 6 children are to be born in wedlock, 7 outside of wedlock. What's the probability of those 7 being all boys?" then your answer will be different from "13 children are born. 6 children are to be born in wedlock, 7 outside of wedlock. What's the probability of those 7 being all boys?", which is also different from "13 children are born to various couples whose martial status is constantly changing. What's the probability those born in wedlock are all of the same gender? What's the probability those out of wedlock are also all of the same (but different) gender?". In that last case it obviously various as you vary the number of births too. Assuming the people in question were always going to have their divorces and marriages (ie having or not having kids made no difference) and those 13 kids were inevitable, then you're asking what the probability of the 7 kids in wedlock were all of the same gender and the other 6 of the other gender. Probability of 7 particular births being male is \(2^{7}\) and the other 6 being female \(2^{6}\). Though if the genders were swapped you'd still be wondering the same thing so you have twice the chance so you get a 1 in \(2^{12} = 4096\) chance.
Here's something else to think about: Out of thirteen successful pregnancies, what are the odds that you'll find some feature common to all the pregnancies with female babies, butnone of the pregnancies with male babies? In this case, the feature is "conceived out of wedlock"... but how many other features of conception, pregnancy, and birth can you think of?
ummm, none. I didn't even notice it til her sisters made a big deal about my Mom being the only one who had granddaughters. She told them the way to get them is to not teach your kids about birth control. Please Register or Log in to view the hidden image!
I don't mean features that actually match up in this case... I mean features that you (or someone else in the family) might have noticed if they did match up.
