Urgent! Ahhh! Vbnet!

Ok, im doing homework for my class, and its due tomorrow (Its long, havent been procrastinating... much =D)

I am trying to convert the DOUBLE 9.23 , and get JUST THE .23

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Here is the problem:
Write an algorithm that starts with a quantity in MPH and converts the quantity into minutes and seconds per mile instead of MPH

Proper answer ffor input of 6.5 MPH=
9 Mins, 13.8 Seconds

I use formula =

MPH = 6.5
so, Math.Round((60 / MPH), 0)
That gives me 9 minutes

THen, to get the seconds its =
60 / MPH

I get 9.23........etc
I want to take JUST THE .23, multiply it by 60

How do i get the program to realize the numbers ONLY after 9, and then to assign a value to it (easy to assign a value, just what do i use to get the .23?)

CODE SO FAR:
Private Sub btnCompute_Click(...<- Dont need this) Handles btnCompute.Click
Dim Minutes, Seconds, MPH As Double
Minutes = Math.Round((60 / MPH), 0)

End Sub

 

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Found its easier to do this:

Private Sub btnCompute_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnCompute.Click
Dim MPH, Seconds, Step1, Step2 As Double
Dim Minutes As Integer
MPH = txtMPH.Text
Minutes = 60 / MPH


End Sub

STILL NO SOLUTION!!!

 

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Private Sub btnCompute_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnCompute.Click
Dim MPH, Seconds, Step1, Step2 As Double
Dim Minutes As Integer
MPH = txtMPH.Text
Minutes = 60 / MPH
Step1 = (60 / MPH) - Minutes
Step2 = Step1 * 60
Seconds = Math.Round(Step2, 3)
Console.WriteLine("Your speed is... " & Minutes & " Minutes, " & Seconds & " Seconds! ")
End Sub


Easy as cake.... Im stupid sometimes =D

 

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actually.... Minutes = Math.Floor(60 / MPH)

But whatever, i just made my entire own thread