Today, I have a head y'could bounce bricks off. Could do with a hand. Any takers, gladly appreciated.

I'm trying to noodle the speed of the Earths surface rotation occurring at a latitude of around 50° North of the equator.

If I'm taking the equatorial speed at around 1038mph, at 45° I keep coming up with a speed of around 0.7 of the equatorial, but if I try noodling it out at latitudinal increments of 10° North from the equator to the pole, I come up with bollocks....

I just basically want to have a ball park figure of how much the rotational speed of the Earths surface diminishes the further North y'go for every 10° North y'travel.

Appreciation in advance by the bucket, Ta. A. ;)

S' = S*sin(90-lat)

At 50 degN, S' = 1038 * sin(40) = 667.2 mph

I just basically want to have a ball park figure of how much the rotational speed of the Earths surface diminishes the further North y'go for every 10° North y'travel.

Appreciation in advance by the bucket, Ta. A. ;) [/FONT] [/SIZE]
takeing the formula of superluminal
the speed diminishes at the rate of the sin of the angle or latitude

but thinking about it i believe it is the COSINE of the angle
thats assuming 0 degrees is the equater

edit
after stuying superluminals post i see that is essentially what he is saying

:) ... Well, I'm gratified to find learn I managed to at least get the .2 bit of that absolutely bang on the nail.

Bless you boyos, knew there was a reason I liked coming here. Super, thank you for the math and the crunchings - Leo, putting that in english helps, I'm of the obliged to y'both. Take care, regards,

A ;)

Anytime, my friend.

Same your way old man, count on it.